Metamath Proof Explorer


Theorem com25

Description: Commutation of antecedents. Swap 2nd and 5th. Deduction associated with com14 . (Contributed by Jeff Hankins, 28-Jun-2009)

Ref Expression
Hypothesis com5.1 φ ψ χ θ τ η
Assertion com25 φ τ χ θ ψ η

Proof

Step Hyp Ref Expression
1 com5.1 φ ψ χ θ τ η
2 1 com24 φ θ χ ψ τ η
3 2 com45 φ θ χ τ ψ η
4 3 com24 φ τ χ θ ψ η