Metamath Proof Explorer


Theorem compsscnv

Description: Complementation on a power set lattice is an involution. (Contributed by Mario Carneiro, 17-May-2015)

Ref Expression
Hypothesis compss.a ⊢ F = x ∈ 𝒫 A ⟼ A ∖ x
Assertion compsscnv ⊢ F -1 = F

Proof

Step Hyp Ref Expression
1 compss.a ⊢ F = x ∈ 𝒫 A ⟼ A ∖ x
2 cnvopab ⊢ y x | y ∈ 𝒫 A ∧ x = A ∖ y -1 = x y | y ∈ 𝒫 A ∧ x = A ∖ y
3 difeq2 ⊢ x = y → A ∖ x = A ∖ y
4 3 cbvmptv ⊢ x ∈ 𝒫 A ⟼ A ∖ x = y ∈ 𝒫 A ⟼ A ∖ y
5 df-mpt ⊢ y ∈ 𝒫 A ⟼ A ∖ y = y x | y ∈ 𝒫 A ∧ x = A ∖ y
6 1 4 5 3eqtri ⊢ F = y x | y ∈ 𝒫 A ∧ x = A ∖ y
7 6 cnveqi ⊢ F -1 = y x | y ∈ 𝒫 A ∧ x = A ∖ y -1
8 df-mpt ⊢ x ∈ 𝒫 A ⟼ A ∖ x = x y | x ∈ 𝒫 A ∧ y = A ∖ x
9 compsscnvlem ⊢ y ∈ 𝒫 A ∧ x = A ∖ y → x ∈ 𝒫 A ∧ y = A ∖ x
10 compsscnvlem ⊢ x ∈ 𝒫 A ∧ y = A ∖ x → y ∈ 𝒫 A ∧ x = A ∖ y
11 9 10 impbii ⊢ y ∈ 𝒫 A ∧ x = A ∖ y ↔ x ∈ 𝒫 A ∧ y = A ∖ x
12 11 opabbii ⊢ x y | y ∈ 𝒫 A ∧ x = A ∖ y = x y | x ∈ 𝒫 A ∧ y = A ∖ x
13 8 1 12 3eqtr4i ⊢ F = x y | y ∈ 𝒫 A ∧ x = A ∖ y
14 2 7 13 3eqtr4i ⊢ F -1 = F