Metamath Proof Explorer


Theorem constrsscn

Description: Closure of the constructible points in the complex numbers. (Contributed by Thierry Arnoux, 25-Jun-2025)

Ref Expression
Hypotheses constr0.1 ⊢ C = rec ⁡ s ∈ V ⟼ x ∈ ℂ | ∃ a ∈ s ∃ b ∈ s ∃ c ∈ s ∃ d ∈ s ∃ t ∈ ℝ ∃ r ∈ ℝ x = a + t ⁢ b − a ∧ x = c + r ⁢ d − c ∧ ℑ ⁡ b − a ‾ ⁢ d − c ≠ 0 ∨ ∃ a ∈ s ∃ b ∈ s ∃ c ∈ s ∃ e ∈ s ∃ f ∈ s ∃ t ∈ ℝ x = a + t ⁢ b − a ∧ x − c = e − f ∨ ∃ a ∈ s ∃ b ∈ s ∃ c ∈ s ∃ d ∈ s ∃ e ∈ s ∃ f ∈ s a ≠ d ∧ x − a = b − c ∧ x − d = e − f 0 1
constrsscn.1 ⊢ φ → N ∈ On
Assertion constrsscn ⊢ φ → C ⁡ N ⊆ ℂ

Proof

Step Hyp Ref Expression
1 constr0.1 ⊢ C = rec ⁡ s ∈ V ⟼ x ∈ ℂ | ∃ a ∈ s ∃ b ∈ s ∃ c ∈ s ∃ d ∈ s ∃ t ∈ ℝ ∃ r ∈ ℝ x = a + t ⁢ b − a ∧ x = c + r ⁢ d − c ∧ ℑ ⁡ b − a ‾ ⁢ d − c ≠ 0 ∨ ∃ a ∈ s ∃ b ∈ s ∃ c ∈ s ∃ e ∈ s ∃ f ∈ s ∃ t ∈ ℝ x = a + t ⁢ b − a ∧ x − c = e − f ∨ ∃ a ∈ s ∃ b ∈ s ∃ c ∈ s ∃ d ∈ s ∃ e ∈ s ∃ f ∈ s a ≠ d ∧ x − a = b − c ∧ x − d = e − f 0 1
2 constrsscn.1 ⊢ φ → N ∈ On
3 fveq2 ⊢ m = ∅ → C ⁡ m = C ⁡ ∅
4 3 sseq1d ⊢ m = ∅ → C ⁡ m ⊆ ℂ ↔ C ⁡ ∅ ⊆ ℂ
5 fveq2 ⊢ m = n → C ⁡ m = C ⁡ n
6 5 sseq1d ⊢ m = n → C ⁡ m ⊆ ℂ ↔ C ⁡ n ⊆ ℂ
7 fveq2 ⊢ m = suc ⁡ n → C ⁡ m = C ⁡ suc ⁡ n
8 7 sseq1d ⊢ m = suc ⁡ n → C ⁡ m ⊆ ℂ ↔ C ⁡ suc ⁡ n ⊆ ℂ
9 fveq2 ⊢ m = N → C ⁡ m = C ⁡ N
10 9 sseq1d ⊢ m = N → C ⁡ m ⊆ ℂ ↔ C ⁡ N ⊆ ℂ
11 1 constr0 ⊢ C ⁡ ∅ = 0 1
12 0cn ⊢ 0 ∈ ℂ
13 ax-1cn ⊢ 1 ∈ ℂ
14 prssi ⊢ 0 ∈ ℂ ∧ 1 ∈ ℂ → 0 1 ⊆ ℂ
15 12 13 14 mp2an ⊢ 0 1 ⊆ ℂ
16 11 15 eqsstri ⊢ C ⁡ ∅ ⊆ ℂ
17 simpl ⊢ n ∈ On ∧ C ⁡ n ⊆ ℂ → n ∈ On
18 eqid ⊢ C ⁡ n = C ⁡ n
19 1 17 18 constrsuc ⊢ n ∈ On ∧ C ⁡ n ⊆ ℂ → x ∈ C ⁡ suc ⁡ n ↔ x ∈ ℂ ∧ ∃ a ∈ C ⁡ n ∃ b ∈ C ⁡ n ∃ c ∈ C ⁡ n ∃ d ∈ C ⁡ n ∃ t ∈ ℝ ∃ r ∈ ℝ x = a + t ⁢ b − a ∧ x = c + r ⁢ d − c ∧ ℑ ⁡ b − a ‾ ⁢ d − c ≠ 0 ∨ ∃ a ∈ C ⁡ n ∃ b ∈ C ⁡ n ∃ c ∈ C ⁡ n ∃ e ∈ C ⁡ n ∃ f ∈ C ⁡ n ∃ t ∈ ℝ x = a + t ⁢ b − a ∧ x − c = e − f ∨ ∃ a ∈ C ⁡ n ∃ b ∈ C ⁡ n ∃ c ∈ C ⁡ n ∃ d ∈ C ⁡ n ∃ e ∈ C ⁡ n ∃ f ∈ C ⁡ n a ≠ d ∧ x − a = b − c ∧ x − d = e − f
20 19 biimpa ⊢ n ∈ On ∧ C ⁡ n ⊆ ℂ ∧ x ∈ C ⁡ suc ⁡ n → x ∈ ℂ ∧ ∃ a ∈ C ⁡ n ∃ b ∈ C ⁡ n ∃ c ∈ C ⁡ n ∃ d ∈ C ⁡ n ∃ t ∈ ℝ ∃ r ∈ ℝ x = a + t ⁢ b − a ∧ x = c + r ⁢ d − c ∧ ℑ ⁡ b − a ‾ ⁢ d − c ≠ 0 ∨ ∃ a ∈ C ⁡ n ∃ b ∈ C ⁡ n ∃ c ∈ C ⁡ n ∃ e ∈ C ⁡ n ∃ f ∈ C ⁡ n ∃ t ∈ ℝ x = a + t ⁢ b − a ∧ x − c = e − f ∨ ∃ a ∈ C ⁡ n ∃ b ∈ C ⁡ n ∃ c ∈ C ⁡ n ∃ d ∈ C ⁡ n ∃ e ∈ C ⁡ n ∃ f ∈ C ⁡ n a ≠ d ∧ x − a = b − c ∧ x − d = e − f
21 20 simpld ⊢ n ∈ On ∧ C ⁡ n ⊆ ℂ ∧ x ∈ C ⁡ suc ⁡ n → x ∈ ℂ
22 21 ex ⊢ n ∈ On ∧ C ⁡ n ⊆ ℂ → x ∈ C ⁡ suc ⁡ n → x ∈ ℂ
23 22 ssrdv ⊢ n ∈ On ∧ C ⁡ n ⊆ ℂ → C ⁡ suc ⁡ n ⊆ ℂ
24 23 ex ⊢ n ∈ On → C ⁡ n ⊆ ℂ → C ⁡ suc ⁡ n ⊆ ℂ
25 vex ⊢ m ∈ V
26 25 a1i ⊢ Lim ⁡ m ∧ ∀ n ∈ m C ⁡ n ⊆ ℂ → m ∈ V
27 simpl ⊢ Lim ⁡ m ∧ ∀ n ∈ m C ⁡ n ⊆ ℂ → Lim ⁡ m
28 1 26 27 constrlim ⊢ Lim ⁡ m ∧ ∀ n ∈ m C ⁡ n ⊆ ℂ → C ⁡ m = ⋃ o ∈ m C ⁡ o
29 fveq2 ⊢ n = o → C ⁡ n = C ⁡ o
30 29 sseq1d ⊢ n = o → C ⁡ n ⊆ ℂ ↔ C ⁡ o ⊆ ℂ
31 simplr ⊢ Lim ⁡ m ∧ ∀ n ∈ m C ⁡ n ⊆ ℂ ∧ o ∈ m → ∀ n ∈ m C ⁡ n ⊆ ℂ
32 simpr ⊢ Lim ⁡ m ∧ ∀ n ∈ m C ⁡ n ⊆ ℂ ∧ o ∈ m → o ∈ m
33 30 31 32 rspcdva ⊢ Lim ⁡ m ∧ ∀ n ∈ m C ⁡ n ⊆ ℂ ∧ o ∈ m → C ⁡ o ⊆ ℂ
34 33 iunssd ⊢ Lim ⁡ m ∧ ∀ n ∈ m C ⁡ n ⊆ ℂ → ⋃ o ∈ m C ⁡ o ⊆ ℂ
35 28 34 eqsstrd ⊢ Lim ⁡ m ∧ ∀ n ∈ m C ⁡ n ⊆ ℂ → C ⁡ m ⊆ ℂ
36 35 ex ⊢ Lim ⁡ m → ∀ n ∈ m C ⁡ n ⊆ ℂ → C ⁡ m ⊆ ℂ
37 4 6 8 10 16 24 36 tfinds ⊢ N ∈ On → C ⁡ N ⊆ ℂ
38 2 37 syl ⊢ φ → C ⁡ N ⊆ ℂ