Metamath Proof Explorer


Theorem cos9thpiminplylem4

Description: Lemma for cos9thpiminply . (Contributed by Thierry Arnoux, 14-Nov-2025)

Ref Expression
Hypotheses cos9thpiminplylem3.1 ⊢ O = e i ⁢ 2 ⁢ π 3
cos9thpiminplylem4.2 ⊢ Z = O 1 3
Assertion cos9thpiminplylem4 ⊢ Z 6 + Z 3 = − 1

Proof

Step Hyp Ref Expression
1 cos9thpiminplylem3.1 ⊢ O = e i ⁢ 2 ⁢ π 3
2 cos9thpiminplylem4.2 ⊢ Z = O 1 3
3 ax-icn ⊢ i ∈ ℂ
4 2cn ⊢ 2 ∈ ℂ
5 picn ⊢ π ∈ ℂ
6 4 5 mulcli ⊢ 2 ⁢ π ∈ ℂ
7 3 6 mulcli ⊢ i ⁢ 2 ⁢ π ∈ ℂ
8 3cn ⊢ 3 ∈ ℂ
9 3ne0 ⊢ 3 ≠ 0
10 7 8 9 divcli ⊢ i ⁢ 2 ⁢ π 3 ∈ ℂ
11 efcl ⊢ i ⁢ 2 ⁢ π 3 ∈ ℂ → e i ⁢ 2 ⁢ π 3 ∈ ℂ
12 10 11 ax-mp ⊢ e i ⁢ 2 ⁢ π 3 ∈ ℂ
13 1 12 eqeltri ⊢ O ∈ ℂ
14 8 9 reccli ⊢ 1 3 ∈ ℂ
15 cxpcl ⊢ O ∈ ℂ ∧ 1 3 ∈ ℂ → O 1 3 ∈ ℂ
16 13 14 15 mp2an ⊢ O 1 3 ∈ ℂ
17 2 16 eqeltri ⊢ Z ∈ ℂ
18 3nn0 ⊢ 3 ∈ ℕ 0
19 2nn0 ⊢ 2 ∈ ℕ 0
20 expmul ⊢ Z ∈ ℂ ∧ 3 ∈ ℕ 0 ∧ 2 ∈ ℕ 0 → Z 3 ⋅ 2 = Z 3 2
21 17 18 19 20 mp3an ⊢ Z 3 ⋅ 2 = Z 3 2
22 3t2e6 ⊢ 3 ⋅ 2 = 6
23 22 oveq2i ⊢ Z 3 ⋅ 2 = Z 6
24 2 oveq1i ⊢ Z 3 = O 1 3 3
25 cxpmul2 ⊢ O ∈ ℂ ∧ 1 3 ∈ ℂ ∧ 3 ∈ ℕ 0 → O 1 3 ⋅ 3 = O 1 3 3
26 13 14 18 25 mp3an ⊢ O 1 3 ⋅ 3 = O 1 3 3
27 24 26 eqtr4i ⊢ Z 3 = O 1 3 ⋅ 3
28 ax-1cn ⊢ 1 ∈ ℂ
29 28 8 9 divcan1i ⊢ 1 3 ⋅ 3 = 1
30 29 oveq2i ⊢ O 1 3 ⋅ 3 = O 1
31 cxp1 ⊢ O ∈ ℂ → O 1 = O
32 13 31 ax-mp ⊢ O 1 = O
33 27 30 32 3eqtri ⊢ Z 3 = O
34 33 oveq1i ⊢ Z 3 2 = O 2
35 21 23 34 3eqtr3i ⊢ Z 6 = O 2
36 35 33 oveq12i ⊢ Z 6 + Z 3 = O 2 + O
37 13 sqcli ⊢ O 2 ∈ ℂ
38 37 13 addcli ⊢ O 2 + O ∈ ℂ
39 38 28 pm3.2i ⊢ O 2 + O ∈ ℂ ∧ 1 ∈ ℂ
40 37 13 28 addassi ⊢ O 2 + O + 1 = O 2 + O + 1
41 1 cos9thpiminplylem3 ⊢ O 2 + O + 1 = 0
42 40 41 eqtri ⊢ O 2 + O + 1 = 0
43 addeq0 ⊢ O 2 + O ∈ ℂ ∧ 1 ∈ ℂ → O 2 + O + 1 = 0 ↔ O 2 + O = − 1
44 43 biimpa ⊢ O 2 + O ∈ ℂ ∧ 1 ∈ ℂ ∧ O 2 + O + 1 = 0 → O 2 + O = − 1
45 39 42 44 mp2an ⊢ O 2 + O = − 1
46 36 45 eqtri ⊢ Z 6 + Z 3 = − 1