Metamath Proof Explorer


Theorem crngcomd

Description: Multiplication is commutative in a commutative ring. (Contributed by SN, 8-Mar-2025)

Ref Expression
Hypotheses crngcomd.b ⊢ B = Base R
crngcomd.t ⊢ · ˙ = ⋅ R
crngcomd.r ⊢ φ → R ∈ CRing
crngcomd.1 ⊢ φ → X ∈ B
crngcomd.2 ⊢ φ → Y ∈ B
Assertion crngcomd ⊢ φ → X · ˙ Y = Y · ˙ X

Proof

Step Hyp Ref Expression
1 crngcomd.b ⊢ B = Base R
2 crngcomd.t ⊢ · ˙ = ⋅ R
3 crngcomd.r ⊢ φ → R ∈ CRing
4 crngcomd.1 ⊢ φ → X ∈ B
5 crngcomd.2 ⊢ φ → Y ∈ B
6 1 2 crngcom ⊢ R ∈ CRing ∧ X ∈ B ∧ Y ∈ B → X · ˙ Y = Y · ˙ X
7 3 4 5 6 syl3anc ⊢ φ → X · ˙ Y = Y · ˙ X