Metamath Proof Explorer


Theorem csbco3g

Description: Composition of two class substitutions. Usage of this theorem is discouraged because it depends on ax-13 . (Contributed by NM, 27-Nov-2005) (Revised by Mario Carneiro, 11-Nov-2016) (New usage is discouraged.)

Ref Expression
Hypothesis sbcco3g.1 ⊢ x = A → B = C
Assertion csbco3g ⊢ A ∈ V → ⦋ A / x⦌ ⦋ B / y⦌ D = ⦋ C / y⦌ D

Proof

Step Hyp Ref Expression
1 sbcco3g.1 ⊢ x = A → B = C
2 csbnestg ⊢ A ∈ V → ⦋ A / x⦌ ⦋ B / y⦌ D = ⦋ ⦋ A / x⦌ B / y⦌ D
3 elex ⊢ A ∈ V → A ∈ V
4 nfcvd ⊢ A ∈ V → Ⅎ _ x C
5 4 1 csbiegf ⊢ A ∈ V → ⦋ A / x⦌ B = C
6 3 5 syl ⊢ A ∈ V → ⦋ A / x⦌ B = C
7 6 csbeq1d ⊢ A ∈ V → ⦋ ⦋ A / x⦌ B / y⦌ D = ⦋ C / y⦌ D
8 2 7 eqtrd ⊢ A ∈ V → ⦋ A / x⦌ ⦋ B / y⦌ D = ⦋ C / y⦌ D