Metamath Proof Explorer


Theorem curf11

Description: Value of the double evaluated curry functor. (Contributed by Mario Carneiro, 12-Jan-2017)

Ref Expression
Hypotheses curfval.g ⊢ G = C D curry F F
curfval.a ⊢ A = Base C
curfval.c ⊢ φ → C ∈ Cat
curfval.d ⊢ φ → D ∈ Cat
curfval.f ⊢ φ → F ∈ C × c D Func E
curfval.b ⊢ B = Base D
curf1.x ⊢ φ → X ∈ A
curf1.k ⊢ K = 1 st ⁡ G ⁡ X
curf11.y ⊢ φ → Y ∈ B
Assertion curf11 ⊢ φ → 1 st ⁡ K ⁡ Y = X 1 st ⁡ F Y

Proof

Step Hyp Ref Expression
1 curfval.g ⊢ G = C D curry F F
2 curfval.a ⊢ A = Base C
3 curfval.c ⊢ φ → C ∈ Cat
4 curfval.d ⊢ φ → D ∈ Cat
5 curfval.f ⊢ φ → F ∈ C × c D Func E
6 curfval.b ⊢ B = Base D
7 curf1.x ⊢ φ → X ∈ A
8 curf1.k ⊢ K = 1 st ⁡ G ⁡ X
9 curf11.y ⊢ φ → Y ∈ B
10 eqid ⊢ Hom ⁡ D = Hom ⁡ D
11 eqid ⊢ Id ⁡ C = Id ⁡ C
12 1 2 3 4 5 6 7 8 10 11 curf1 ⊢ φ → K = y ∈ B ⟼ X 1 st ⁡ F y y ∈ B , z ∈ B ⟼ g ∈ y Hom ⁡ D z ⟼ Id ⁡ C ⁡ X X y 2 nd ⁡ F X z g
13 6 fvexi ⊢ B ∈ V
14 13 mptex ⊢ y ∈ B ⟼ X 1 st ⁡ F y ∈ V
15 13 13 mpoex ⊢ y ∈ B , z ∈ B ⟼ g ∈ y Hom ⁡ D z ⟼ Id ⁡ C ⁡ X X y 2 nd ⁡ F X z g ∈ V
16 14 15 op1std ⊢ K = y ∈ B ⟼ X 1 st ⁡ F y y ∈ B , z ∈ B ⟼ g ∈ y Hom ⁡ D z ⟼ Id ⁡ C ⁡ X X y 2 nd ⁡ F X z g → 1 st ⁡ K = y ∈ B ⟼ X 1 st ⁡ F y
17 12 16 syl ⊢ φ → 1 st ⁡ K = y ∈ B ⟼ X 1 st ⁡ F y
18 simpr ⊢ φ ∧ y = Y → y = Y
19 18 oveq2d ⊢ φ ∧ y = Y → X 1 st ⁡ F y = X 1 st ⁡ F Y
20 ovexd ⊢ φ → X 1 st ⁡ F Y ∈ V
21 17 19 9 20 fvmptd ⊢ φ → 1 st ⁡ K ⁡ Y = X 1 st ⁡ F Y