Metamath Proof Explorer


Theorem cvlsupr5

Description: Consequence of superposition condition ( P .\/ R ) = ( Q .\/ R ) . (Contributed by NM, 9-Nov-2012)

Ref Expression
Hypotheses cvlsupr5.a ⊢ A = Atoms ⁡ K
cvlsupr5.j ⊢ ∨ ˙ = join ⁡ K
Assertion cvlsupr5 ⊢ K ∈ CvLat ∧ P ∈ A ∧ Q ∈ A ∧ R ∈ A ∧ P ≠ Q ∧ P ∨ ˙ R = Q ∨ ˙ R → R ≠ P

Proof

Step Hyp Ref Expression
1 cvlsupr5.a ⊢ A = Atoms ⁡ K
2 cvlsupr5.j ⊢ ∨ ˙ = join ⁡ K
3 eqid ⊢ ≤ K = ≤ K
4 1 3 2 cvlsupr2 ⊢ K ∈ CvLat ∧ P ∈ A ∧ Q ∈ A ∧ R ∈ A ∧ P ≠ Q → P ∨ ˙ R = Q ∨ ˙ R ↔ R ≠ P ∧ R ≠ Q ∧ R ≤ K P ∨ ˙ Q
5 simp1 ⊢ R ≠ P ∧ R ≠ Q ∧ R ≤ K P ∨ ˙ Q → R ≠ P
6 4 5 biimtrdi ⊢ K ∈ CvLat ∧ P ∈ A ∧ Q ∈ A ∧ R ∈ A ∧ P ≠ Q → P ∨ ˙ R = Q ∨ ˙ R → R ≠ P
7 6 3exp ⊢ K ∈ CvLat → P ∈ A ∧ Q ∈ A ∧ R ∈ A → P ≠ Q → P ∨ ˙ R = Q ∨ ˙ R → R ≠ P
8 7 imp4a ⊢ K ∈ CvLat → P ∈ A ∧ Q ∈ A ∧ R ∈ A → P ≠ Q ∧ P ∨ ˙ R = Q ∨ ˙ R → R ≠ P
9 8 3imp ⊢ K ∈ CvLat ∧ P ∈ A ∧ Q ∈ A ∧ R ∈ A ∧ P ≠ Q ∧ P ∨ ˙ R = Q ∨ ˙ R → R ≠ P