Metamath Proof Explorer


Theorem cxpaddlelem

Description: Lemma for cxpaddle . (Contributed by Mario Carneiro, 2-Aug-2014)

Ref Expression
Hypotheses cxpaddlelem.1 ⊢ φ → A ∈ ℝ
cxpaddlelem.2 ⊢ φ → 0 ≤ A
cxpaddlelem.3 ⊢ φ → A ≤ 1
cxpaddlelem.4 ⊢ φ → B ∈ ℝ +
cxpaddlelem.5 ⊢ φ → B ≤ 1
Assertion cxpaddlelem ⊢ φ → A ≤ A B

Proof

Step Hyp Ref Expression
1 cxpaddlelem.1 ⊢ φ → A ∈ ℝ
2 cxpaddlelem.2 ⊢ φ → 0 ≤ A
3 cxpaddlelem.3 ⊢ φ → A ≤ 1
4 cxpaddlelem.4 ⊢ φ → B ∈ ℝ +
5 cxpaddlelem.5 ⊢ φ → B ≤ 1
6 1re ⊢ 1 ∈ ℝ
7 4 rpred ⊢ φ → B ∈ ℝ
8 resubcl ⊢ 1 ∈ ℝ ∧ B ∈ ℝ → 1 − B ∈ ℝ
9 6 7 8 sylancr ⊢ φ → 1 − B ∈ ℝ
10 1 2 9 recxpcld ⊢ φ → A 1 − B ∈ ℝ
11 10 adantr ⊢ φ ∧ 0 < A → A 1 − B ∈ ℝ
12 1red ⊢ φ ∧ 0 < A → 1 ∈ ℝ
13 recxpcl ⊢ A ∈ ℝ ∧ 0 ≤ A ∧ B ∈ ℝ → A B ∈ ℝ
14 cxpge0 ⊢ A ∈ ℝ ∧ 0 ≤ A ∧ B ∈ ℝ → 0 ≤ A B
15 13 14 jca ⊢ A ∈ ℝ ∧ 0 ≤ A ∧ B ∈ ℝ → A B ∈ ℝ ∧ 0 ≤ A B
16 1 2 7 15 syl3anc ⊢ φ → A B ∈ ℝ ∧ 0 ≤ A B
17 16 adantr ⊢ φ ∧ 0 < A → A B ∈ ℝ ∧ 0 ≤ A B
18 3 ad2antrr ⊢ φ ∧ 0 < A ∧ B < 1 → A ≤ 1
19 1 ad2antrr ⊢ φ ∧ 0 < A ∧ B < 1 → A ∈ ℝ
20 2 ad2antrr ⊢ φ ∧ 0 < A ∧ B < 1 → 0 ≤ A
21 1red ⊢ φ ∧ 0 < A ∧ B < 1 → 1 ∈ ℝ
22 0le1 ⊢ 0 ≤ 1
23 22 a1i ⊢ φ ∧ 0 < A ∧ B < 1 → 0 ≤ 1
24 difrp ⊢ B ∈ ℝ ∧ 1 ∈ ℝ → B < 1 ↔ 1 − B ∈ ℝ +
25 7 6 24 sylancl ⊢ φ → B < 1 ↔ 1 − B ∈ ℝ +
26 25 adantr ⊢ φ ∧ 0 < A → B < 1 ↔ 1 − B ∈ ℝ +
27 26 biimpa ⊢ φ ∧ 0 < A ∧ B < 1 → 1 − B ∈ ℝ +
28 19 20 21 23 27 cxple2d ⊢ φ ∧ 0 < A ∧ B < 1 → A ≤ 1 ↔ A 1 − B ≤ 1 1 − B
29 18 28 mpbid ⊢ φ ∧ 0 < A ∧ B < 1 → A 1 − B ≤ 1 1 − B
30 9 recnd ⊢ φ → 1 − B ∈ ℂ
31 30 1cxpd ⊢ φ → 1 1 − B = 1
32 31 ad2antrr ⊢ φ ∧ 0 < A ∧ B < 1 → 1 1 − B = 1
33 29 32 breqtrd ⊢ φ ∧ 0 < A ∧ B < 1 → A 1 − B ≤ 1
34 simpr ⊢ φ ∧ 0 < A ∧ B = 1 → B = 1
35 34 oveq2d ⊢ φ ∧ 0 < A ∧ B = 1 → 1 − B = 1 − 1
36 1m1e0 ⊢ 1 − 1 = 0
37 35 36 eqtrdi ⊢ φ ∧ 0 < A ∧ B = 1 → 1 − B = 0
38 37 oveq2d ⊢ φ ∧ 0 < A ∧ B = 1 → A 1 − B = A 0
39 1 recnd ⊢ φ → A ∈ ℂ
40 39 ad2antrr ⊢ φ ∧ 0 < A ∧ B = 1 → A ∈ ℂ
41 40 cxp0d ⊢ φ ∧ 0 < A ∧ B = 1 → A 0 = 1
42 38 41 eqtrd ⊢ φ ∧ 0 < A ∧ B = 1 → A 1 − B = 1
43 1le1 ⊢ 1 ≤ 1
44 42 43 eqbrtrdi ⊢ φ ∧ 0 < A ∧ B = 1 → A 1 − B ≤ 1
45 leloe ⊢ B ∈ ℝ ∧ 1 ∈ ℝ → B ≤ 1 ↔ B < 1 ∨ B = 1
46 7 6 45 sylancl ⊢ φ → B ≤ 1 ↔ B < 1 ∨ B = 1
47 5 46 mpbid ⊢ φ → B < 1 ∨ B = 1
48 47 adantr ⊢ φ ∧ 0 < A → B < 1 ∨ B = 1
49 33 44 48 mpjaodan ⊢ φ ∧ 0 < A → A 1 − B ≤ 1
50 lemul1a ⊢ A 1 − B ∈ ℝ ∧ 1 ∈ ℝ ∧ A B ∈ ℝ ∧ 0 ≤ A B ∧ A 1 − B ≤ 1 → A 1 − B ⁢ A B ≤ 1 ⁢ A B
51 11 12 17 49 50 syl31anc ⊢ φ ∧ 0 < A → A 1 − B ⁢ A B ≤ 1 ⁢ A B
52 ax-1cn ⊢ 1 ∈ ℂ
53 7 recnd ⊢ φ → B ∈ ℂ
54 npcan ⊢ 1 ∈ ℂ ∧ B ∈ ℂ → 1 - B + B = 1
55 52 53 54 sylancr ⊢ φ → 1 - B + B = 1
56 55 adantr ⊢ φ ∧ 0 < A → 1 - B + B = 1
57 56 oveq2d ⊢ φ ∧ 0 < A → A 1 - B + B = A 1
58 39 adantr ⊢ φ ∧ 0 < A → A ∈ ℂ
59 1 anim1i ⊢ φ ∧ 0 < A → A ∈ ℝ ∧ 0 < A
60 elrp ⊢ A ∈ ℝ + ↔ A ∈ ℝ ∧ 0 < A
61 59 60 sylibr ⊢ φ ∧ 0 < A → A ∈ ℝ +
62 61 rpne0d ⊢ φ ∧ 0 < A → A ≠ 0
63 30 adantr ⊢ φ ∧ 0 < A → 1 − B ∈ ℂ
64 53 adantr ⊢ φ ∧ 0 < A → B ∈ ℂ
65 58 62 63 64 cxpaddd ⊢ φ ∧ 0 < A → A 1 - B + B = A 1 − B ⁢ A B
66 39 cxp1d ⊢ φ → A 1 = A
67 66 adantr ⊢ φ ∧ 0 < A → A 1 = A
68 57 65 67 3eqtr3d ⊢ φ ∧ 0 < A → A 1 − B ⁢ A B = A
69 39 53 cxpcld ⊢ φ → A B ∈ ℂ
70 69 mullidd ⊢ φ → 1 ⁢ A B = A B
71 70 adantr ⊢ φ ∧ 0 < A → 1 ⁢ A B = A B
72 51 68 71 3brtr3d ⊢ φ ∧ 0 < A → A ≤ A B
73 1 2 7 cxpge0d ⊢ φ → 0 ≤ A B
74 breq1 ⊢ 0 = A → 0 ≤ A B ↔ A ≤ A B
75 73 74 syl5ibcom ⊢ φ → 0 = A → A ≤ A B
76 75 imp ⊢ φ ∧ 0 = A → A ≤ A B
77 0re ⊢ 0 ∈ ℝ
78 leloe ⊢ 0 ∈ ℝ ∧ A ∈ ℝ → 0 ≤ A ↔ 0 < A ∨ 0 = A
79 77 1 78 sylancr ⊢ φ → 0 ≤ A ↔ 0 < A ∨ 0 = A
80 2 79 mpbid ⊢ φ → 0 < A ∨ 0 = A
81 72 76 80 mpjaodan ⊢ φ → A ≤ A B