Metamath Proof Explorer


Theorem cxpmul

Description: Product of exponents law for complex exponentiation. Proposition 10-4.2(b) of Gleason p. 135. (Contributed by Mario Carneiro, 2-Aug-2014)

Ref Expression
Assertion cxpmul ⊢ A ∈ ℝ + ∧ B ∈ ℝ ∧ C ∈ ℂ → A B ⁢ C = A B C

Proof

Step Hyp Ref Expression
1 simp3 ⊢ A ∈ ℝ + ∧ B ∈ ℝ ∧ C ∈ ℂ → C ∈ ℂ
2 simp2 ⊢ A ∈ ℝ + ∧ B ∈ ℝ ∧ C ∈ ℂ → B ∈ ℝ
3 2 recnd ⊢ A ∈ ℝ + ∧ B ∈ ℝ ∧ C ∈ ℂ → B ∈ ℂ
4 relogcl ⊢ A ∈ ℝ + → log ⁡ A ∈ ℝ
5 4 3ad2ant1 ⊢ A ∈ ℝ + ∧ B ∈ ℝ ∧ C ∈ ℂ → log ⁡ A ∈ ℝ
6 5 recnd ⊢ A ∈ ℝ + ∧ B ∈ ℝ ∧ C ∈ ℂ → log ⁡ A ∈ ℂ
7 1 3 6 mulassd ⊢ A ∈ ℝ + ∧ B ∈ ℝ ∧ C ∈ ℂ → C ⁢ B ⁢ log ⁡ A = C ⁢ B ⁢ log ⁡ A
8 3 1 mulcomd ⊢ A ∈ ℝ + ∧ B ∈ ℝ ∧ C ∈ ℂ → B ⁢ C = C ⁢ B
9 8 oveq1d ⊢ A ∈ ℝ + ∧ B ∈ ℝ ∧ C ∈ ℂ → B ⁢ C ⁢ log ⁡ A = C ⁢ B ⁢ log ⁡ A
10 rpcn ⊢ A ∈ ℝ + → A ∈ ℂ
11 10 3ad2ant1 ⊢ A ∈ ℝ + ∧ B ∈ ℝ ∧ C ∈ ℂ → A ∈ ℂ
12 rpne0 ⊢ A ∈ ℝ + → A ≠ 0
13 12 3ad2ant1 ⊢ A ∈ ℝ + ∧ B ∈ ℝ ∧ C ∈ ℂ → A ≠ 0
14 cxpef ⊢ A ∈ ℂ ∧ A ≠ 0 ∧ B ∈ ℂ → A B = e B ⁢ log ⁡ A
15 11 13 3 14 syl3anc ⊢ A ∈ ℝ + ∧ B ∈ ℝ ∧ C ∈ ℂ → A B = e B ⁢ log ⁡ A
16 15 fveq2d ⊢ A ∈ ℝ + ∧ B ∈ ℝ ∧ C ∈ ℂ → log ⁡ A B = log ⁡ e B ⁢ log ⁡ A
17 2 5 remulcld ⊢ A ∈ ℝ + ∧ B ∈ ℝ ∧ C ∈ ℂ → B ⁢ log ⁡ A ∈ ℝ
18 17 relogefd ⊢ A ∈ ℝ + ∧ B ∈ ℝ ∧ C ∈ ℂ → log ⁡ e B ⁢ log ⁡ A = B ⁢ log ⁡ A
19 16 18 eqtrd ⊢ A ∈ ℝ + ∧ B ∈ ℝ ∧ C ∈ ℂ → log ⁡ A B = B ⁢ log ⁡ A
20 19 oveq2d ⊢ A ∈ ℝ + ∧ B ∈ ℝ ∧ C ∈ ℂ → C ⁢ log ⁡ A B = C ⁢ B ⁢ log ⁡ A
21 7 9 20 3eqtr4d ⊢ A ∈ ℝ + ∧ B ∈ ℝ ∧ C ∈ ℂ → B ⁢ C ⁢ log ⁡ A = C ⁢ log ⁡ A B
22 21 fveq2d ⊢ A ∈ ℝ + ∧ B ∈ ℝ ∧ C ∈ ℂ → e B ⁢ C ⁢ log ⁡ A = e C ⁢ log ⁡ A B
23 3 1 mulcld ⊢ A ∈ ℝ + ∧ B ∈ ℝ ∧ C ∈ ℂ → B ⁢ C ∈ ℂ
24 cxpef ⊢ A ∈ ℂ ∧ A ≠ 0 ∧ B ⁢ C ∈ ℂ → A B ⁢ C = e B ⁢ C ⁢ log ⁡ A
25 11 13 23 24 syl3anc ⊢ A ∈ ℝ + ∧ B ∈ ℝ ∧ C ∈ ℂ → A B ⁢ C = e B ⁢ C ⁢ log ⁡ A
26 cxpcl ⊢ A ∈ ℂ ∧ B ∈ ℂ → A B ∈ ℂ
27 11 3 26 syl2anc ⊢ A ∈ ℝ + ∧ B ∈ ℝ ∧ C ∈ ℂ → A B ∈ ℂ
28 cxpne0 ⊢ A ∈ ℂ ∧ A ≠ 0 ∧ B ∈ ℂ → A B ≠ 0
29 11 13 3 28 syl3anc ⊢ A ∈ ℝ + ∧ B ∈ ℝ ∧ C ∈ ℂ → A B ≠ 0
30 cxpef ⊢ A B ∈ ℂ ∧ A B ≠ 0 ∧ C ∈ ℂ → A B C = e C ⁢ log ⁡ A B
31 27 29 1 30 syl3anc ⊢ A ∈ ℝ + ∧ B ∈ ℝ ∧ C ∈ ℂ → A B C = e C ⁢ log ⁡ A B
32 22 25 31 3eqtr4d ⊢ A ∈ ℝ + ∧ B ∈ ℝ ∧ C ∈ ℂ → A B ⁢ C = A B C