Metamath Proof Explorer


Theorem dalem28

Description: Lemma for dath . Lemma dalem27 expressed differently. (Contributed by NM, 4-Aug-2012)

Ref Expression
Hypotheses dalem.ph ⊢ φ ↔ K ∈ HL ∧ C ∈ Base K ∧ P ∈ A ∧ Q ∈ A ∧ R ∈ A ∧ S ∈ A ∧ T ∈ A ∧ U ∈ A ∧ Y ∈ O ∧ Z ∈ O ∧ ¬ C ≤ ˙ P ∨ ˙ Q ∧ ¬ C ≤ ˙ Q ∨ ˙ R ∧ ¬ C ≤ ˙ R ∨ ˙ P ∧ ¬ C ≤ ˙ S ∨ ˙ T ∧ ¬ C ≤ ˙ T ∨ ˙ U ∧ ¬ C ≤ ˙ U ∨ ˙ S ∧ C ≤ ˙ P ∨ ˙ S ∧ C ≤ ˙ Q ∨ ˙ T ∧ C ≤ ˙ R ∨ ˙ U
dalem.l ⊢ ≤ ˙ = ≤ K
dalem.j ⊢ ∨ ˙ = join ⁡ K
dalem.a ⊢ A = Atoms ⁡ K
dalem.ps ⊢ ψ ↔ c ∈ A ∧ d ∈ A ∧ ¬ c ≤ ˙ Y ∧ d ≠ c ∧ ¬ d ≤ ˙ Y ∧ C ≤ ˙ c ∨ ˙ d
dalem23.m ⊢ ∧ ˙ = meet ⁡ K
dalem23.o ⊢ O = LPlanes ⁡ K
dalem23.y ⊢ Y = P ∨ ˙ Q ∨ ˙ R
dalem23.z ⊢ Z = S ∨ ˙ T ∨ ˙ U
dalem23.g ⊢ G = c ∨ ˙ P ∧ ˙ d ∨ ˙ S
Assertion dalem28 ⊢ φ ∧ Y = Z ∧ ψ → P ≤ ˙ G ∨ ˙ c

Proof

Step Hyp Ref Expression
1 dalem.ph ⊢ φ ↔ K ∈ HL ∧ C ∈ Base K ∧ P ∈ A ∧ Q ∈ A ∧ R ∈ A ∧ S ∈ A ∧ T ∈ A ∧ U ∈ A ∧ Y ∈ O ∧ Z ∈ O ∧ ¬ C ≤ ˙ P ∨ ˙ Q ∧ ¬ C ≤ ˙ Q ∨ ˙ R ∧ ¬ C ≤ ˙ R ∨ ˙ P ∧ ¬ C ≤ ˙ S ∨ ˙ T ∧ ¬ C ≤ ˙ T ∨ ˙ U ∧ ¬ C ≤ ˙ U ∨ ˙ S ∧ C ≤ ˙ P ∨ ˙ S ∧ C ≤ ˙ Q ∨ ˙ T ∧ C ≤ ˙ R ∨ ˙ U
2 dalem.l ⊢ ≤ ˙ = ≤ K
3 dalem.j ⊢ ∨ ˙ = join ⁡ K
4 dalem.a ⊢ A = Atoms ⁡ K
5 dalem.ps ⊢ ψ ↔ c ∈ A ∧ d ∈ A ∧ ¬ c ≤ ˙ Y ∧ d ≠ c ∧ ¬ d ≤ ˙ Y ∧ C ≤ ˙ c ∨ ˙ d
6 dalem23.m ⊢ ∧ ˙ = meet ⁡ K
7 dalem23.o ⊢ O = LPlanes ⁡ K
8 dalem23.y ⊢ Y = P ∨ ˙ Q ∨ ˙ R
9 dalem23.z ⊢ Z = S ∨ ˙ T ∨ ˙ U
10 dalem23.g ⊢ G = c ∨ ˙ P ∧ ˙ d ∨ ˙ S
11 1 2 3 4 5 6 7 8 9 10 dalem27 ⊢ φ ∧ Y = Z ∧ ψ → c ≤ ˙ G ∨ ˙ P
12 1 dalemkehl ⊢ φ → K ∈ HL
13 12 3ad2ant1 ⊢ φ ∧ Y = Z ∧ ψ → K ∈ HL
14 5 dalemccea ⊢ ψ → c ∈ A
15 14 3ad2ant3 ⊢ φ ∧ Y = Z ∧ ψ → c ∈ A
16 1 dalempea ⊢ φ → P ∈ A
17 16 3ad2ant1 ⊢ φ ∧ Y = Z ∧ ψ → P ∈ A
18 1 2 3 4 5 6 7 8 9 10 dalem23 ⊢ φ ∧ Y = Z ∧ ψ → G ∈ A
19 1 2 3 4 5 6 7 8 9 10 dalem25 ⊢ φ ∧ Y = Z ∧ ψ → c ≠ G
20 2 3 4 hlatexch1 ⊢ K ∈ HL ∧ c ∈ A ∧ P ∈ A ∧ G ∈ A ∧ c ≠ G → c ≤ ˙ G ∨ ˙ P → P ≤ ˙ G ∨ ˙ c
21 13 15 17 18 19 20 syl131anc ⊢ φ ∧ Y = Z ∧ ψ → c ≤ ˙ G ∨ ˙ P → P ≤ ˙ G ∨ ˙ c
22 11 21 mpd ⊢ φ ∧ Y = Z ∧ ψ → P ≤ ˙ G ∨ ˙ c