Metamath Proof Explorer


Theorem dalem63

Description: Lemma for dath . Combine the cases where Y and Z are different planes with the case where Y and Z are the same plane. (Contributed by NM, 11-Aug-2012)

Ref Expression
Hypotheses dalem62.ph ⊢ φ ↔ K ∈ HL ∧ C ∈ Base K ∧ P ∈ A ∧ Q ∈ A ∧ R ∈ A ∧ S ∈ A ∧ T ∈ A ∧ U ∈ A ∧ Y ∈ O ∧ Z ∈ O ∧ ¬ C ≤ ˙ P ∨ ˙ Q ∧ ¬ C ≤ ˙ Q ∨ ˙ R ∧ ¬ C ≤ ˙ R ∨ ˙ P ∧ ¬ C ≤ ˙ S ∨ ˙ T ∧ ¬ C ≤ ˙ T ∨ ˙ U ∧ ¬ C ≤ ˙ U ∨ ˙ S ∧ C ≤ ˙ P ∨ ˙ S ∧ C ≤ ˙ Q ∨ ˙ T ∧ C ≤ ˙ R ∨ ˙ U
dalem62.l ⊢ ≤ ˙ = ≤ K
dalem62.j ⊢ ∨ ˙ = join ⁡ K
dalem62.a ⊢ A = Atoms ⁡ K
dalem62.m ⊢ ∧ ˙ = meet ⁡ K
dalem62.o ⊢ O = LPlanes ⁡ K
dalem62.y ⊢ Y = P ∨ ˙ Q ∨ ˙ R
dalem62.z ⊢ Z = S ∨ ˙ T ∨ ˙ U
dalem62.d ⊢ D = P ∨ ˙ Q ∧ ˙ S ∨ ˙ T
dalem62.e ⊢ E = Q ∨ ˙ R ∧ ˙ T ∨ ˙ U
dalem62.f ⊢ F = R ∨ ˙ P ∧ ˙ U ∨ ˙ S
Assertion dalem63 ⊢ φ → F ≤ ˙ D ∨ ˙ E

Proof

Step Hyp Ref Expression
1 dalem62.ph ⊢ φ ↔ K ∈ HL ∧ C ∈ Base K ∧ P ∈ A ∧ Q ∈ A ∧ R ∈ A ∧ S ∈ A ∧ T ∈ A ∧ U ∈ A ∧ Y ∈ O ∧ Z ∈ O ∧ ¬ C ≤ ˙ P ∨ ˙ Q ∧ ¬ C ≤ ˙ Q ∨ ˙ R ∧ ¬ C ≤ ˙ R ∨ ˙ P ∧ ¬ C ≤ ˙ S ∨ ˙ T ∧ ¬ C ≤ ˙ T ∨ ˙ U ∧ ¬ C ≤ ˙ U ∨ ˙ S ∧ C ≤ ˙ P ∨ ˙ S ∧ C ≤ ˙ Q ∨ ˙ T ∧ C ≤ ˙ R ∨ ˙ U
2 dalem62.l ⊢ ≤ ˙ = ≤ K
3 dalem62.j ⊢ ∨ ˙ = join ⁡ K
4 dalem62.a ⊢ A = Atoms ⁡ K
5 dalem62.m ⊢ ∧ ˙ = meet ⁡ K
6 dalem62.o ⊢ O = LPlanes ⁡ K
7 dalem62.y ⊢ Y = P ∨ ˙ Q ∨ ˙ R
8 dalem62.z ⊢ Z = S ∨ ˙ T ∨ ˙ U
9 dalem62.d ⊢ D = P ∨ ˙ Q ∧ ˙ S ∨ ˙ T
10 dalem62.e ⊢ E = Q ∨ ˙ R ∧ ˙ T ∨ ˙ U
11 dalem62.f ⊢ F = R ∨ ˙ P ∧ ˙ U ∨ ˙ S
12 1 2 3 4 5 6 7 8 9 10 11 dalem62 ⊢ φ ∧ Y = Z → F ≤ ˙ D ∨ ˙ E
13 1 2 3 4 5 6 7 8 9 10 11 dalem16 ⊢ φ ∧ Y ≠ Z → F ≤ ˙ D ∨ ˙ E
14 12 13 pm2.61dane ⊢ φ → F ≤ ˙ D ∨ ˙ E