Metamath Proof Explorer


Theorem dalemccnedd

Description: Lemma for dath . Frequently-used utility lemma. (Contributed by NM, 15-Aug-2012)

Ref Expression
Hypothesis da.ps0 ⊢ ψ ↔ c ∈ A ∧ d ∈ A ∧ ¬ c ≤ ˙ Y ∧ d ≠ c ∧ ¬ d ≤ ˙ Y ∧ C ≤ ˙ c ∨ ˙ d
Assertion dalemccnedd ⊢ ψ → c ≠ d

Proof

Step Hyp Ref Expression
1 da.ps0 ⊢ ψ ↔ c ∈ A ∧ d ∈ A ∧ ¬ c ≤ ˙ Y ∧ d ≠ c ∧ ¬ d ≤ ˙ Y ∧ C ≤ ˙ c ∨ ˙ d
2 simp31 ⊢ c ∈ A ∧ d ∈ A ∧ ¬ c ≤ ˙ Y ∧ d ≠ c ∧ ¬ d ≤ ˙ Y ∧ C ≤ ˙ c ∨ ˙ d → d ≠ c
3 1 2 sylbi ⊢ ψ → d ≠ c
4 3 necomd ⊢ ψ → c ≠ d