Metamath Proof Explorer


Theorem dalemdnee

Description: Lemma for dath . Axis of perspectivity points D and E are different. (Contributed by NM, 10-Aug-2012)

Ref Expression
Hypotheses dalema.ph ⊢ φ ↔ K ∈ HL ∧ C ∈ Base K ∧ P ∈ A ∧ Q ∈ A ∧ R ∈ A ∧ S ∈ A ∧ T ∈ A ∧ U ∈ A ∧ Y ∈ O ∧ Z ∈ O ∧ ¬ C ≤ ˙ P ∨ ˙ Q ∧ ¬ C ≤ ˙ Q ∨ ˙ R ∧ ¬ C ≤ ˙ R ∨ ˙ P ∧ ¬ C ≤ ˙ S ∨ ˙ T ∧ ¬ C ≤ ˙ T ∨ ˙ U ∧ ¬ C ≤ ˙ U ∨ ˙ S ∧ C ≤ ˙ P ∨ ˙ S ∧ C ≤ ˙ Q ∨ ˙ T ∧ C ≤ ˙ R ∨ ˙ U
dalemc.l ⊢ ≤ ˙ = ≤ K
dalemc.j ⊢ ∨ ˙ = join ⁡ K
dalemc.a ⊢ A = Atoms ⁡ K
dalem3.m ⊢ ∧ ˙ = meet ⁡ K
dalem3.o ⊢ O = LPlanes ⁡ K
dalem3.y ⊢ Y = P ∨ ˙ Q ∨ ˙ R
dalem3.z ⊢ Z = S ∨ ˙ T ∨ ˙ U
dalem3.d ⊢ D = P ∨ ˙ Q ∧ ˙ S ∨ ˙ T
dalem3.e ⊢ E = Q ∨ ˙ R ∧ ˙ T ∨ ˙ U
Assertion dalemdnee ⊢ φ → D ≠ E

Proof

Step Hyp Ref Expression
1 dalema.ph ⊢ φ ↔ K ∈ HL ∧ C ∈ Base K ∧ P ∈ A ∧ Q ∈ A ∧ R ∈ A ∧ S ∈ A ∧ T ∈ A ∧ U ∈ A ∧ Y ∈ O ∧ Z ∈ O ∧ ¬ C ≤ ˙ P ∨ ˙ Q ∧ ¬ C ≤ ˙ Q ∨ ˙ R ∧ ¬ C ≤ ˙ R ∨ ˙ P ∧ ¬ C ≤ ˙ S ∨ ˙ T ∧ ¬ C ≤ ˙ T ∨ ˙ U ∧ ¬ C ≤ ˙ U ∨ ˙ S ∧ C ≤ ˙ P ∨ ˙ S ∧ C ≤ ˙ Q ∨ ˙ T ∧ C ≤ ˙ R ∨ ˙ U
2 dalemc.l ⊢ ≤ ˙ = ≤ K
3 dalemc.j ⊢ ∨ ˙ = join ⁡ K
4 dalemc.a ⊢ A = Atoms ⁡ K
5 dalem3.m ⊢ ∧ ˙ = meet ⁡ K
6 dalem3.o ⊢ O = LPlanes ⁡ K
7 dalem3.y ⊢ Y = P ∨ ˙ Q ∨ ˙ R
8 dalem3.z ⊢ Z = S ∨ ˙ T ∨ ˙ U
9 dalem3.d ⊢ D = P ∨ ˙ Q ∧ ˙ S ∨ ˙ T
10 dalem3.e ⊢ E = Q ∨ ˙ R ∧ ˙ T ∨ ˙ U
11 simpr ⊢ φ ∧ D = Q → D = Q
12 1 2 3 4 6 7 dalemqnet ⊢ φ → Q ≠ T
13 12 adantr ⊢ φ ∧ D = Q → Q ≠ T
14 11 13 eqnetrd ⊢ φ ∧ D = Q → D ≠ T
15 1 2 3 4 5 6 7 8 9 10 dalem4 ⊢ φ ∧ D ≠ T → D ≠ E
16 14 15 syldan ⊢ φ ∧ D = Q → D ≠ E
17 1 2 3 4 5 6 7 8 9 10 dalem3 ⊢ φ ∧ D ≠ Q → D ≠ E
18 16 17 pm2.61dane ⊢ φ → D ≠ E