Metamath Proof Explorer


Theorem dalemswapyzps

Description: Lemma for dath . Swap the Y and Z planes, along with dummy concurrency (center of perspectivity) atoms c and d , to allow reuse of analogous proofs. (Contributed by NM, 17-Aug-2012)

Ref Expression
Hypotheses dalem.ph ⊢ φ ↔ K ∈ HL ∧ C ∈ Base K ∧ P ∈ A ∧ Q ∈ A ∧ R ∈ A ∧ S ∈ A ∧ T ∈ A ∧ U ∈ A ∧ Y ∈ O ∧ Z ∈ O ∧ ¬ C ≤ ˙ P ∨ ˙ Q ∧ ¬ C ≤ ˙ Q ∨ ˙ R ∧ ¬ C ≤ ˙ R ∨ ˙ P ∧ ¬ C ≤ ˙ S ∨ ˙ T ∧ ¬ C ≤ ˙ T ∨ ˙ U ∧ ¬ C ≤ ˙ U ∨ ˙ S ∧ C ≤ ˙ P ∨ ˙ S ∧ C ≤ ˙ Q ∨ ˙ T ∧ C ≤ ˙ R ∨ ˙ U
dalem.l ⊢ ≤ ˙ = ≤ K
dalem.j ⊢ ∨ ˙ = join ⁡ K
dalem.a ⊢ A = Atoms ⁡ K
dalem.ps ⊢ ψ ↔ c ∈ A ∧ d ∈ A ∧ ¬ c ≤ ˙ Y ∧ d ≠ c ∧ ¬ d ≤ ˙ Y ∧ C ≤ ˙ c ∨ ˙ d
Assertion dalemswapyzps ⊢ φ ∧ Y = Z ∧ ψ → d ∈ A ∧ c ∈ A ∧ ¬ d ≤ ˙ Z ∧ c ≠ d ∧ ¬ c ≤ ˙ Z ∧ C ≤ ˙ d ∨ ˙ c

Proof

Step Hyp Ref Expression
1 dalem.ph ⊢ φ ↔ K ∈ HL ∧ C ∈ Base K ∧ P ∈ A ∧ Q ∈ A ∧ R ∈ A ∧ S ∈ A ∧ T ∈ A ∧ U ∈ A ∧ Y ∈ O ∧ Z ∈ O ∧ ¬ C ≤ ˙ P ∨ ˙ Q ∧ ¬ C ≤ ˙ Q ∨ ˙ R ∧ ¬ C ≤ ˙ R ∨ ˙ P ∧ ¬ C ≤ ˙ S ∨ ˙ T ∧ ¬ C ≤ ˙ T ∨ ˙ U ∧ ¬ C ≤ ˙ U ∨ ˙ S ∧ C ≤ ˙ P ∨ ˙ S ∧ C ≤ ˙ Q ∨ ˙ T ∧ C ≤ ˙ R ∨ ˙ U
2 dalem.l ⊢ ≤ ˙ = ≤ K
3 dalem.j ⊢ ∨ ˙ = join ⁡ K
4 dalem.a ⊢ A = Atoms ⁡ K
5 dalem.ps ⊢ ψ ↔ c ∈ A ∧ d ∈ A ∧ ¬ c ≤ ˙ Y ∧ d ≠ c ∧ ¬ d ≤ ˙ Y ∧ C ≤ ˙ c ∨ ˙ d
6 5 dalemddea ⊢ ψ → d ∈ A
7 5 dalemccea ⊢ ψ → c ∈ A
8 6 7 jca ⊢ ψ → d ∈ A ∧ c ∈ A
9 8 3ad2ant3 ⊢ φ ∧ Y = Z ∧ ψ → d ∈ A ∧ c ∈ A
10 5 dalem-ddly ⊢ ψ → ¬ d ≤ ˙ Y
11 10 3ad2ant3 ⊢ φ ∧ Y = Z ∧ ψ → ¬ d ≤ ˙ Y
12 simp2 ⊢ φ ∧ Y = Z ∧ ψ → Y = Z
13 12 breq2d ⊢ φ ∧ Y = Z ∧ ψ → d ≤ ˙ Y ↔ d ≤ ˙ Z
14 11 13 mtbid ⊢ φ ∧ Y = Z ∧ ψ → ¬ d ≤ ˙ Z
15 5 dalemccnedd ⊢ ψ → c ≠ d
16 15 3ad2ant3 ⊢ φ ∧ Y = Z ∧ ψ → c ≠ d
17 5 dalem-ccly ⊢ ψ → ¬ c ≤ ˙ Y
18 17 3ad2ant3 ⊢ φ ∧ Y = Z ∧ ψ → ¬ c ≤ ˙ Y
19 12 breq2d ⊢ φ ∧ Y = Z ∧ ψ → c ≤ ˙ Y ↔ c ≤ ˙ Z
20 18 19 mtbid ⊢ φ ∧ Y = Z ∧ ψ → ¬ c ≤ ˙ Z
21 5 dalemclccjdd ⊢ ψ → C ≤ ˙ c ∨ ˙ d
22 21 3ad2ant3 ⊢ φ ∧ Y = Z ∧ ψ → C ≤ ˙ c ∨ ˙ d
23 1 dalemkehl ⊢ φ → K ∈ HL
24 23 3ad2ant1 ⊢ φ ∧ Y = Z ∧ ψ → K ∈ HL
25 7 3ad2ant3 ⊢ φ ∧ Y = Z ∧ ψ → c ∈ A
26 6 3ad2ant3 ⊢ φ ∧ Y = Z ∧ ψ → d ∈ A
27 3 4 hlatjcom ⊢ K ∈ HL ∧ c ∈ A ∧ d ∈ A → c ∨ ˙ d = d ∨ ˙ c
28 24 25 26 27 syl3anc ⊢ φ ∧ Y = Z ∧ ψ → c ∨ ˙ d = d ∨ ˙ c
29 22 28 breqtrd ⊢ φ ∧ Y = Z ∧ ψ → C ≤ ˙ d ∨ ˙ c
30 16 20 29 3jca ⊢ φ ∧ Y = Z ∧ ψ → c ≠ d ∧ ¬ c ≤ ˙ Z ∧ C ≤ ˙ d ∨ ˙ c
31 9 14 30 3jca ⊢ φ ∧ Y = Z ∧ ψ → d ∈ A ∧ c ∈ A ∧ ¬ d ≤ ˙ Z ∧ c ≠ d ∧ ¬ c ≤ ˙ Z ∧ C ≤ ˙ d ∨ ˙ c