Metamath Proof Explorer


Theorem deg1ge

Description: Conversely, a nonzero coefficient sets a lower bound on the degree. (Contributed by Stefan O'Rear, 23-Mar-2015)

Ref Expression
Hypotheses deg1leb.d ⊢ D = deg 1 ⁡ R
deg1leb.p ⊢ P = Poly 1 ⁡ R
deg1leb.b ⊢ B = Base P
deg1leb.y ⊢ 0 ˙ = 0 R
deg1leb.a ⊢ A = coe 1 ⁡ F
Assertion deg1ge ⊢ F ∈ B ∧ G ∈ ℕ 0 ∧ A ⁡ G ≠ 0 ˙ → G ≤ D ⁡ F

Proof

Step Hyp Ref Expression
1 deg1leb.d ⊢ D = deg 1 ⁡ R
2 deg1leb.p ⊢ P = Poly 1 ⁡ R
3 deg1leb.b ⊢ B = Base P
4 deg1leb.y ⊢ 0 ˙ = 0 R
5 deg1leb.a ⊢ A = coe 1 ⁡ F
6 1 2 3 deg1xrcl ⊢ F ∈ B → D ⁡ F ∈ ℝ *
7 nn0re ⊢ G ∈ ℕ 0 → G ∈ ℝ
8 7 rexrd ⊢ G ∈ ℕ 0 → G ∈ ℝ *
9 xrltnle ⊢ D ⁡ F ∈ ℝ * ∧ G ∈ ℝ * → D ⁡ F < G ↔ ¬ G ≤ D ⁡ F
10 6 8 9 syl2an ⊢ F ∈ B ∧ G ∈ ℕ 0 → D ⁡ F < G ↔ ¬ G ≤ D ⁡ F
11 1 2 3 4 5 deg1lt ⊢ F ∈ B ∧ G ∈ ℕ 0 ∧ D ⁡ F < G → A ⁡ G = 0 ˙
12 11 3expia ⊢ F ∈ B ∧ G ∈ ℕ 0 → D ⁡ F < G → A ⁡ G = 0 ˙
13 10 12 sylbird ⊢ F ∈ B ∧ G ∈ ℕ 0 → ¬ G ≤ D ⁡ F → A ⁡ G = 0 ˙
14 13 necon1ad ⊢ F ∈ B ∧ G ∈ ℕ 0 → A ⁡ G ≠ 0 ˙ → G ≤ D ⁡ F
15 14 3impia ⊢ F ∈ B ∧ G ∈ ℕ 0 ∧ A ⁡ G ≠ 0 ˙ → G ≤ D ⁡ F