Metamath Proof Explorer


Theorem deg1sclle

Description: A scalar polynomial has nonpositive degree. (Contributed by Stefan O'Rear, 29-Mar-2015)

Ref Expression
Hypotheses deg1sclle.d ⊢ D = deg 1 ⁡ R
deg1sclle.p ⊢ P = Poly 1 ⁡ R
deg1sclle.k ⊢ K = Base R
deg1sclle.a ⊢ A = algSc ⁡ P
Assertion deg1sclle ⊢ R ∈ Ring ∧ F ∈ K → D ⁡ A ⁡ F ≤ 0

Proof

Step Hyp Ref Expression
1 deg1sclle.d ⊢ D = deg 1 ⁡ R
2 deg1sclle.p ⊢ P = Poly 1 ⁡ R
3 deg1sclle.k ⊢ K = Base R
4 deg1sclle.a ⊢ A = algSc ⁡ P
5 2 4 3 ply1sclid ⊢ R ∈ Ring ∧ F ∈ K → F = coe 1 ⁡ A ⁡ F ⁡ 0
6 5 fveq2d ⊢ R ∈ Ring ∧ F ∈ K → A ⁡ F = A ⁡ coe 1 ⁡ A ⁡ F ⁡ 0
7 eqid ⊢ Base P = Base P
8 2 4 3 7 ply1sclcl ⊢ R ∈ Ring ∧ F ∈ K → A ⁡ F ∈ Base P
9 1 2 7 4 deg1le0 ⊢ R ∈ Ring ∧ A ⁡ F ∈ Base P → D ⁡ A ⁡ F ≤ 0 ↔ A ⁡ F = A ⁡ coe 1 ⁡ A ⁡ F ⁡ 0
10 8 9 syldan ⊢ R ∈ Ring ∧ F ∈ K → D ⁡ A ⁡ F ≤ 0 ↔ A ⁡ F = A ⁡ coe 1 ⁡ A ⁡ F ⁡ 0
11 6 10 mpbird ⊢ R ∈ Ring ∧ F ∈ K → D ⁡ A ⁡ F ≤ 0