Metamath Proof Explorer


Theorem deg1sub

Description: Exact degree of a difference of two polynomials of unequal degree. (Contributed by Stefan O'Rear, 28-Mar-2015)

Ref Expression
Hypotheses deg1addle.y ⊢ Y = Poly 1 ⁡ R
deg1addle.d ⊢ D = deg 1 ⁡ R
deg1addle.r ⊢ φ → R ∈ Ring
deg1suble.b ⊢ B = Base Y
deg1suble.m ⊢ - ˙ = - Y
deg1suble.f ⊢ φ → F ∈ B
deg1suble.g ⊢ φ → G ∈ B
deg1sub.l ⊢ φ → D ⁡ G < D ⁡ F
Assertion deg1sub ⊢ φ → D ⁡ F - ˙ G = D ⁡ F

Proof

Step Hyp Ref Expression
1 deg1addle.y ⊢ Y = Poly 1 ⁡ R
2 deg1addle.d ⊢ D = deg 1 ⁡ R
3 deg1addle.r ⊢ φ → R ∈ Ring
4 deg1suble.b ⊢ B = Base Y
5 deg1suble.m ⊢ - ˙ = - Y
6 deg1suble.f ⊢ φ → F ∈ B
7 deg1suble.g ⊢ φ → G ∈ B
8 deg1sub.l ⊢ φ → D ⁡ G < D ⁡ F
9 eqid ⊢ + Y = + Y
10 eqid ⊢ inv g ⁡ Y = inv g ⁡ Y
11 4 9 10 5 grpsubval ⊢ F ∈ B ∧ G ∈ B → F - ˙ G = F + Y inv g ⁡ Y ⁡ G
12 6 7 11 syl2anc ⊢ φ → F - ˙ G = F + Y inv g ⁡ Y ⁡ G
13 12 fveq2d ⊢ φ → D ⁡ F - ˙ G = D ⁡ F + Y inv g ⁡ Y ⁡ G
14 1 ply1ring ⊢ R ∈ Ring → Y ∈ Ring
15 ringgrp ⊢ Y ∈ Ring → Y ∈ Grp
16 3 14 15 3syl ⊢ φ → Y ∈ Grp
17 4 10 grpinvcl ⊢ Y ∈ Grp ∧ G ∈ B → inv g ⁡ Y ⁡ G ∈ B
18 16 7 17 syl2anc ⊢ φ → inv g ⁡ Y ⁡ G ∈ B
19 1 2 3 4 10 7 deg1invg ⊢ φ → D ⁡ inv g ⁡ Y ⁡ G = D ⁡ G
20 19 8 eqbrtrd ⊢ φ → D ⁡ inv g ⁡ Y ⁡ G < D ⁡ F
21 1 2 3 4 9 6 18 20 deg1add ⊢ φ → D ⁡ F + Y inv g ⁡ Y ⁡ G = D ⁡ F
22 13 21 eqtrd ⊢ φ → D ⁡ F - ˙ G = D ⁡ F