Metamath Proof Explorer


Definition df-ply

Description: Define the set of polynomials on the complex numbers with coefficients in the given subset. (Contributed by Mario Carneiro, 17-Jul-2014)

Ref Expression
Assertion df-ply ⊢ Poly = x ∈ 𝒫 ℂ ⟼ f | ∃ n ∈ ℕ 0 ∃ a ∈ x ∪ 0 ℕ 0 f = z ∈ ℂ ⟼ ∑ k = 0 n a ⁡ k ⁢ z k

Detailed syntax breakdown

Step Hyp Ref Expression
0 cply class Poly
1 vx setvar x
2 cc class ℂ
3 2 cpw class 𝒫 ℂ
4 vf setvar f
5 vn setvar n
6 cn0 class ℕ 0
7 va setvar a
8 1 cv setvar x
9 cc0 class 0
10 9 csn class 0
11 8 10 cun class x ∪ 0
12 cmap class ↑ 𝑚
13 11 6 12 co class x ∪ 0 ℕ 0
14 4 cv setvar f
15 vz setvar z
16 vk setvar k
17 cfz class …
18 5 cv setvar n
19 9 18 17 co class 0 … n
20 7 cv setvar a
21 16 cv setvar k
22 21 20 cfv class a ⁡ k
23 cmul class ×
24 15 cv setvar z
25 cexp class ^
26 24 21 25 co class z k
27 22 26 23 co class a ⁡ k ⁢ z k
28 19 27 16 csu class ∑ k = 0 n a ⁡ k ⁢ z k
29 15 2 28 cmpt class z ∈ ℂ ⟼ ∑ k = 0 n a ⁡ k ⁢ z k
30 14 29 wceq wff f = z ∈ ℂ ⟼ ∑ k = 0 n a ⁡ k ⁢ z k
31 30 7 13 wrex wff ∃ a ∈ x ∪ 0 ℕ 0 f = z ∈ ℂ ⟼ ∑ k = 0 n a ⁡ k ⁢ z k
32 31 5 6 wrex wff ∃ n ∈ ℕ 0 ∃ a ∈ x ∪ 0 ℕ 0 f = z ∈ ℂ ⟼ ∑ k = 0 n a ⁡ k ⁢ z k
33 32 4 cab class f | ∃ n ∈ ℕ 0 ∃ a ∈ x ∪ 0 ℕ 0 f = z ∈ ℂ ⟼ ∑ k = 0 n a ⁡ k ⁢ z k
34 1 3 33 cmpt class x ∈ 𝒫 ℂ ⟼ f | ∃ n ∈ ℕ 0 ∃ a ∈ x ∪ 0 ℕ 0 f = z ∈ ℂ ⟼ ∑ k = 0 n a ⁡ k ⁢ z k
35 0 34 wceq wff Poly = x ∈ 𝒫 ℂ ⟼ f | ∃ n ∈ ℕ 0 ∃ a ∈ x ∪ 0 ℕ 0 f = z ∈ ℂ ⟼ ∑ k = 0 n a ⁡ k ⁢ z k