Metamath Proof Explorer


Theorem dfcnv2

Description: Alternative definition of the converse of a relation. (Contributed by Thierry Arnoux, 31-Mar-2018)

Ref Expression
Assertion dfcnv2 ⊢ ran ⁡ R ⊆ A → R -1 = ⋃ x ∈ A x × R -1 x

Proof

Step Hyp Ref Expression
1 relcnv ⊢ Rel ⁡ R -1
2 relxp ⊢ Rel ⁡ x × R -1 x
3 2 rgenw ⊢ ∀ x ∈ A Rel ⁡ x × R -1 x
4 reliun ⊢ Rel ⁡ ⋃ x ∈ A x × R -1 x ↔ ∀ x ∈ A Rel ⁡ x × R -1 x
5 3 4 mpbir ⊢ Rel ⁡ ⋃ x ∈ A x × R -1 x
6 vex ⊢ z ∈ V
7 vex ⊢ y ∈ V
8 6 7 opeldm ⊢ z y ∈ R -1 → z ∈ dom ⁡ R -1
9 df-rn ⊢ ran ⁡ R = dom ⁡ R -1
10 8 9 eleqtrrdi ⊢ z y ∈ R -1 → z ∈ ran ⁡ R
11 ssel2 ⊢ ran ⁡ R ⊆ A ∧ z ∈ ran ⁡ R → z ∈ A
12 10 11 sylan2 ⊢ ran ⁡ R ⊆ A ∧ z y ∈ R -1 → z ∈ A
13 12 ex ⊢ ran ⁡ R ⊆ A → z y ∈ R -1 → z ∈ A
14 13 pm4.71rd ⊢ ran ⁡ R ⊆ A → z y ∈ R -1 ↔ z ∈ A ∧ z y ∈ R -1
15 6 7 elimasn ⊢ y ∈ R -1 z ↔ z y ∈ R -1
16 15 anbi2i ⊢ z ∈ A ∧ y ∈ R -1 z ↔ z ∈ A ∧ z y ∈ R -1
17 14 16 bitr4di ⊢ ran ⁡ R ⊆ A → z y ∈ R -1 ↔ z ∈ A ∧ y ∈ R -1 z
18 sneq ⊢ x = z → x = z
19 18 imaeq2d ⊢ x = z → R -1 x = R -1 z
20 19 opeliunxp2 ⊢ z y ∈ ⋃ x ∈ A x × R -1 x ↔ z ∈ A ∧ y ∈ R -1 z
21 17 20 bitr4di ⊢ ran ⁡ R ⊆ A → z y ∈ R -1 ↔ z y ∈ ⋃ x ∈ A x × R -1 x
22 1 5 21 eqrelrdv ⊢ ran ⁡ R ⊆ A → R -1 = ⋃ x ∈ A x × R -1 x