Metamath Proof Explorer


Theorem dgrmulc

Description: Scalar multiplication by a nonzero constant does not change the degree of a function. (Contributed by Mario Carneiro, 24-Jul-2014)

Ref Expression
Assertion dgrmulc ⊢ A ∈ ℂ ∧ A ≠ 0 ∧ F ∈ Poly ⁡ S → deg ⁡ ℂ × A × f F = deg ⁡ F

Proof

Step Hyp Ref Expression
1 oveq2 ⊢ F = 0 𝑝 → ℂ × A × f F = ℂ × A × f 0 𝑝
2 1 fveq2d ⊢ F = 0 𝑝 → deg ⁡ ℂ × A × f F = deg ⁡ ℂ × A × f 0 𝑝
3 fveq2 ⊢ F = 0 𝑝 → deg ⁡ F = deg ⁡ 0 𝑝
4 dgr0 ⊢ deg ⁡ 0 𝑝 = 0
5 3 4 eqtrdi ⊢ F = 0 𝑝 → deg ⁡ F = 0
6 2 5 eqeq12d ⊢ F = 0 𝑝 → deg ⁡ ℂ × A × f F = deg ⁡ F ↔ deg ⁡ ℂ × A × f 0 𝑝 = 0
7 ssid ⊢ ℂ ⊆ ℂ
8 simpl1 ⊢ A ∈ ℂ ∧ A ≠ 0 ∧ F ∈ Poly ⁡ S ∧ F ≠ 0 𝑝 → A ∈ ℂ
9 plyconst ⊢ ℂ ⊆ ℂ ∧ A ∈ ℂ → ℂ × A ∈ Poly ⁡ ℂ
10 7 8 9 sylancr ⊢ A ∈ ℂ ∧ A ≠ 0 ∧ F ∈ Poly ⁡ S ∧ F ≠ 0 𝑝 → ℂ × A ∈ Poly ⁡ ℂ
11 0cn ⊢ 0 ∈ ℂ
12 fvconst2g ⊢ A ∈ ℂ ∧ 0 ∈ ℂ → ℂ × A ⁡ 0 = A
13 8 11 12 sylancl ⊢ A ∈ ℂ ∧ A ≠ 0 ∧ F ∈ Poly ⁡ S ∧ F ≠ 0 𝑝 → ℂ × A ⁡ 0 = A
14 simpl2 ⊢ A ∈ ℂ ∧ A ≠ 0 ∧ F ∈ Poly ⁡ S ∧ F ≠ 0 𝑝 → A ≠ 0
15 13 14 eqnetrd ⊢ A ∈ ℂ ∧ A ≠ 0 ∧ F ∈ Poly ⁡ S ∧ F ≠ 0 𝑝 → ℂ × A ⁡ 0 ≠ 0
16 ne0p ⊢ 0 ∈ ℂ ∧ ℂ × A ⁡ 0 ≠ 0 → ℂ × A ≠ 0 𝑝
17 11 15 16 sylancr ⊢ A ∈ ℂ ∧ A ≠ 0 ∧ F ∈ Poly ⁡ S ∧ F ≠ 0 𝑝 → ℂ × A ≠ 0 𝑝
18 plyssc ⊢ Poly ⁡ S ⊆ Poly ⁡ ℂ
19 simpl3 ⊢ A ∈ ℂ ∧ A ≠ 0 ∧ F ∈ Poly ⁡ S ∧ F ≠ 0 𝑝 → F ∈ Poly ⁡ S
20 18 19 sselid ⊢ A ∈ ℂ ∧ A ≠ 0 ∧ F ∈ Poly ⁡ S ∧ F ≠ 0 𝑝 → F ∈ Poly ⁡ ℂ
21 simpr ⊢ A ∈ ℂ ∧ A ≠ 0 ∧ F ∈ Poly ⁡ S ∧ F ≠ 0 𝑝 → F ≠ 0 𝑝
22 eqid ⊢ deg ⁡ ℂ × A = deg ⁡ ℂ × A
23 eqid ⊢ deg ⁡ F = deg ⁡ F
24 22 23 dgrmul ⊢ ℂ × A ∈ Poly ⁡ ℂ ∧ ℂ × A ≠ 0 𝑝 ∧ F ∈ Poly ⁡ ℂ ∧ F ≠ 0 𝑝 → deg ⁡ ℂ × A × f F = deg ⁡ ℂ × A + deg ⁡ F
25 10 17 20 21 24 syl22anc ⊢ A ∈ ℂ ∧ A ≠ 0 ∧ F ∈ Poly ⁡ S ∧ F ≠ 0 𝑝 → deg ⁡ ℂ × A × f F = deg ⁡ ℂ × A + deg ⁡ F
26 0dgr ⊢ A ∈ ℂ → deg ⁡ ℂ × A = 0
27 8 26 syl ⊢ A ∈ ℂ ∧ A ≠ 0 ∧ F ∈ Poly ⁡ S ∧ F ≠ 0 𝑝 → deg ⁡ ℂ × A = 0
28 27 oveq1d ⊢ A ∈ ℂ ∧ A ≠ 0 ∧ F ∈ Poly ⁡ S ∧ F ≠ 0 𝑝 → deg ⁡ ℂ × A + deg ⁡ F = 0 + deg ⁡ F
29 dgrcl ⊢ F ∈ Poly ⁡ S → deg ⁡ F ∈ ℕ 0
30 19 29 syl ⊢ A ∈ ℂ ∧ A ≠ 0 ∧ F ∈ Poly ⁡ S ∧ F ≠ 0 𝑝 → deg ⁡ F ∈ ℕ 0
31 30 nn0cnd ⊢ A ∈ ℂ ∧ A ≠ 0 ∧ F ∈ Poly ⁡ S ∧ F ≠ 0 𝑝 → deg ⁡ F ∈ ℂ
32 31 addlidd ⊢ A ∈ ℂ ∧ A ≠ 0 ∧ F ∈ Poly ⁡ S ∧ F ≠ 0 𝑝 → 0 + deg ⁡ F = deg ⁡ F
33 25 28 32 3eqtrd ⊢ A ∈ ℂ ∧ A ≠ 0 ∧ F ∈ Poly ⁡ S ∧ F ≠ 0 𝑝 → deg ⁡ ℂ × A × f F = deg ⁡ F
34 cnex ⊢ ℂ ∈ V
35 34 a1i ⊢ A ∈ ℂ ∧ A ≠ 0 ∧ F ∈ Poly ⁡ S → ℂ ∈ V
36 simp1 ⊢ A ∈ ℂ ∧ A ≠ 0 ∧ F ∈ Poly ⁡ S → A ∈ ℂ
37 11 a1i ⊢ A ∈ ℂ ∧ A ≠ 0 ∧ F ∈ Poly ⁡ S → 0 ∈ ℂ
38 35 36 37 ofc12 ⊢ A ∈ ℂ ∧ A ≠ 0 ∧ F ∈ Poly ⁡ S → ℂ × A × f ℂ × 0 = ℂ × A ⋅ 0
39 36 mul01d ⊢ A ∈ ℂ ∧ A ≠ 0 ∧ F ∈ Poly ⁡ S → A ⋅ 0 = 0
40 39 sneqd ⊢ A ∈ ℂ ∧ A ≠ 0 ∧ F ∈ Poly ⁡ S → A ⋅ 0 = 0
41 40 xpeq2d ⊢ A ∈ ℂ ∧ A ≠ 0 ∧ F ∈ Poly ⁡ S → ℂ × A ⋅ 0 = ℂ × 0
42 38 41 eqtrd ⊢ A ∈ ℂ ∧ A ≠ 0 ∧ F ∈ Poly ⁡ S → ℂ × A × f ℂ × 0 = ℂ × 0
43 df-0p ⊢ 0 𝑝 = ℂ × 0
44 43 oveq2i ⊢ ℂ × A × f 0 𝑝 = ℂ × A × f ℂ × 0
45 42 44 43 3eqtr4g ⊢ A ∈ ℂ ∧ A ≠ 0 ∧ F ∈ Poly ⁡ S → ℂ × A × f 0 𝑝 = 0 𝑝
46 45 fveq2d ⊢ A ∈ ℂ ∧ A ≠ 0 ∧ F ∈ Poly ⁡ S → deg ⁡ ℂ × A × f 0 𝑝 = deg ⁡ 0 𝑝
47 46 4 eqtrdi ⊢ A ∈ ℂ ∧ A ≠ 0 ∧ F ∈ Poly ⁡ S → deg ⁡ ℂ × A × f 0 𝑝 = 0
48 6 33 47 pm2.61ne ⊢ A ∈ ℂ ∧ A ≠ 0 ∧ F ∈ Poly ⁡ S → deg ⁡ ℂ × A × f F = deg ⁡ F