Metamath Proof Explorer


Theorem dia1dimid

Description: A vector (translation) belongs to the 1-dim subspace it generates. (Contributed by NM, 8-Sep-2014)

Ref Expression
Hypotheses dia1dimid.h ⊢ H = LHyp ⁡ K
dia1dimid.t ⊢ T = LTrn ⁡ K ⁡ W
dia1dimid.r ⊢ R = trL ⁡ K ⁡ W
dia1dimid.i ⊢ I = DIsoA ⁡ K ⁡ W
Assertion dia1dimid ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T → F ∈ I ⁡ R ⁡ F

Proof

Step Hyp Ref Expression
1 dia1dimid.h ⊢ H = LHyp ⁡ K
2 dia1dimid.t ⊢ T = LTrn ⁡ K ⁡ W
3 dia1dimid.r ⊢ R = trL ⁡ K ⁡ W
4 dia1dimid.i ⊢ I = DIsoA ⁡ K ⁡ W
5 eqid ⊢ DVecA ⁡ K ⁡ W = DVecA ⁡ K ⁡ W
6 1 5 dvalvec ⊢ K ∈ HL ∧ W ∈ H → DVecA ⁡ K ⁡ W ∈ LVec
7 lveclmod ⊢ DVecA ⁡ K ⁡ W ∈ LVec → DVecA ⁡ K ⁡ W ∈ LMod
8 6 7 syl ⊢ K ∈ HL ∧ W ∈ H → DVecA ⁡ K ⁡ W ∈ LMod
9 8 adantr ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T → DVecA ⁡ K ⁡ W ∈ LMod
10 eqid ⊢ Base DVecA ⁡ K ⁡ W = Base DVecA ⁡ K ⁡ W
11 1 2 5 10 dvavbase ⊢ K ∈ HL ∧ W ∈ H → Base DVecA ⁡ K ⁡ W = T
12 11 eleq2d ⊢ K ∈ HL ∧ W ∈ H → F ∈ Base DVecA ⁡ K ⁡ W ↔ F ∈ T
13 12 biimpar ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T → F ∈ Base DVecA ⁡ K ⁡ W
14 eqid ⊢ LSpan ⁡ DVecA ⁡ K ⁡ W = LSpan ⁡ DVecA ⁡ K ⁡ W
15 10 14 lspsnid ⊢ DVecA ⁡ K ⁡ W ∈ LMod ∧ F ∈ Base DVecA ⁡ K ⁡ W → F ∈ LSpan ⁡ DVecA ⁡ K ⁡ W ⁡ F
16 9 13 15 syl2anc ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T → F ∈ LSpan ⁡ DVecA ⁡ K ⁡ W ⁡ F
17 1 2 3 5 4 14 dia1dim2 ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T → I ⁡ R ⁡ F = LSpan ⁡ DVecA ⁡ K ⁡ W ⁡ F
18 16 17 eleqtrrd ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T → F ∈ I ⁡ R ⁡ F