Metamath Proof Explorer


Theorem diag12

Description: Value of the constant functor at a morphism. (Contributed by Mario Carneiro, 6-Jan-2017) (Revised by Mario Carneiro, 15-Jan-2017)

Ref Expression
Hypotheses diagval.l ⊢ L = C Δ func D
diagval.c ⊢ φ → C ∈ Cat
diagval.d ⊢ φ → D ∈ Cat
diag11.a ⊢ A = Base C
diag11.c ⊢ φ → X ∈ A
diag11.k ⊢ K = 1 st ⁡ L ⁡ X
diag11.b ⊢ B = Base D
diag11.y ⊢ φ → Y ∈ B
diag12.j ⊢ J = Hom ⁡ D
diag12.i ⊢ 1 ˙ = Id ⁡ C
diag12.z ⊢ φ → Z ∈ B
diag12.f ⊢ φ → F ∈ Y J Z
Assertion diag12 ⊢ φ → Y 2 nd ⁡ K Z ⁡ F = 1 ˙ ⁡ X

Proof

Step Hyp Ref Expression
1 diagval.l ⊢ L = C Δ func D
2 diagval.c ⊢ φ → C ∈ Cat
3 diagval.d ⊢ φ → D ∈ Cat
4 diag11.a ⊢ A = Base C
5 diag11.c ⊢ φ → X ∈ A
6 diag11.k ⊢ K = 1 st ⁡ L ⁡ X
7 diag11.b ⊢ B = Base D
8 diag11.y ⊢ φ → Y ∈ B
9 diag12.j ⊢ J = Hom ⁡ D
10 diag12.i ⊢ 1 ˙ = Id ⁡ C
11 diag12.z ⊢ φ → Z ∈ B
12 diag12.f ⊢ φ → F ∈ Y J Z
13 1 2 3 diagval ⊢ φ → L = C D curry F C 1 st F D
14 13 fveq2d ⊢ φ → 1 st ⁡ L = 1 st ⁡ C D curry F C 1 st F D
15 14 fveq1d ⊢ φ → 1 st ⁡ L ⁡ X = 1 st ⁡ C D curry F C 1 st F D ⁡ X
16 6 15 eqtrid ⊢ φ → K = 1 st ⁡ C D curry F C 1 st F D ⁡ X
17 16 fveq2d ⊢ φ → 2 nd ⁡ K = 2 nd ⁡ 1 st ⁡ C D curry F C 1 st F D ⁡ X
18 17 oveqd ⊢ φ → Y 2 nd ⁡ K Z = Y 2 nd ⁡ 1 st ⁡ C D curry F C 1 st F D ⁡ X Z
19 18 fveq1d ⊢ φ → Y 2 nd ⁡ K Z ⁡ F = Y 2 nd ⁡ 1 st ⁡ C D curry F C 1 st F D ⁡ X Z ⁡ F
20 eqid ⊢ C D curry F C 1 st F D = C D curry F C 1 st F D
21 eqid ⊢ C × c D = C × c D
22 eqid ⊢ C 1 st F D = C 1 st F D
23 21 2 3 22 1stfcl ⊢ φ → C 1 st F D ∈ C × c D Func C
24 eqid ⊢ 1 st ⁡ C D curry F C 1 st F D ⁡ X = 1 st ⁡ C D curry F C 1 st F D ⁡ X
25 20 4 2 3 23 7 5 24 8 9 10 11 12 curf12 ⊢ φ → Y 2 nd ⁡ 1 st ⁡ C D curry F C 1 st F D ⁡ X Z ⁡ F = 1 ˙ ⁡ X X Y 2 nd ⁡ C 1 st F D X Z F
26 df-ov ⊢ 1 ˙ ⁡ X X Y 2 nd ⁡ C 1 st F D X Z F = X Y 2 nd ⁡ C 1 st F D X Z ⁡ 1 ˙ ⁡ X F
27 21 4 7 xpcbas ⊢ A × B = Base C × c D
28 eqid ⊢ Hom ⁡ C × c D = Hom ⁡ C × c D
29 5 8 opelxpd ⊢ φ → X Y ∈ A × B
30 5 11 opelxpd ⊢ φ → X Z ∈ A × B
31 21 27 28 2 3 22 29 30 1stf2 ⊢ φ → X Y 2 nd ⁡ C 1 st F D X Z = 1 st ↾ X Y Hom ⁡ C × c D X Z
32 31 fveq1d ⊢ φ → X Y 2 nd ⁡ C 1 st F D X Z ⁡ 1 ˙ ⁡ X F = 1 st ↾ X Y Hom ⁡ C × c D X Z ⁡ 1 ˙ ⁡ X F
33 26 32 eqtrid ⊢ φ → 1 ˙ ⁡ X X Y 2 nd ⁡ C 1 st F D X Z F = 1 st ↾ X Y Hom ⁡ C × c D X Z ⁡ 1 ˙ ⁡ X F
34 eqid ⊢ Hom ⁡ C = Hom ⁡ C
35 4 34 10 2 5 catidcl ⊢ φ → 1 ˙ ⁡ X ∈ X Hom ⁡ C X
36 35 12 opelxpd ⊢ φ → 1 ˙ ⁡ X F ∈ X Hom ⁡ C X × Y J Z
37 21 4 7 34 9 5 8 5 11 28 xpchom2 ⊢ φ → X Y Hom ⁡ C × c D X Z = X Hom ⁡ C X × Y J Z
38 36 37 eleqtrrd ⊢ φ → 1 ˙ ⁡ X F ∈ X Y Hom ⁡ C × c D X Z
39 38 fvresd ⊢ φ → 1 st ↾ X Y Hom ⁡ C × c D X Z ⁡ 1 ˙ ⁡ X F = 1 st ⁡ 1 ˙ ⁡ X F
40 op1stg ⊢ 1 ˙ ⁡ X ∈ X Hom ⁡ C X ∧ F ∈ Y J Z → 1 st ⁡ 1 ˙ ⁡ X F = 1 ˙ ⁡ X
41 35 12 40 syl2anc ⊢ φ → 1 st ⁡ 1 ˙ ⁡ X F = 1 ˙ ⁡ X
42 33 39 41 3eqtrd ⊢ φ → 1 ˙ ⁡ X X Y 2 nd ⁡ C 1 st F D X Z F = 1 ˙ ⁡ X
43 19 25 42 3eqtrd ⊢ φ → Y 2 nd ⁡ K Z ⁡ F = 1 ˙ ⁡ X