Metamath Proof Explorer


Theorem diag2

Description: Value of the diagonal functor at a morphism. (Contributed by Mario Carneiro, 7-Jan-2017)

Ref Expression
Hypotheses diag2.l ⊢ L = C Δ func D
diag2.a ⊢ A = Base C
diag2.b ⊢ B = Base D
diag2.h ⊢ H = Hom ⁡ C
diag2.c ⊢ φ → C ∈ Cat
diag2.d ⊢ φ → D ∈ Cat
diag2.x ⊢ φ → X ∈ A
diag2.y ⊢ φ → Y ∈ A
diag2.f ⊢ φ → F ∈ X H Y
Assertion diag2 ⊢ φ → X 2 nd ⁡ L Y ⁡ F = B × F

Proof

Step Hyp Ref Expression
1 diag2.l ⊢ L = C Δ func D
2 diag2.a ⊢ A = Base C
3 diag2.b ⊢ B = Base D
4 diag2.h ⊢ H = Hom ⁡ C
5 diag2.c ⊢ φ → C ∈ Cat
6 diag2.d ⊢ φ → D ∈ Cat
7 diag2.x ⊢ φ → X ∈ A
8 diag2.y ⊢ φ → Y ∈ A
9 diag2.f ⊢ φ → F ∈ X H Y
10 1 5 6 diagval ⊢ φ → L = C D curry F C 1 st F D
11 10 fveq2d ⊢ φ → 2 nd ⁡ L = 2 nd ⁡ C D curry F C 1 st F D
12 11 oveqd ⊢ φ → X 2 nd ⁡ L Y = X 2 nd ⁡ C D curry F C 1 st F D Y
13 12 fveq1d ⊢ φ → X 2 nd ⁡ L Y ⁡ F = X 2 nd ⁡ C D curry F C 1 st F D Y ⁡ F
14 eqid ⊢ C D curry F C 1 st F D = C D curry F C 1 st F D
15 eqid ⊢ C × c D = C × c D
16 eqid ⊢ C 1 st F D = C 1 st F D
17 15 5 6 16 1stfcl ⊢ φ → C 1 st F D ∈ C × c D Func C
18 eqid ⊢ Id ⁡ D = Id ⁡ D
19 eqid ⊢ X 2 nd ⁡ C D curry F C 1 st F D Y ⁡ F = X 2 nd ⁡ C D curry F C 1 st F D Y ⁡ F
20 14 2 5 6 17 3 4 18 7 8 9 19 curf2 ⊢ φ → X 2 nd ⁡ C D curry F C 1 st F D Y ⁡ F = x ∈ B ⟼ F X x 2 nd ⁡ C 1 st F D Y x Id ⁡ D ⁡ x
21 15 2 3 xpcbas ⊢ A × B = Base C × c D
22 eqid ⊢ Hom ⁡ C × c D = Hom ⁡ C × c D
23 5 adantr ⊢ φ ∧ x ∈ B → C ∈ Cat
24 6 adantr ⊢ φ ∧ x ∈ B → D ∈ Cat
25 opelxpi ⊢ X ∈ A ∧ x ∈ B → X x ∈ A × B
26 7 25 sylan ⊢ φ ∧ x ∈ B → X x ∈ A × B
27 opelxpi ⊢ Y ∈ A ∧ x ∈ B → Y x ∈ A × B
28 8 27 sylan ⊢ φ ∧ x ∈ B → Y x ∈ A × B
29 15 21 22 23 24 16 26 28 1stf2 ⊢ φ ∧ x ∈ B → X x 2 nd ⁡ C 1 st F D Y x = 1 st ↾ X x Hom ⁡ C × c D Y x
30 29 oveqd ⊢ φ ∧ x ∈ B → F X x 2 nd ⁡ C 1 st F D Y x Id ⁡ D ⁡ x = F 1 st ↾ X x Hom ⁡ C × c D Y x Id ⁡ D ⁡ x
31 df-ov ⊢ F 1 st ↾ X x Hom ⁡ C × c D Y x Id ⁡ D ⁡ x = 1 st ↾ X x Hom ⁡ C × c D Y x ⁡ F Id ⁡ D ⁡ x
32 9 adantr ⊢ φ ∧ x ∈ B → F ∈ X H Y
33 eqid ⊢ Hom ⁡ D = Hom ⁡ D
34 simpr ⊢ φ ∧ x ∈ B → x ∈ B
35 3 33 18 24 34 catidcl ⊢ φ ∧ x ∈ B → Id ⁡ D ⁡ x ∈ x Hom ⁡ D x
36 32 35 opelxpd ⊢ φ ∧ x ∈ B → F Id ⁡ D ⁡ x ∈ X H Y × x Hom ⁡ D x
37 7 adantr ⊢ φ ∧ x ∈ B → X ∈ A
38 8 adantr ⊢ φ ∧ x ∈ B → Y ∈ A
39 15 2 3 4 33 37 34 38 34 22 xpchom2 ⊢ φ ∧ x ∈ B → X x Hom ⁡ C × c D Y x = X H Y × x Hom ⁡ D x
40 36 39 eleqtrrd ⊢ φ ∧ x ∈ B → F Id ⁡ D ⁡ x ∈ X x Hom ⁡ C × c D Y x
41 40 fvresd ⊢ φ ∧ x ∈ B → 1 st ↾ X x Hom ⁡ C × c D Y x ⁡ F Id ⁡ D ⁡ x = 1 st ⁡ F Id ⁡ D ⁡ x
42 31 41 eqtrid ⊢ φ ∧ x ∈ B → F 1 st ↾ X x Hom ⁡ C × c D Y x Id ⁡ D ⁡ x = 1 st ⁡ F Id ⁡ D ⁡ x
43 op1stg ⊢ F ∈ X H Y ∧ Id ⁡ D ⁡ x ∈ x Hom ⁡ D x → 1 st ⁡ F Id ⁡ D ⁡ x = F
44 9 35 43 syl2an2r ⊢ φ ∧ x ∈ B → 1 st ⁡ F Id ⁡ D ⁡ x = F
45 30 42 44 3eqtrd ⊢ φ ∧ x ∈ B → F X x 2 nd ⁡ C 1 st F D Y x Id ⁡ D ⁡ x = F
46 45 mpteq2dva ⊢ φ → x ∈ B ⟼ F X x 2 nd ⁡ C 1 st F D Y x Id ⁡ D ⁡ x = x ∈ B ⟼ F
47 fconstmpt ⊢ B × F = x ∈ B ⟼ F
48 46 47 eqtr4di ⊢ φ → x ∈ B ⟼ F X x 2 nd ⁡ C 1 st F D Y x Id ⁡ D ⁡ x = B × F
49 13 20 48 3eqtrd ⊢ φ → X 2 nd ⁡ L Y ⁡ F = B × F