Metamath Proof Explorer


Theorem diaocN

Description: Value of partial isomorphism A at lattice orthocomplement (using a Sasaki projection to get orthocomplement relative to the fiducial co-atom W ). (Contributed by NM, 6-Dec-2013) (New usage is discouraged.)

Ref Expression
Hypotheses diaoc.j ⊢ ∨ ˙ = join ⁡ K
diaoc.m ⊢ ∧ ˙ = meet ⁡ K
diaoc.o ⊢ ⊥ ˙ = oc ⁡ K
diaoc.h ⊢ H = LHyp ⁡ K
diaoc.t ⊢ T = LTrn ⁡ K ⁡ W
diaoc.i ⊢ I = DIsoA ⁡ K ⁡ W
diaoc.n ⊢ N = ocA ⁡ K ⁡ W
Assertion diaocN ⊢ K ∈ HL ∧ W ∈ H ∧ X ∈ dom ⁡ I → I ⁡ ⊥ ˙ ⁡ X ∨ ˙ ⊥ ˙ ⁡ W ∧ ˙ W = N ⁡ I ⁡ X

Proof

Step Hyp Ref Expression
1 diaoc.j ⊢ ∨ ˙ = join ⁡ K
2 diaoc.m ⊢ ∧ ˙ = meet ⁡ K
3 diaoc.o ⊢ ⊥ ˙ = oc ⁡ K
4 diaoc.h ⊢ H = LHyp ⁡ K
5 diaoc.t ⊢ T = LTrn ⁡ K ⁡ W
6 diaoc.i ⊢ I = DIsoA ⁡ K ⁡ W
7 diaoc.n ⊢ N = ocA ⁡ K ⁡ W
8 simpl ⊢ K ∈ HL ∧ W ∈ H ∧ X ∈ dom ⁡ I → K ∈ HL ∧ W ∈ H
9 eqid ⊢ Base K = Base K
10 9 4 6 diadmclN ⊢ K ∈ HL ∧ W ∈ H ∧ X ∈ dom ⁡ I → X ∈ Base K
11 eqid ⊢ ≤ K = ≤ K
12 11 4 6 diadmleN ⊢ K ∈ HL ∧ W ∈ H ∧ X ∈ dom ⁡ I → X ≤ K W
13 9 11 4 5 6 diass ⊢ K ∈ HL ∧ W ∈ H ∧ X ∈ Base K ∧ X ≤ K W → I ⁡ X ⊆ T
14 8 10 12 13 syl12anc ⊢ K ∈ HL ∧ W ∈ H ∧ X ∈ dom ⁡ I → I ⁡ X ⊆ T
15 1 2 3 4 5 6 7 docavalN ⊢ K ∈ HL ∧ W ∈ H ∧ I ⁡ X ⊆ T → N ⁡ I ⁡ X = I ⁡ ⊥ ˙ ⁡ I -1 ⁡ ⋂ z ∈ ran ⁡ I | I ⁡ X ⊆ z ∨ ˙ ⊥ ˙ ⁡ W ∧ ˙ W
16 14 15 syldan ⊢ K ∈ HL ∧ W ∈ H ∧ X ∈ dom ⁡ I → N ⁡ I ⁡ X = I ⁡ ⊥ ˙ ⁡ I -1 ⁡ ⋂ z ∈ ran ⁡ I | I ⁡ X ⊆ z ∨ ˙ ⊥ ˙ ⁡ W ∧ ˙ W
17 4 6 diaclN ⊢ K ∈ HL ∧ W ∈ H ∧ X ∈ dom ⁡ I → I ⁡ X ∈ ran ⁡ I
18 intmin ⊢ I ⁡ X ∈ ran ⁡ I → ⋂ z ∈ ran ⁡ I | I ⁡ X ⊆ z = I ⁡ X
19 17 18 syl ⊢ K ∈ HL ∧ W ∈ H ∧ X ∈ dom ⁡ I → ⋂ z ∈ ran ⁡ I | I ⁡ X ⊆ z = I ⁡ X
20 19 fveq2d ⊢ K ∈ HL ∧ W ∈ H ∧ X ∈ dom ⁡ I → I -1 ⁡ ⋂ z ∈ ran ⁡ I | I ⁡ X ⊆ z = I -1 ⁡ I ⁡ X
21 4 6 diaf11N ⊢ K ∈ HL ∧ W ∈ H → I : dom ⁡ I ⟶ 1-1 onto ran ⁡ I
22 f1ocnvfv1 ⊢ I : dom ⁡ I ⟶ 1-1 onto ran ⁡ I ∧ X ∈ dom ⁡ I → I -1 ⁡ I ⁡ X = X
23 21 22 sylan ⊢ K ∈ HL ∧ W ∈ H ∧ X ∈ dom ⁡ I → I -1 ⁡ I ⁡ X = X
24 20 23 eqtrd ⊢ K ∈ HL ∧ W ∈ H ∧ X ∈ dom ⁡ I → I -1 ⁡ ⋂ z ∈ ran ⁡ I | I ⁡ X ⊆ z = X
25 24 fveq2d ⊢ K ∈ HL ∧ W ∈ H ∧ X ∈ dom ⁡ I → ⊥ ˙ ⁡ I -1 ⁡ ⋂ z ∈ ran ⁡ I | I ⁡ X ⊆ z = ⊥ ˙ ⁡ X
26 25 oveq1d ⊢ K ∈ HL ∧ W ∈ H ∧ X ∈ dom ⁡ I → ⊥ ˙ ⁡ I -1 ⁡ ⋂ z ∈ ran ⁡ I | I ⁡ X ⊆ z ∨ ˙ ⊥ ˙ ⁡ W = ⊥ ˙ ⁡ X ∨ ˙ ⊥ ˙ ⁡ W
27 26 fvoveq1d ⊢ K ∈ HL ∧ W ∈ H ∧ X ∈ dom ⁡ I → I ⁡ ⊥ ˙ ⁡ I -1 ⁡ ⋂ z ∈ ran ⁡ I | I ⁡ X ⊆ z ∨ ˙ ⊥ ˙ ⁡ W ∧ ˙ W = I ⁡ ⊥ ˙ ⁡ X ∨ ˙ ⊥ ˙ ⁡ W ∧ ˙ W
28 16 27 eqtr2d ⊢ K ∈ HL ∧ W ∈ H ∧ X ∈ dom ⁡ I → I ⁡ ⊥ ˙ ⁡ X ∨ ˙ ⊥ ˙ ⁡ W ∧ ˙ W = N ⁡ I ⁡ X