Metamath Proof Explorer


Theorem dibelval2nd

Description: Membership in value of the partial isomorphism B for a lattice K . (Contributed by NM, 13-Feb-2014)

Ref Expression
Hypotheses dibelval2nd.b ⊢ B = Base K
dibelval2nd.l ⊢ ≤ ˙ = ≤ K
dibelval2nd.h ⊢ H = LHyp ⁡ K
dibelval2nd.t ⊢ T = LTrn ⁡ K ⁡ W
dibelval2nd.o ⊢ 0 ˙ = f ∈ T ⟼ I ↾ B
dibelval2nd.i ⊢ I = DIsoB ⁡ K ⁡ W
Assertion dibelval2nd ⊢ K ∈ V ∧ W ∈ H ∧ X ∈ B ∧ X ≤ ˙ W ∧ Y ∈ I ⁡ X → 2 nd ⁡ Y = 0 ˙

Proof

Step Hyp Ref Expression
1 dibelval2nd.b ⊢ B = Base K
2 dibelval2nd.l ⊢ ≤ ˙ = ≤ K
3 dibelval2nd.h ⊢ H = LHyp ⁡ K
4 dibelval2nd.t ⊢ T = LTrn ⁡ K ⁡ W
5 dibelval2nd.o ⊢ 0 ˙ = f ∈ T ⟼ I ↾ B
6 dibelval2nd.i ⊢ I = DIsoB ⁡ K ⁡ W
7 eqid ⊢ DIsoA ⁡ K ⁡ W = DIsoA ⁡ K ⁡ W
8 1 2 3 4 5 7 6 dibval2 ⊢ K ∈ V ∧ W ∈ H ∧ X ∈ B ∧ X ≤ ˙ W → I ⁡ X = DIsoA ⁡ K ⁡ W ⁡ X × 0 ˙
9 8 eleq2d ⊢ K ∈ V ∧ W ∈ H ∧ X ∈ B ∧ X ≤ ˙ W → Y ∈ I ⁡ X ↔ Y ∈ DIsoA ⁡ K ⁡ W ⁡ X × 0 ˙
10 9 biimp3a ⊢ K ∈ V ∧ W ∈ H ∧ X ∈ B ∧ X ≤ ˙ W ∧ Y ∈ I ⁡ X → Y ∈ DIsoA ⁡ K ⁡ W ⁡ X × 0 ˙
11 xp2nd ⊢ Y ∈ DIsoA ⁡ K ⁡ W ⁡ X × 0 ˙ → 2 nd ⁡ Y ∈ 0 ˙
12 elsni ⊢ 2 nd ⁡ Y ∈ 0 ˙ → 2 nd ⁡ Y = 0 ˙
13 10 11 12 3syl ⊢ K ∈ V ∧ W ∈ H ∧ X ∈ B ∧ X ≤ ˙ W ∧ Y ∈ I ⁡ X → 2 nd ⁡ Y = 0 ˙