Metamath Proof Explorer


Theorem difun1

Description: A relationship involving double difference and union. (Contributed by NM, 29-Aug-2004)

Ref Expression
Assertion difun1 A B C = A B C

Proof

Step Hyp Ref Expression
1 inass A V B V C = A V B V C
2 invdif A V B V C = A V B C
3 1 2 eqtr3i A V B V C = A V B C
4 undm V B C = V B V C
5 4 ineq2i A V B C = A V B V C
6 invdif A V B C = A B C
7 5 6 eqtr3i A V B V C = A B C
8 3 7 eqtr3i A V B C = A B C
9 invdif A V B = A B
10 9 difeq1i A V B C = A B C
11 8 10 eqtr3i A B C = A B C