Metamath Proof Explorer


Theorem difxp1

Description: Difference law for Cartesian product. (Contributed by Scott Fenton, 18-Feb-2013) (Revised by Mario Carneiro, 26-Jun-2014)

Ref Expression
Assertion difxp1 A B × C = A × C B × C

Proof

Step Hyp Ref Expression
1 difxp A × C B × C = A B × C A × C C
2 difid C C =
3 2 xpeq2i A × C C = A ×
4 xp0 A × =
5 3 4 eqtri A × C C =
6 5 uneq2i A B × C A × C C = A B × C
7 un0 A B × C = A B × C
8 1 6 7 3eqtrri A B × C = A × C B × C