Metamath Proof Explorer


Theorem difxp1ss

Description: Difference law for Cartesian products. (Contributed by Thierry Arnoux, 24-Jul-2023)

Ref Expression
Assertion difxp1ss ⊢ A ∖ C × B ⊆ A × B

Proof

Step Hyp Ref Expression
1 difxp1 ⊢ A ∖ C × B = A × B ∖ C × B
2 difss ⊢ A × B ∖ C × B ⊆ A × B
3 1 2 eqsstri ⊢ A ∖ C × B ⊆ A × B