Metamath Proof Explorer


Theorem difxp2ss

Description: Difference law for Cartesian products. (Contributed by Thierry Arnoux, 24-Jul-2023)

Ref Expression
Assertion difxp2ss ⊢ A × B ∖ C ⊆ A × B

Proof

Step Hyp Ref Expression
1 difxp2 ⊢ A × B ∖ C = A × B ∖ A × C
2 difss ⊢ A × B ∖ A × C ⊆ A × B
3 1 2 eqsstri ⊢ A × B ∖ C ⊆ A × B