Metamath Proof Explorer


Theorem dihjat1

Description: Subspace sum of a closed subspace and an atom. ( pmapjat1 analog.) (Contributed by NM, 1-Oct-2014)

Ref Expression
Hypotheses dihjat1.h ⊢ H = LHyp ⁡ K
dihjat1.u ⊢ U = DVecH ⁡ K ⁡ W
dihjat1.v ⊢ V = Base U
dihjat1.p ⊢ ⊕ ˙ = LSSum ⁡ U
dihjat1.n ⊢ N = LSpan ⁡ U
dihjat1.i ⊢ I = DIsoH ⁡ K ⁡ W
dihjat1.j ⊢ ∨ ˙ = joinH ⁡ K ⁡ W
dihjat1.k ⊢ φ → K ∈ HL ∧ W ∈ H
dihjat1.x ⊢ φ → X ∈ ran ⁡ I
dihjat1.q ⊢ φ → T ∈ V
Assertion dihjat1 ⊢ φ → X ∨ ˙ N ⁡ T = X ⊕ ˙ N ⁡ T

Proof

Step Hyp Ref Expression
1 dihjat1.h ⊢ H = LHyp ⁡ K
2 dihjat1.u ⊢ U = DVecH ⁡ K ⁡ W
3 dihjat1.v ⊢ V = Base U
4 dihjat1.p ⊢ ⊕ ˙ = LSSum ⁡ U
5 dihjat1.n ⊢ N = LSpan ⁡ U
6 dihjat1.i ⊢ I = DIsoH ⁡ K ⁡ W
7 dihjat1.j ⊢ ∨ ˙ = joinH ⁡ K ⁡ W
8 dihjat1.k ⊢ φ → K ∈ HL ∧ W ∈ H
9 dihjat1.x ⊢ φ → X ∈ ran ⁡ I
10 dihjat1.q ⊢ φ → T ∈ V
11 sneq ⊢ T = 0 U → T = 0 U
12 11 fveq2d ⊢ T = 0 U → N ⁡ T = N ⁡ 0 U
13 1 2 8 dvhlmod ⊢ φ → U ∈ LMod
14 eqid ⊢ 0 U = 0 U
15 14 5 lspsn0 ⊢ U ∈ LMod → N ⁡ 0 U = 0 U
16 13 15 syl ⊢ φ → N ⁡ 0 U = 0 U
17 12 16 sylan9eqr ⊢ φ ∧ T = 0 U → N ⁡ T = 0 U
18 17 oveq2d ⊢ φ ∧ T = 0 U → X ∨ ˙ N ⁡ T = X ∨ ˙ 0 U
19 1 2 14 6 7 8 9 djh01 ⊢ φ → X ∨ ˙ 0 U = X
20 19 adantr ⊢ φ ∧ T = 0 U → X ∨ ˙ 0 U = X
21 17 oveq2d ⊢ φ ∧ T = 0 U → X ⊕ ˙ N ⁡ T = X ⊕ ˙ 0 U
22 eqid ⊢ LSubSp ⁡ U = LSubSp ⁡ U
23 1 2 6 22 dihrnlss ⊢ K ∈ HL ∧ W ∈ H ∧ X ∈ ran ⁡ I → X ∈ LSubSp ⁡ U
24 8 9 23 syl2anc ⊢ φ → X ∈ LSubSp ⁡ U
25 22 lsssubg ⊢ U ∈ LMod ∧ X ∈ LSubSp ⁡ U → X ∈ SubGrp ⁡ U
26 13 24 25 syl2anc ⊢ φ → X ∈ SubGrp ⁡ U
27 14 4 lsm01 ⊢ X ∈ SubGrp ⁡ U → X ⊕ ˙ 0 U = X
28 26 27 syl ⊢ φ → X ⊕ ˙ 0 U = X
29 28 adantr ⊢ φ ∧ T = 0 U → X ⊕ ˙ 0 U = X
30 21 29 eqtr2d ⊢ φ ∧ T = 0 U → X = X ⊕ ˙ N ⁡ T
31 18 20 30 3eqtrd ⊢ φ ∧ T = 0 U → X ∨ ˙ N ⁡ T = X ⊕ ˙ N ⁡ T
32 8 adantr ⊢ φ ∧ T ≠ 0 U → K ∈ HL ∧ W ∈ H
33 9 adantr ⊢ φ ∧ T ≠ 0 U → X ∈ ran ⁡ I
34 10 anim1i ⊢ φ ∧ T ≠ 0 U → T ∈ V ∧ T ≠ 0 U
35 eldifsn ⊢ T ∈ V ∖ 0 U ↔ T ∈ V ∧ T ≠ 0 U
36 34 35 sylibr ⊢ φ ∧ T ≠ 0 U → T ∈ V ∖ 0 U
37 1 2 3 4 5 6 7 32 33 14 36 dihjat1lem ⊢ φ ∧ T ≠ 0 U → X ∨ ˙ N ⁡ T = X ⊕ ˙ N ⁡ T
38 31 37 pm2.61dane ⊢ φ → X ∨ ˙ N ⁡ T = X ⊕ ˙ N ⁡ T