Metamath Proof Explorer


Theorem dirkertrigeqlem3

Description: Trigonometric equality lemma for the Dirichlet kernel trigonometric equality. Here we handle the case for an angle that's an odd multiple of _pi . (Contributed by Glauco Siliprandi, 11-Dec-2019)

Ref Expression
Hypotheses dirkertrigeqlem3.n ⊢ φ → N ∈ ℕ
dirkertrigeqlem3.k ⊢ φ → K ∈ ℤ
dirkertrigeqlem3.a ⊢ A = 2 ⁢ K + 1 ⁢ π
Assertion dirkertrigeqlem3 ⊢ φ → 1 2 + ∑ n = 1 N cos ⁡ n ⁢ A π = sin ⁡ N + 1 2 ⁢ A 2 ⁢ π ⁢ sin ⁡ A 2

Proof

Step Hyp Ref Expression
1 dirkertrigeqlem3.n ⊢ φ → N ∈ ℕ
2 dirkertrigeqlem3.k ⊢ φ → K ∈ ℤ
3 dirkertrigeqlem3.a ⊢ A = 2 ⁢ K + 1 ⁢ π
4 3 a1i ⊢ φ ∧ n ∈ 1 … N → A = 2 ⁢ K + 1 ⁢ π
5 4 oveq2d ⊢ φ ∧ n ∈ 1 … N → n ⁢ A = n ⁢ 2 ⁢ K + 1 ⁢ π
6 elfzelz ⊢ n ∈ 1 … N → n ∈ ℤ
7 6 zcnd ⊢ n ∈ 1 … N → n ∈ ℂ
8 7 adantl ⊢ φ ∧ n ∈ 1 … N → n ∈ ℂ
9 2cnd ⊢ φ ∧ n ∈ 1 … N → 2 ∈ ℂ
10 2 zcnd ⊢ φ → K ∈ ℂ
11 10 adantr ⊢ φ ∧ n ∈ 1 … N → K ∈ ℂ
12 9 11 mulcld ⊢ φ ∧ n ∈ 1 … N → 2 ⁢ K ∈ ℂ
13 1cnd ⊢ φ ∧ n ∈ 1 … N → 1 ∈ ℂ
14 12 13 addcld ⊢ φ ∧ n ∈ 1 … N → 2 ⁢ K + 1 ∈ ℂ
15 picn ⊢ π ∈ ℂ
16 15 a1i ⊢ φ ∧ n ∈ 1 … N → π ∈ ℂ
17 14 16 mulcld ⊢ φ ∧ n ∈ 1 … N → 2 ⁢ K + 1 ⁢ π ∈ ℂ
18 8 17 mulcomd ⊢ φ ∧ n ∈ 1 … N → n ⁢ 2 ⁢ K + 1 ⁢ π = 2 ⁢ K + 1 ⁢ π ⁢ n
19 14 16 8 mulassd ⊢ φ ∧ n ∈ 1 … N → 2 ⁢ K + 1 ⁢ π ⁢ n = 2 ⁢ K + 1 ⁢ π ⁢ n
20 16 8 mulcld ⊢ φ ∧ n ∈ 1 … N → π ⁢ n ∈ ℂ
21 12 13 20 adddird ⊢ φ ∧ n ∈ 1 … N → 2 ⁢ K + 1 ⁢ π ⁢ n = 2 ⁢ K ⁢ π ⁢ n + 1 ⁢ π ⁢ n
22 12 20 mulcld ⊢ φ ∧ n ∈ 1 … N → 2 ⁢ K ⁢ π ⁢ n ∈ ℂ
23 13 20 mulcld ⊢ φ ∧ n ∈ 1 … N → 1 ⁢ π ⁢ n ∈ ℂ
24 22 23 addcomd ⊢ φ ∧ n ∈ 1 … N → 2 ⁢ K ⁢ π ⁢ n + 1 ⁢ π ⁢ n = 1 ⁢ π ⁢ n + 2 ⁢ K ⁢ π ⁢ n
25 15 a1i ⊢ n ∈ 1 … N → π ∈ ℂ
26 25 7 mulcld ⊢ n ∈ 1 … N → π ⁢ n ∈ ℂ
27 26 mullidd ⊢ n ∈ 1 … N → 1 ⁢ π ⁢ n = π ⁢ n
28 27 adantl ⊢ φ ∧ n ∈ 1 … N → 1 ⁢ π ⁢ n = π ⁢ n
29 9 11 16 8 mul4d ⊢ φ ∧ n ∈ 1 … N → 2 ⁢ K ⁢ π ⁢ n = 2 ⁢ π ⁢ K ⁢ n
30 9 16 mulcld ⊢ φ ∧ n ∈ 1 … N → 2 ⁢ π ∈ ℂ
31 11 8 mulcld ⊢ φ ∧ n ∈ 1 … N → K ⁢ n ∈ ℂ
32 30 31 mulcomd ⊢ φ ∧ n ∈ 1 … N → 2 ⁢ π ⁢ K ⁢ n = K ⁢ n ⁢ 2 ⁢ π
33 29 32 eqtrd ⊢ φ ∧ n ∈ 1 … N → 2 ⁢ K ⁢ π ⁢ n = K ⁢ n ⁢ 2 ⁢ π
34 28 33 oveq12d ⊢ φ ∧ n ∈ 1 … N → 1 ⁢ π ⁢ n + 2 ⁢ K ⁢ π ⁢ n = π ⁢ n + K ⁢ n ⁢ 2 ⁢ π
35 24 34 eqtrd ⊢ φ ∧ n ∈ 1 … N → 2 ⁢ K ⁢ π ⁢ n + 1 ⁢ π ⁢ n = π ⁢ n + K ⁢ n ⁢ 2 ⁢ π
36 19 21 35 3eqtrd ⊢ φ ∧ n ∈ 1 … N → 2 ⁢ K + 1 ⁢ π ⁢ n = π ⁢ n + K ⁢ n ⁢ 2 ⁢ π
37 5 18 36 3eqtrd ⊢ φ ∧ n ∈ 1 … N → n ⁢ A = π ⁢ n + K ⁢ n ⁢ 2 ⁢ π
38 37 fveq2d ⊢ φ ∧ n ∈ 1 … N → cos ⁡ n ⁢ A = cos ⁡ π ⁢ n + K ⁢ n ⁢ 2 ⁢ π
39 2 adantr ⊢ φ ∧ n ∈ 1 … N → K ∈ ℤ
40 6 adantl ⊢ φ ∧ n ∈ 1 … N → n ∈ ℤ
41 39 40 zmulcld ⊢ φ ∧ n ∈ 1 … N → K ⁢ n ∈ ℤ
42 cosper ⊢ π ⁢ n ∈ ℂ ∧ K ⁢ n ∈ ℤ → cos ⁡ π ⁢ n + K ⁢ n ⁢ 2 ⁢ π = cos ⁡ π ⁢ n
43 20 41 42 syl2anc ⊢ φ ∧ n ∈ 1 … N → cos ⁡ π ⁢ n + K ⁢ n ⁢ 2 ⁢ π = cos ⁡ π ⁢ n
44 38 43 eqtrd ⊢ φ ∧ n ∈ 1 … N → cos ⁡ n ⁢ A = cos ⁡ π ⁢ n
45 44 sumeq2dv ⊢ φ → ∑ n = 1 N cos ⁡ n ⁢ A = ∑ n = 1 N cos ⁡ π ⁢ n
46 45 oveq2d ⊢ φ → 1 2 + ∑ n = 1 N cos ⁡ n ⁢ A = 1 2 + ∑ n = 1 N cos ⁡ π ⁢ n
47 46 oveq1d ⊢ φ → 1 2 + ∑ n = 1 N cos ⁡ n ⁢ A π = 1 2 + ∑ n = 1 N cos ⁡ π ⁢ n π
48 47 adantr ⊢ φ ∧ N mod 2 = 0 → 1 2 + ∑ n = 1 N cos ⁡ n ⁢ A π = 1 2 + ∑ n = 1 N cos ⁡ π ⁢ n π
49 1 nncnd ⊢ φ → N ∈ ℂ
50 2cnd ⊢ φ → 2 ∈ ℂ
51 2ne0 ⊢ 2 ≠ 0
52 51 a1i ⊢ φ → 2 ≠ 0
53 49 50 52 divcan2d ⊢ φ → 2 ⁢ N 2 = N
54 53 eqcomd ⊢ φ → N = 2 ⁢ N 2
55 54 oveq2d ⊢ φ → 1 … N = 1 … 2 ⁢ N 2
56 55 sumeq1d ⊢ φ → ∑ n = 1 N cos ⁡ π ⁢ n = ∑ n = 1 2 ⁢ N 2 cos ⁡ π ⁢ n
57 56 adantr ⊢ φ ∧ N mod 2 = 0 → ∑ n = 1 N cos ⁡ π ⁢ n = ∑ n = 1 2 ⁢ N 2 cos ⁡ π ⁢ n
58 15 a1i ⊢ n ∈ 1 … 2 ⁢ N 2 → π ∈ ℂ
59 elfzelz ⊢ n ∈ 1 … 2 ⁢ N 2 → n ∈ ℤ
60 59 zcnd ⊢ n ∈ 1 … 2 ⁢ N 2 → n ∈ ℂ
61 58 60 mulcomd ⊢ n ∈ 1 … 2 ⁢ N 2 → π ⁢ n = n ⁢ π
62 61 fveq2d ⊢ n ∈ 1 … 2 ⁢ N 2 → cos ⁡ π ⁢ n = cos ⁡ n ⁢ π
63 62 rgen ⊢ ∀ n ∈ 1 … 2 ⁢ N 2 cos ⁡ π ⁢ n = cos ⁡ n ⁢ π
64 63 a1i ⊢ φ ∧ N mod 2 = 0 → ∀ n ∈ 1 … 2 ⁢ N 2 cos ⁡ π ⁢ n = cos ⁡ n ⁢ π
65 64 sumeq2d ⊢ φ ∧ N mod 2 = 0 → ∑ n = 1 2 ⁢ N 2 cos ⁡ π ⁢ n = ∑ n = 1 2 ⁢ N 2 cos ⁡ n ⁢ π
66 simpr ⊢ φ ∧ N mod 2 = 0 → N mod 2 = 0
67 1 nnred ⊢ φ → N ∈ ℝ
68 67 adantr ⊢ φ ∧ N mod 2 = 0 → N ∈ ℝ
69 2rp ⊢ 2 ∈ ℝ +
70 mod0 ⊢ N ∈ ℝ ∧ 2 ∈ ℝ + → N mod 2 = 0 ↔ N 2 ∈ ℤ
71 68 69 70 sylancl ⊢ φ ∧ N mod 2 = 0 → N mod 2 = 0 ↔ N 2 ∈ ℤ
72 66 71 mpbid ⊢ φ ∧ N mod 2 = 0 → N 2 ∈ ℤ
73 2re ⊢ 2 ∈ ℝ
74 73 a1i ⊢ φ → 2 ∈ ℝ
75 1 nngt0d ⊢ φ → 0 < N
76 2pos ⊢ 0 < 2
77 76 a1i ⊢ φ → 0 < 2
78 67 74 75 77 divgt0d ⊢ φ → 0 < N 2
79 78 adantr ⊢ φ ∧ N mod 2 = 0 → 0 < N 2
80 elnnz ⊢ N 2 ∈ ℕ ↔ N 2 ∈ ℤ ∧ 0 < N 2
81 72 79 80 sylanbrc ⊢ φ ∧ N mod 2 = 0 → N 2 ∈ ℕ
82 dirkertrigeqlem1 ⊢ N 2 ∈ ℕ → ∑ n = 1 2 ⁢ N 2 cos ⁡ n ⁢ π = 0
83 81 82 syl ⊢ φ ∧ N mod 2 = 0 → ∑ n = 1 2 ⁢ N 2 cos ⁡ n ⁢ π = 0
84 57 65 83 3eqtrd ⊢ φ ∧ N mod 2 = 0 → ∑ n = 1 N cos ⁡ π ⁢ n = 0
85 84 oveq2d ⊢ φ ∧ N mod 2 = 0 → 1 2 + ∑ n = 1 N cos ⁡ π ⁢ n = 1 2 + 0
86 halfcn ⊢ 1 2 ∈ ℂ
87 86 addridi ⊢ 1 2 + 0 = 1 2
88 85 87 eqtrdi ⊢ φ ∧ N mod 2 = 0 → 1 2 + ∑ n = 1 N cos ⁡ π ⁢ n = 1 2
89 88 oveq1d ⊢ φ ∧ N mod 2 = 0 → 1 2 + ∑ n = 1 N cos ⁡ π ⁢ n π = 1 2 π
90 ax-1cn ⊢ 1 ∈ ℂ
91 2cnne0 ⊢ 2 ∈ ℂ ∧ 2 ≠ 0
92 pire ⊢ π ∈ ℝ
93 pipos ⊢ 0 < π
94 92 93 gt0ne0ii ⊢ π ≠ 0
95 15 94 pm3.2i ⊢ π ∈ ℂ ∧ π ≠ 0
96 divdiv1 ⊢ 1 ∈ ℂ ∧ 2 ∈ ℂ ∧ 2 ≠ 0 ∧ π ∈ ℂ ∧ π ≠ 0 → 1 2 π = 1 2 ⁢ π
97 90 91 95 96 mp3an ⊢ 1 2 π = 1 2 ⁢ π
98 97 a1i ⊢ φ ∧ N mod 2 = 0 → 1 2 π = 1 2 ⁢ π
99 48 89 98 3eqtrd ⊢ φ ∧ N mod 2 = 0 → 1 2 + ∑ n = 1 N cos ⁡ n ⁢ A π = 1 2 ⁢ π
100 3 oveq2i ⊢ N + 1 2 ⁢ A = N + 1 2 ⁢ 2 ⁢ K + 1 ⁢ π
101 100 a1i ⊢ φ → N + 1 2 ⁢ A = N + 1 2 ⁢ 2 ⁢ K + 1 ⁢ π
102 86 a1i ⊢ φ → 1 2 ∈ ℂ
103 49 102 addcld ⊢ φ → N + 1 2 ∈ ℂ
104 50 10 mulcld ⊢ φ → 2 ⁢ K ∈ ℂ
105 peano2cn ⊢ 2 ⁢ K ∈ ℂ → 2 ⁢ K + 1 ∈ ℂ
106 104 105 syl ⊢ φ → 2 ⁢ K + 1 ∈ ℂ
107 15 a1i ⊢ φ → π ∈ ℂ
108 103 106 107 mulassd ⊢ φ → N + 1 2 ⁢ 2 ⁢ K + 1 ⁢ π = N + 1 2 ⁢ 2 ⁢ K + 1 ⁢ π
109 1cnd ⊢ φ → 1 ∈ ℂ
110 49 102 104 109 muladdd ⊢ φ → N + 1 2 ⁢ 2 ⁢ K + 1 = N ⁢ 2 ⁢ K + 1 ⁢ 1 2 + N ⋅ 1 + 2 ⁢ K ⁢ 1 2
111 49 50 10 mul12d ⊢ φ → N ⁢ 2 ⁢ K = 2 ⁢ N ⁢ K
112 102 mullidd ⊢ φ → 1 ⁢ 1 2 = 1 2
113 111 112 oveq12d ⊢ φ → N ⁢ 2 ⁢ K + 1 ⁢ 1 2 = 2 ⁢ N ⁢ K + 1 2
114 49 mulridd ⊢ φ → N ⋅ 1 = N
115 50 10 mulcomd ⊢ φ → 2 ⁢ K = K ⋅ 2
116 115 oveq1d ⊢ φ → 2 ⁢ K ⁢ 1 2 = K ⋅ 2 ⁢ 1 2
117 10 50 102 mulassd ⊢ φ → K ⋅ 2 ⁢ 1 2 = K ⁢ 2 ⁢ 1 2
118 2thalfe1 ⊢ 2 ⁢ 1 2 = 1
119 118 oveq2i ⊢ K ⁢ 2 ⁢ 1 2 = K ⋅ 1
120 10 mulridd ⊢ φ → K ⋅ 1 = K
121 119 120 eqtrid ⊢ φ → K ⁢ 2 ⁢ 1 2 = K
122 116 117 121 3eqtrd ⊢ φ → 2 ⁢ K ⁢ 1 2 = K
123 114 122 oveq12d ⊢ φ → N ⋅ 1 + 2 ⁢ K ⁢ 1 2 = N + K
124 113 123 oveq12d ⊢ φ → N ⁢ 2 ⁢ K + 1 ⁢ 1 2 + N ⋅ 1 + 2 ⁢ K ⁢ 1 2 = 2 ⁢ N ⁢ K + 1 2 + N + K
125 49 10 mulcld ⊢ φ → N ⁢ K ∈ ℂ
126 50 125 mulcld ⊢ φ → 2 ⁢ N ⁢ K ∈ ℂ
127 49 10 addcld ⊢ φ → N + K ∈ ℂ
128 126 102 127 addassd ⊢ φ → 2 ⁢ N ⁢ K + 1 2 + N + K = 2 ⁢ N ⁢ K + 1 2 + N + K
129 110 124 128 3eqtrd ⊢ φ → N + 1 2 ⁢ 2 ⁢ K + 1 = 2 ⁢ N ⁢ K + 1 2 + N + K
130 102 127 addcld ⊢ φ → 1 2 + N + K ∈ ℂ
131 126 130 addcomd ⊢ φ → 2 ⁢ N ⁢ K + 1 2 + N + K = 1 2 + N + K + 2 ⁢ N ⁢ K
132 50 125 mulcomd ⊢ φ → 2 ⁢ N ⁢ K = N ⁢ K ⋅ 2
133 132 oveq2d ⊢ φ → 1 2 + N + K + 2 ⁢ N ⁢ K = 1 2 + N + K + N ⁢ K ⋅ 2
134 129 131 133 3eqtrd ⊢ φ → N + 1 2 ⁢ 2 ⁢ K + 1 = 1 2 + N + K + N ⁢ K ⋅ 2
135 134 oveq1d ⊢ φ → N + 1 2 ⁢ 2 ⁢ K + 1 ⁢ π = 1 2 + N + K + N ⁢ K ⋅ 2 ⁢ π
136 125 50 mulcld ⊢ φ → N ⁢ K ⋅ 2 ∈ ℂ
137 130 136 107 adddird ⊢ φ → 1 2 + N + K + N ⁢ K ⋅ 2 ⁢ π = 1 2 + N + K ⁢ π + N ⁢ K ⋅ 2 ⁢ π
138 125 50 107 mulassd ⊢ φ → N ⁢ K ⋅ 2 ⁢ π = N ⁢ K ⁢ 2 ⁢ π
139 138 oveq2d ⊢ φ → 1 2 + N + K ⁢ π + N ⁢ K ⋅ 2 ⁢ π = 1 2 + N + K ⁢ π + N ⁢ K ⁢ 2 ⁢ π
140 135 137 139 3eqtrd ⊢ φ → N + 1 2 ⁢ 2 ⁢ K + 1 ⁢ π = 1 2 + N + K ⁢ π + N ⁢ K ⁢ 2 ⁢ π
141 101 108 140 3eqtr2d ⊢ φ → N + 1 2 ⁢ A = 1 2 + N + K ⁢ π + N ⁢ K ⁢ 2 ⁢ π
142 141 fveq2d ⊢ φ → sin ⁡ N + 1 2 ⁢ A = sin ⁡ 1 2 + N + K ⁢ π + N ⁢ K ⁢ 2 ⁢ π
143 130 107 mulcld ⊢ φ → 1 2 + N + K ⁢ π ∈ ℂ
144 1 nnzd ⊢ φ → N ∈ ℤ
145 144 2 zmulcld ⊢ φ → N ⁢ K ∈ ℤ
146 sinper ⊢ 1 2 + N + K ⁢ π ∈ ℂ ∧ N ⁢ K ∈ ℤ → sin ⁡ 1 2 + N + K ⁢ π + N ⁢ K ⁢ 2 ⁢ π = sin ⁡ 1 2 + N + K ⁢ π
147 143 145 146 syl2anc ⊢ φ → sin ⁡ 1 2 + N + K ⁢ π + N ⁢ K ⁢ 2 ⁢ π = sin ⁡ 1 2 + N + K ⁢ π
148 102 127 addcomd ⊢ φ → 1 2 + N + K = N + K + 1 2
149 49 10 102 addassd ⊢ φ → N + K + 1 2 = N + K + 1 2
150 10 102 addcld ⊢ φ → K + 1 2 ∈ ℂ
151 49 150 addcomd ⊢ φ → N + K + 1 2 = K + 1 2 + N
152 148 149 151 3eqtrd ⊢ φ → 1 2 + N + K = K + 1 2 + N
153 152 oveq1d ⊢ φ → 1 2 + N + K ⁢ π = K + 1 2 + N ⁢ π
154 153 fveq2d ⊢ φ → sin ⁡ 1 2 + N + K ⁢ π = sin ⁡ K + 1 2 + N ⁢ π
155 142 147 154 3eqtrd ⊢ φ → sin ⁡ N + 1 2 ⁢ A = sin ⁡ K + 1 2 + N ⁢ π
156 3 a1i ⊢ φ → A = 2 ⁢ K + 1 ⁢ π
157 156 oveq1d ⊢ φ → A 2 = 2 ⁢ K + 1 ⁢ π 2
158 106 107 50 52 div23d ⊢ φ → 2 ⁢ K + 1 ⁢ π 2 = 2 ⁢ K + 1 2 ⁢ π
159 104 109 50 52 divdird ⊢ φ → 2 ⁢ K + 1 2 = 2 ⁢ K 2 + 1 2
160 10 50 52 divcan3d ⊢ φ → 2 ⁢ K 2 = K
161 160 oveq1d ⊢ φ → 2 ⁢ K 2 + 1 2 = K + 1 2
162 159 161 eqtrd ⊢ φ → 2 ⁢ K + 1 2 = K + 1 2
163 162 oveq1d ⊢ φ → 2 ⁢ K + 1 2 ⁢ π = K + 1 2 ⁢ π
164 157 158 163 3eqtrd ⊢ φ → A 2 = K + 1 2 ⁢ π
165 164 fveq2d ⊢ φ → sin ⁡ A 2 = sin ⁡ K + 1 2 ⁢ π
166 165 oveq2d ⊢ φ → 2 ⁢ π ⁢ sin ⁡ A 2 = 2 ⁢ π ⁢ sin ⁡ K + 1 2 ⁢ π
167 155 166 oveq12d ⊢ φ → sin ⁡ N + 1 2 ⁢ A 2 ⁢ π ⁢ sin ⁡ A 2 = sin ⁡ K + 1 2 + N ⁢ π 2 ⁢ π ⁢ sin ⁡ K + 1 2 ⁢ π
168 167 adantr ⊢ φ ∧ N mod 2 = 0 → sin ⁡ N + 1 2 ⁢ A 2 ⁢ π ⁢ sin ⁡ A 2 = sin ⁡ K + 1 2 + N ⁢ π 2 ⁢ π ⁢ sin ⁡ K + 1 2 ⁢ π
169 150 49 107 adddird ⊢ φ → K + 1 2 + N ⁢ π = K + 1 2 ⁢ π + N ⁢ π
170 169 fveq2d ⊢ φ → sin ⁡ K + 1 2 + N ⁢ π = sin ⁡ K + 1 2 ⁢ π + N ⁢ π
171 170 oveq1d ⊢ φ → sin ⁡ K + 1 2 + N ⁢ π 2 ⁢ π ⁢ sin ⁡ K + 1 2 ⁢ π = sin ⁡ K + 1 2 ⁢ π + N ⁢ π 2 ⁢ π ⁢ sin ⁡ K + 1 2 ⁢ π
172 171 adantr ⊢ φ ∧ N mod 2 = 0 → sin ⁡ K + 1 2 + N ⁢ π 2 ⁢ π ⁢ sin ⁡ K + 1 2 ⁢ π = sin ⁡ K + 1 2 ⁢ π + N ⁢ π 2 ⁢ π ⁢ sin ⁡ K + 1 2 ⁢ π
173 49 halfcld ⊢ φ → N 2 ∈ ℂ
174 50 173 mulcomd ⊢ φ → 2 ⁢ N 2 = N 2 ⋅ 2
175 53 174 eqtr3d ⊢ φ → N = N 2 ⋅ 2
176 175 oveq1d ⊢ φ → N ⁢ π = N 2 ⋅ 2 ⁢ π
177 173 50 107 mulassd ⊢ φ → N 2 ⋅ 2 ⁢ π = N 2 ⁢ 2 ⁢ π
178 176 177 eqtrd ⊢ φ → N ⁢ π = N 2 ⁢ 2 ⁢ π
179 178 oveq2d ⊢ φ → K + 1 2 ⁢ π + N ⁢ π = K + 1 2 ⁢ π + N 2 ⁢ 2 ⁢ π
180 179 fveq2d ⊢ φ → sin ⁡ K + 1 2 ⁢ π + N ⁢ π = sin ⁡ K + 1 2 ⁢ π + N 2 ⁢ 2 ⁢ π
181 180 adantr ⊢ φ ∧ N mod 2 = 0 → sin ⁡ K + 1 2 ⁢ π + N ⁢ π = sin ⁡ K + 1 2 ⁢ π + N 2 ⁢ 2 ⁢ π
182 10 adantr ⊢ φ ∧ N mod 2 = 0 → K ∈ ℂ
183 1cnd ⊢ φ ∧ N mod 2 = 0 → 1 ∈ ℂ
184 183 halfcld ⊢ φ ∧ N mod 2 = 0 → 1 2 ∈ ℂ
185 182 184 addcld ⊢ φ ∧ N mod 2 = 0 → K + 1 2 ∈ ℂ
186 15 a1i ⊢ φ ∧ N mod 2 = 0 → π ∈ ℂ
187 185 186 mulcld ⊢ φ ∧ N mod 2 = 0 → K + 1 2 ⁢ π ∈ ℂ
188 sinper ⊢ K + 1 2 ⁢ π ∈ ℂ ∧ N 2 ∈ ℤ → sin ⁡ K + 1 2 ⁢ π + N 2 ⁢ 2 ⁢ π = sin ⁡ K + 1 2 ⁢ π
189 187 72 188 syl2anc ⊢ φ ∧ N mod 2 = 0 → sin ⁡ K + 1 2 ⁢ π + N 2 ⁢ 2 ⁢ π = sin ⁡ K + 1 2 ⁢ π
190 181 189 eqtrd ⊢ φ ∧ N mod 2 = 0 → sin ⁡ K + 1 2 ⁢ π + N ⁢ π = sin ⁡ K + 1 2 ⁢ π
191 50 107 mulcld ⊢ φ → 2 ⁢ π ∈ ℂ
192 150 107 mulcld ⊢ φ → K + 1 2 ⁢ π ∈ ℂ
193 192 sincld ⊢ φ → sin ⁡ K + 1 2 ⁢ π ∈ ℂ
194 191 193 mulcomd ⊢ φ → 2 ⁢ π ⁢ sin ⁡ K + 1 2 ⁢ π = sin ⁡ K + 1 2 ⁢ π ⁢ 2 ⁢ π
195 194 adantr ⊢ φ ∧ N mod 2 = 0 → 2 ⁢ π ⁢ sin ⁡ K + 1 2 ⁢ π = sin ⁡ K + 1 2 ⁢ π ⁢ 2 ⁢ π
196 190 195 oveq12d ⊢ φ ∧ N mod 2 = 0 → sin ⁡ K + 1 2 ⁢ π + N ⁢ π 2 ⁢ π ⁢ sin ⁡ K + 1 2 ⁢ π = sin ⁡ K + 1 2 ⁢ π sin ⁡ K + 1 2 ⁢ π ⁢ 2 ⁢ π
197 94 a1i ⊢ φ → π ≠ 0
198 150 107 197 divcan4d ⊢ φ → K + 1 2 ⁢ π π = K + 1 2
199 2 zred ⊢ φ → K ∈ ℝ
200 69 a1i ⊢ φ → 2 ∈ ℝ +
201 200 rpreccld ⊢ φ → 1 2 ∈ ℝ +
202 199 201 ltaddrpd ⊢ φ → K < K + 1 2
203 1red ⊢ φ → 1 ∈ ℝ
204 203 rehalfcld ⊢ φ → 1 2 ∈ ℝ
205 halflt1 ⊢ 1 2 < 1
206 205 a1i ⊢ φ → 1 2 < 1
207 204 203 199 206 ltadd2dd ⊢ φ → K + 1 2 < K + 1
208 btwnnz ⊢ K ∈ ℤ ∧ K < K + 1 2 ∧ K + 1 2 < K + 1 → ¬ K + 1 2 ∈ ℤ
209 2 202 207 208 syl3anc ⊢ φ → ¬ K + 1 2 ∈ ℤ
210 198 209 eqneltrd ⊢ φ → ¬ K + 1 2 ⁢ π π ∈ ℤ
211 sineq0 ⊢ K + 1 2 ⁢ π ∈ ℂ → sin ⁡ K + 1 2 ⁢ π = 0 ↔ K + 1 2 ⁢ π π ∈ ℤ
212 192 211 syl ⊢ φ → sin ⁡ K + 1 2 ⁢ π = 0 ↔ K + 1 2 ⁢ π π ∈ ℤ
213 210 212 mtbird ⊢ φ → ¬ sin ⁡ K + 1 2 ⁢ π = 0
214 213 neqned ⊢ φ → sin ⁡ K + 1 2 ⁢ π ≠ 0
215 50 107 52 197 mulne0d ⊢ φ → 2 ⁢ π ≠ 0
216 193 193 191 214 215 divdiv1d ⊢ φ → sin ⁡ K + 1 2 ⁢ π sin ⁡ K + 1 2 ⁢ π 2 ⁢ π = sin ⁡ K + 1 2 ⁢ π sin ⁡ K + 1 2 ⁢ π ⁢ 2 ⁢ π
217 193 214 dividd ⊢ φ → sin ⁡ K + 1 2 ⁢ π sin ⁡ K + 1 2 ⁢ π = 1
218 217 oveq1d ⊢ φ → sin ⁡ K + 1 2 ⁢ π sin ⁡ K + 1 2 ⁢ π 2 ⁢ π = 1 2 ⁢ π
219 216 218 eqtr3d ⊢ φ → sin ⁡ K + 1 2 ⁢ π sin ⁡ K + 1 2 ⁢ π ⁢ 2 ⁢ π = 1 2 ⁢ π
220 219 adantr ⊢ φ ∧ N mod 2 = 0 → sin ⁡ K + 1 2 ⁢ π sin ⁡ K + 1 2 ⁢ π ⁢ 2 ⁢ π = 1 2 ⁢ π
221 196 220 eqtrd ⊢ φ ∧ N mod 2 = 0 → sin ⁡ K + 1 2 ⁢ π + N ⁢ π 2 ⁢ π ⁢ sin ⁡ K + 1 2 ⁢ π = 1 2 ⁢ π
222 168 172 221 3eqtrrd ⊢ φ ∧ N mod 2 = 0 → 1 2 ⁢ π = sin ⁡ N + 1 2 ⁢ A 2 ⁢ π ⁢ sin ⁡ A 2
223 99 222 eqtrd ⊢ φ ∧ N mod 2 = 0 → 1 2 + ∑ n = 1 N cos ⁡ n ⁢ A π = sin ⁡ N + 1 2 ⁢ A 2 ⁢ π ⁢ sin ⁡ A 2
224 47 adantr ⊢ φ ∧ ¬ N mod 2 = 0 → 1 2 + ∑ n = 1 N cos ⁡ n ⁢ A π = 1 2 + ∑ n = 1 N cos ⁡ π ⁢ n π
225 144 adantr ⊢ φ ∧ ¬ N mod 2 = 0 → N ∈ ℤ
226 simpr ⊢ φ ∧ ¬ N mod 2 = 0 → ¬ N mod 2 = 0
227 226 neqned ⊢ φ ∧ ¬ N mod 2 = 0 → N mod 2 ≠ 0
228 oddfl ⊢ N ∈ ℤ ∧ N mod 2 ≠ 0 → N = 2 ⁢ N 2 + 1
229 225 227 228 syl2anc ⊢ φ ∧ ¬ N mod 2 = 0 → N = 2 ⁢ N 2 + 1
230 229 oveq2d ⊢ φ ∧ ¬ N mod 2 = 0 → 1 … N = 1 … 2 ⁢ N 2 + 1
231 230 sumeq1d ⊢ φ ∧ ¬ N mod 2 = 0 → ∑ n = 1 N cos ⁡ π ⁢ n = ∑ n = 1 2 ⁢ N 2 + 1 cos ⁡ π ⁢ n
232 fvoveq1 ⊢ N = 1 → N 2 = 1 2
233 halffl ⊢ 1 2 = 0
234 232 233 eqtrdi ⊢ N = 1 → N 2 = 0
235 234 oveq2d ⊢ N = 1 → 2 ⁢ N 2 = 2 ⋅ 0
236 2t0e0 ⊢ 2 ⋅ 0 = 0
237 235 236 eqtrdi ⊢ N = 1 → 2 ⁢ N 2 = 0
238 237 oveq1d ⊢ N = 1 → 2 ⁢ N 2 + 1 = 0 + 1
239 90 addlidi ⊢ 0 + 1 = 1
240 238 239 eqtrdi ⊢ N = 1 → 2 ⁢ N 2 + 1 = 1
241 240 oveq2d ⊢ N = 1 → 1 … 2 ⁢ N 2 + 1 = 1 … 1
242 241 sumeq1d ⊢ N = 1 → ∑ n = 1 2 ⁢ N 2 + 1 cos ⁡ π ⁢ n = ∑ n = 1 1 cos ⁡ π ⁢ n
243 1z ⊢ 1 ∈ ℤ
244 coscl ⊢ π ∈ ℂ → cos ⁡ π ∈ ℂ
245 15 244 ax-mp ⊢ cos ⁡ π ∈ ℂ
246 oveq2 ⊢ n = 1 → π ⁢ n = π ⋅ 1
247 15 mulridi ⊢ π ⋅ 1 = π
248 246 247 eqtrdi ⊢ n = 1 → π ⁢ n = π
249 248 fveq2d ⊢ n = 1 → cos ⁡ π ⁢ n = cos ⁡ π
250 249 fsum1 ⊢ 1 ∈ ℤ ∧ cos ⁡ π ∈ ℂ → ∑ n = 1 1 cos ⁡ π ⁢ n = cos ⁡ π
251 243 245 250 mp2an ⊢ ∑ n = 1 1 cos ⁡ π ⁢ n = cos ⁡ π
252 251 a1i ⊢ N = 1 → ∑ n = 1 1 cos ⁡ π ⁢ n = cos ⁡ π
253 cospi ⊢ cos ⁡ π = − 1
254 253 a1i ⊢ N = 1 → cos ⁡ π = − 1
255 242 252 254 3eqtrd ⊢ N = 1 → ∑ n = 1 2 ⁢ N 2 + 1 cos ⁡ π ⁢ n = − 1
256 255 adantl ⊢ φ ∧ N = 1 → ∑ n = 1 2 ⁢ N 2 + 1 cos ⁡ π ⁢ n = − 1
257 2nn ⊢ 2 ∈ ℕ
258 257 a1i ⊢ φ ∧ ¬ N = 1 → 2 ∈ ℕ
259 67 rehalfcld ⊢ φ → N 2 ∈ ℝ
260 259 flcld ⊢ φ → N 2 ∈ ℤ
261 260 adantr ⊢ φ ∧ ¬ N = 1 → N 2 ∈ ℤ
262 2div2e1 ⊢ 2 2 = 1
263 73 a1i ⊢ φ ∧ ¬ N = 1 → 2 ∈ ℝ
264 67 adantr ⊢ φ ∧ ¬ N = 1 → N ∈ ℝ
265 69 a1i ⊢ φ ∧ ¬ N = 1 → 2 ∈ ℝ +
266 neqne ⊢ ¬ N = 1 → N ≠ 1
267 nnne1ge2 ⊢ N ∈ ℕ ∧ N ≠ 1 → 2 ≤ N
268 1 266 267 syl2an ⊢ φ ∧ ¬ N = 1 → 2 ≤ N
269 263 264 265 268 lediv1dd ⊢ φ ∧ ¬ N = 1 → 2 2 ≤ N 2
270 262 269 eqbrtrrid ⊢ φ ∧ ¬ N = 1 → 1 ≤ N 2
271 259 adantr ⊢ φ ∧ ¬ N = 1 → N 2 ∈ ℝ
272 flge ⊢ N 2 ∈ ℝ ∧ 1 ∈ ℤ → 1 ≤ N 2 ↔ 1 ≤ N 2
273 271 243 272 sylancl ⊢ φ ∧ ¬ N = 1 → 1 ≤ N 2 ↔ 1 ≤ N 2
274 270 273 mpbid ⊢ φ ∧ ¬ N = 1 → 1 ≤ N 2
275 elnnz1 ⊢ N 2 ∈ ℕ ↔ N 2 ∈ ℤ ∧ 1 ≤ N 2
276 261 274 275 sylanbrc ⊢ φ ∧ ¬ N = 1 → N 2 ∈ ℕ
277 258 276 nnmulcld ⊢ φ ∧ ¬ N = 1 → 2 ⁢ N 2 ∈ ℕ
278 nnuz ⊢ ℕ = ℤ ≥ 1
279 277 278 eleqtrdi ⊢ φ ∧ ¬ N = 1 → 2 ⁢ N 2 ∈ ℤ ≥ 1
280 15 a1i ⊢ φ ∧ ¬ N = 1 ∧ n ∈ 1 … 2 ⁢ N 2 + 1 → π ∈ ℂ
281 elfzelz ⊢ n ∈ 1 … 2 ⁢ N 2 + 1 → n ∈ ℤ
282 281 zcnd ⊢ n ∈ 1 … 2 ⁢ N 2 + 1 → n ∈ ℂ
283 282 adantl ⊢ φ ∧ ¬ N = 1 ∧ n ∈ 1 … 2 ⁢ N 2 + 1 → n ∈ ℂ
284 280 283 mulcld ⊢ φ ∧ ¬ N = 1 ∧ n ∈ 1 … 2 ⁢ N 2 + 1 → π ⁢ n ∈ ℂ
285 284 coscld ⊢ φ ∧ ¬ N = 1 ∧ n ∈ 1 … 2 ⁢ N 2 + 1 → cos ⁡ π ⁢ n ∈ ℂ
286 oveq2 ⊢ n = 2 ⁢ N 2 + 1 → π ⁢ n = π ⁢ 2 ⁢ N 2 + 1
287 286 fveq2d ⊢ n = 2 ⁢ N 2 + 1 → cos ⁡ π ⁢ n = cos ⁡ π ⁢ 2 ⁢ N 2 + 1
288 279 285 287 fsump1 ⊢ φ ∧ ¬ N = 1 → ∑ n = 1 2 ⁢ N 2 + 1 cos ⁡ π ⁢ n = ∑ n = 1 2 ⁢ N 2 cos ⁡ π ⁢ n + cos ⁡ π ⁢ 2 ⁢ N 2 + 1
289 15 a1i ⊢ n ∈ 1 … 2 ⁢ N 2 → π ∈ ℂ
290 elfzelz ⊢ n ∈ 1 … 2 ⁢ N 2 → n ∈ ℤ
291 290 zcnd ⊢ n ∈ 1 … 2 ⁢ N 2 → n ∈ ℂ
292 289 291 mulcomd ⊢ n ∈ 1 … 2 ⁢ N 2 → π ⁢ n = n ⁢ π
293 292 fveq2d ⊢ n ∈ 1 … 2 ⁢ N 2 → cos ⁡ π ⁢ n = cos ⁡ n ⁢ π
294 293 sumeq2i ⊢ ∑ n = 1 2 ⁢ N 2 cos ⁡ π ⁢ n = ∑ n = 1 2 ⁢ N 2 cos ⁡ n ⁢ π
295 dirkertrigeqlem1 ⊢ N 2 ∈ ℕ → ∑ n = 1 2 ⁢ N 2 cos ⁡ n ⁢ π = 0
296 276 295 syl ⊢ φ ∧ ¬ N = 1 → ∑ n = 1 2 ⁢ N 2 cos ⁡ n ⁢ π = 0
297 294 296 eqtrid ⊢ φ ∧ ¬ N = 1 → ∑ n = 1 2 ⁢ N 2 cos ⁡ π ⁢ n = 0
298 260 zcnd ⊢ φ → N 2 ∈ ℂ
299 50 298 mulcld ⊢ φ → 2 ⁢ N 2 ∈ ℂ
300 107 299 109 adddid ⊢ φ → π ⁢ 2 ⁢ N 2 + 1 = π ⁢ 2 ⁢ N 2 + π ⋅ 1
301 107 50 298 mul13d ⊢ φ → π ⁢ 2 ⁢ N 2 = N 2 ⁢ 2 ⁢ π
302 247 a1i ⊢ φ → π ⋅ 1 = π
303 301 302 oveq12d ⊢ φ → π ⁢ 2 ⁢ N 2 + π ⋅ 1 = N 2 ⁢ 2 ⁢ π + π
304 298 191 mulcld ⊢ φ → N 2 ⁢ 2 ⁢ π ∈ ℂ
305 304 107 addcomd ⊢ φ → N 2 ⁢ 2 ⁢ π + π = π + N 2 ⁢ 2 ⁢ π
306 300 303 305 3eqtrd ⊢ φ → π ⁢ 2 ⁢ N 2 + 1 = π + N 2 ⁢ 2 ⁢ π
307 306 fveq2d ⊢ φ → cos ⁡ π ⁢ 2 ⁢ N 2 + 1 = cos ⁡ π + N 2 ⁢ 2 ⁢ π
308 cosper ⊢ π ∈ ℂ ∧ N 2 ∈ ℤ → cos ⁡ π + N 2 ⁢ 2 ⁢ π = cos ⁡ π
309 107 260 308 syl2anc ⊢ φ → cos ⁡ π + N 2 ⁢ 2 ⁢ π = cos ⁡ π
310 253 a1i ⊢ φ → cos ⁡ π = − 1
311 307 309 310 3eqtrd ⊢ φ → cos ⁡ π ⁢ 2 ⁢ N 2 + 1 = − 1
312 311 adantr ⊢ φ ∧ ¬ N = 1 → cos ⁡ π ⁢ 2 ⁢ N 2 + 1 = − 1
313 297 312 oveq12d ⊢ φ ∧ ¬ N = 1 → ∑ n = 1 2 ⁢ N 2 cos ⁡ π ⁢ n + cos ⁡ π ⁢ 2 ⁢ N 2 + 1 = 0 + -1
314 neg1cn ⊢ − 1 ∈ ℂ
315 314 addlidi ⊢ 0 + -1 = − 1
316 315 a1i ⊢ φ ∧ ¬ N = 1 → 0 + -1 = − 1
317 288 313 316 3eqtrd ⊢ φ ∧ ¬ N = 1 → ∑ n = 1 2 ⁢ N 2 + 1 cos ⁡ π ⁢ n = − 1
318 256 317 pm2.61dan ⊢ φ → ∑ n = 1 2 ⁢ N 2 + 1 cos ⁡ π ⁢ n = − 1
319 318 adantr ⊢ φ ∧ ¬ N mod 2 = 0 → ∑ n = 1 2 ⁢ N 2 + 1 cos ⁡ π ⁢ n = − 1
320 231 319 eqtrd ⊢ φ ∧ ¬ N mod 2 = 0 → ∑ n = 1 N cos ⁡ π ⁢ n = − 1
321 320 oveq2d ⊢ φ ∧ ¬ N mod 2 = 0 → 1 2 + ∑ n = 1 N cos ⁡ π ⁢ n = 1 2 + -1
322 321 oveq1d ⊢ φ ∧ ¬ N mod 2 = 0 → 1 2 + ∑ n = 1 N cos ⁡ π ⁢ n π = 1 2 + -1 π
323 167 171 eqtrd ⊢ φ → sin ⁡ N + 1 2 ⁢ A 2 ⁢ π ⁢ sin ⁡ A 2 = sin ⁡ K + 1 2 ⁢ π + N ⁢ π 2 ⁢ π ⁢ sin ⁡ K + 1 2 ⁢ π
324 323 adantr ⊢ φ ∧ ¬ N mod 2 = 0 → sin ⁡ N + 1 2 ⁢ A 2 ⁢ π ⁢ sin ⁡ A 2 = sin ⁡ K + 1 2 ⁢ π + N ⁢ π 2 ⁢ π ⁢ sin ⁡ K + 1 2 ⁢ π
325 229 oveq1d ⊢ φ ∧ ¬ N mod 2 = 0 → N ⁢ π = 2 ⁢ N 2 + 1 ⁢ π
326 299 109 107 adddird ⊢ φ → 2 ⁢ N 2 + 1 ⁢ π = 2 ⁢ N 2 ⁢ π + 1 ⁢ π
327 107 mullidd ⊢ φ → 1 ⁢ π = π
328 327 oveq2d ⊢ φ → 2 ⁢ N 2 ⁢ π + 1 ⁢ π = 2 ⁢ N 2 ⁢ π + π
329 299 107 mulcld ⊢ φ → 2 ⁢ N 2 ⁢ π ∈ ℂ
330 329 107 addcomd ⊢ φ → 2 ⁢ N 2 ⁢ π + π = π + 2 ⁢ N 2 ⁢ π
331 326 328 330 3eqtrd ⊢ φ → 2 ⁢ N 2 + 1 ⁢ π = π + 2 ⁢ N 2 ⁢ π
332 331 adantr ⊢ φ ∧ ¬ N mod 2 = 0 → 2 ⁢ N 2 + 1 ⁢ π = π + 2 ⁢ N 2 ⁢ π
333 50 298 mulcomd ⊢ φ → 2 ⁢ N 2 = N 2 ⋅ 2
334 333 oveq1d ⊢ φ → 2 ⁢ N 2 ⁢ π = N 2 ⋅ 2 ⁢ π
335 298 50 107 mulassd ⊢ φ → N 2 ⋅ 2 ⁢ π = N 2 ⁢ 2 ⁢ π
336 334 335 eqtrd ⊢ φ → 2 ⁢ N 2 ⁢ π = N 2 ⁢ 2 ⁢ π
337 336 oveq2d ⊢ φ → π + 2 ⁢ N 2 ⁢ π = π + N 2 ⁢ 2 ⁢ π
338 337 adantr ⊢ φ ∧ ¬ N mod 2 = 0 → π + 2 ⁢ N 2 ⁢ π = π + N 2 ⁢ 2 ⁢ π
339 325 332 338 3eqtrd ⊢ φ ∧ ¬ N mod 2 = 0 → N ⁢ π = π + N 2 ⁢ 2 ⁢ π
340 339 oveq2d ⊢ φ ∧ ¬ N mod 2 = 0 → K + 1 2 ⁢ π + N ⁢ π = K + 1 2 ⁢ π + π + N 2 ⁢ 2 ⁢ π
341 192 adantr ⊢ φ ∧ ¬ N mod 2 = 0 → K + 1 2 ⁢ π ∈ ℂ
342 15 a1i ⊢ φ ∧ ¬ N mod 2 = 0 → π ∈ ℂ
343 304 adantr ⊢ φ ∧ ¬ N mod 2 = 0 → N 2 ⁢ 2 ⁢ π ∈ ℂ
344 341 342 343 addassd ⊢ φ ∧ ¬ N mod 2 = 0 → K + 1 2 ⁢ π + π + N 2 ⁢ 2 ⁢ π = K + 1 2 ⁢ π + π + N 2 ⁢ 2 ⁢ π
345 340 344 eqtr4d ⊢ φ ∧ ¬ N mod 2 = 0 → K + 1 2 ⁢ π + N ⁢ π = K + 1 2 ⁢ π + π + N 2 ⁢ 2 ⁢ π
346 345 fveq2d ⊢ φ ∧ ¬ N mod 2 = 0 → sin ⁡ K + 1 2 ⁢ π + N ⁢ π = sin ⁡ K + 1 2 ⁢ π + π + N 2 ⁢ 2 ⁢ π
347 346 oveq1d ⊢ φ ∧ ¬ N mod 2 = 0 → sin ⁡ K + 1 2 ⁢ π + N ⁢ π 2 ⁢ π ⁢ sin ⁡ K + 1 2 ⁢ π = sin ⁡ K + 1 2 ⁢ π + π + N 2 ⁢ 2 ⁢ π 2 ⁢ π ⁢ sin ⁡ K + 1 2 ⁢ π
348 192 107 addcld ⊢ φ → K + 1 2 ⁢ π + π ∈ ℂ
349 sinper ⊢ K + 1 2 ⁢ π + π ∈ ℂ ∧ N 2 ∈ ℤ → sin ⁡ K + 1 2 ⁢ π + π + N 2 ⁢ 2 ⁢ π = sin ⁡ K + 1 2 ⁢ π + π
350 348 260 349 syl2anc ⊢ φ → sin ⁡ K + 1 2 ⁢ π + π + N 2 ⁢ 2 ⁢ π = sin ⁡ K + 1 2 ⁢ π + π
351 sinppi ⊢ K + 1 2 ⁢ π ∈ ℂ → sin ⁡ K + 1 2 ⁢ π + π = − sin ⁡ K + 1 2 ⁢ π
352 192 351 syl ⊢ φ → sin ⁡ K + 1 2 ⁢ π + π = − sin ⁡ K + 1 2 ⁢ π
353 350 352 eqtrd ⊢ φ → sin ⁡ K + 1 2 ⁢ π + π + N 2 ⁢ 2 ⁢ π = − sin ⁡ K + 1 2 ⁢ π
354 353 oveq1d ⊢ φ → sin ⁡ K + 1 2 ⁢ π + π + N 2 ⁢ 2 ⁢ π 2 ⁢ π ⁢ sin ⁡ K + 1 2 ⁢ π = − sin ⁡ K + 1 2 ⁢ π 2 ⁢ π ⁢ sin ⁡ K + 1 2 ⁢ π
355 194 oveq2d ⊢ φ → − sin ⁡ K + 1 2 ⁢ π 2 ⁢ π ⁢ sin ⁡ K + 1 2 ⁢ π = − sin ⁡ K + 1 2 ⁢ π sin ⁡ K + 1 2 ⁢ π ⁢ 2 ⁢ π
356 193 193 214 divnegd ⊢ φ → − sin ⁡ K + 1 2 ⁢ π sin ⁡ K + 1 2 ⁢ π = − sin ⁡ K + 1 2 ⁢ π sin ⁡ K + 1 2 ⁢ π
357 217 negeqd ⊢ φ → − sin ⁡ K + 1 2 ⁢ π sin ⁡ K + 1 2 ⁢ π = − 1
358 356 357 eqtr3d ⊢ φ → − sin ⁡ K + 1 2 ⁢ π sin ⁡ K + 1 2 ⁢ π = − 1
359 358 oveq1d ⊢ φ → − sin ⁡ K + 1 2 ⁢ π sin ⁡ K + 1 2 ⁢ π 2 ⁢ π = − 1 2 ⁢ π
360 193 negcld ⊢ φ → − sin ⁡ K + 1 2 ⁢ π ∈ ℂ
361 360 193 191 214 215 divdiv1d ⊢ φ → − sin ⁡ K + 1 2 ⁢ π sin ⁡ K + 1 2 ⁢ π 2 ⁢ π = − sin ⁡ K + 1 2 ⁢ π sin ⁡ K + 1 2 ⁢ π ⁢ 2 ⁢ π
362 86 90 negsubi ⊢ 1 2 + -1 = 1 2 − 1
363 90 86 negsubdi2i ⊢ − 1 − 1 2 = 1 2 − 1
364 1mhlfehlf ⊢ 1 − 1 2 = 1 2
365 364 negeqi ⊢ − 1 − 1 2 = − 1 2
366 2cn ⊢ 2 ∈ ℂ
367 divneg ⊢ 1 ∈ ℂ ∧ 2 ∈ ℂ ∧ 2 ≠ 0 → − 1 2 = − 1 2
368 90 366 51 367 mp3an ⊢ − 1 2 = − 1 2
369 365 368 eqtri ⊢ − 1 − 1 2 = − 1 2
370 362 363 369 3eqtr2i ⊢ 1 2 + -1 = − 1 2
371 370 oveq1i ⊢ 1 2 + -1 π = − 1 2 π
372 divdiv1 ⊢ − 1 ∈ ℂ ∧ 2 ∈ ℂ ∧ 2 ≠ 0 ∧ π ∈ ℂ ∧ π ≠ 0 → − 1 2 π = − 1 2 ⁢ π
373 314 91 95 372 mp3an ⊢ − 1 2 π = − 1 2 ⁢ π
374 371 373 eqtr2i ⊢ − 1 2 ⁢ π = 1 2 + -1 π
375 374 a1i ⊢ φ → − 1 2 ⁢ π = 1 2 + -1 π
376 359 361 375 3eqtr3d ⊢ φ → − sin ⁡ K + 1 2 ⁢ π sin ⁡ K + 1 2 ⁢ π ⁢ 2 ⁢ π = 1 2 + -1 π
377 354 355 376 3eqtrd ⊢ φ → sin ⁡ K + 1 2 ⁢ π + π + N 2 ⁢ 2 ⁢ π 2 ⁢ π ⁢ sin ⁡ K + 1 2 ⁢ π = 1 2 + -1 π
378 377 adantr ⊢ φ ∧ ¬ N mod 2 = 0 → sin ⁡ K + 1 2 ⁢ π + π + N 2 ⁢ 2 ⁢ π 2 ⁢ π ⁢ sin ⁡ K + 1 2 ⁢ π = 1 2 + -1 π
379 324 347 378 3eqtrrd ⊢ φ ∧ ¬ N mod 2 = 0 → 1 2 + -1 π = sin ⁡ N + 1 2 ⁢ A 2 ⁢ π ⁢ sin ⁡ A 2
380 224 322 379 3eqtrd ⊢ φ ∧ ¬ N mod 2 = 0 → 1 2 + ∑ n = 1 N cos ⁡ n ⁢ A π = sin ⁡ N + 1 2 ⁢ A 2 ⁢ π ⁢ sin ⁡ A 2
381 223 380 pm2.61dan ⊢ φ → 1 2 + ∑ n = 1 N cos ⁡ n ⁢ A π = sin ⁡ N + 1 2 ⁢ A 2 ⁢ π ⁢ sin ⁡ A 2