Metamath Proof Explorer


Theorem disjin

Description: If a collection is disjoint, so is the collection of the intersections with a given set. (Contributed by Thierry Arnoux, 14-Feb-2017)

Ref Expression
Assertion disjin ⊢ Disj x ∈ B C → Disj x ∈ B C ∩ A

Proof

Step Hyp Ref Expression
1 elinel1 ⊢ y ∈ C ∩ A → y ∈ C
2 1 rmoimi ⊢ ∃* x ∈ B y ∈ C → ∃* x ∈ B y ∈ C ∩ A
3 2 alimi ⊢ ∀ y ∃* x ∈ B y ∈ C → ∀ y ∃* x ∈ B y ∈ C ∩ A
4 df-disj ⊢ Disj x ∈ B C ↔ ∀ y ∃* x ∈ B y ∈ C
5 df-disj ⊢ Disj x ∈ B C ∩ A ↔ ∀ y ∃* x ∈ B y ∈ C ∩ A
6 3 4 5 3imtr4i ⊢ Disj x ∈ B C → Disj x ∈ B C ∩ A