Metamath Proof Explorer


Theorem disjin2

Description: If a collection is disjoint, so is the collection of the intersections with a given set. (Contributed by Thierry Arnoux, 21-Jun-2020)

Ref Expression
Assertion disjin2 ⊢ Disj x ∈ B C → Disj x ∈ B A ∩ C

Proof

Step Hyp Ref Expression
1 elinel2 ⊢ y ∈ A ∩ C → y ∈ C
2 1 rmoimi ⊢ ∃* x ∈ B y ∈ C → ∃* x ∈ B y ∈ A ∩ C
3 2 alimi ⊢ ∀ y ∃* x ∈ B y ∈ C → ∀ y ∃* x ∈ B y ∈ A ∩ C
4 df-disj ⊢ Disj x ∈ B C ↔ ∀ y ∃* x ∈ B y ∈ C
5 df-disj ⊢ Disj x ∈ B A ∩ C ↔ ∀ y ∃* x ∈ B y ∈ A ∩ C
6 3 4 5 3imtr4i ⊢ Disj x ∈ B C → Disj x ∈ B A ∩ C