Metamath Proof Explorer


Theorem disjxpin

Description: Derive a disjunction over a Cartesian product from the disjunctions over its first and second elements. (Contributed by Thierry Arnoux, 9-Mar-2018)

Ref Expression
Hypotheses disjxpin.1 ⊢ x = 1 st ⁡ p → C = E
disjxpin.2 ⊢ y = 2 nd ⁡ p → D = F
disjxpin.3 ⊢ φ → Disj x ∈ A C
disjxpin.4 ⊢ φ → Disj y ∈ B D
Assertion disjxpin ⊢ φ → Disj p ∈ A × B E ∩ F

Proof

Step Hyp Ref Expression
1 disjxpin.1 ⊢ x = 1 st ⁡ p → C = E
2 disjxpin.2 ⊢ y = 2 nd ⁡ p → D = F
3 disjxpin.3 ⊢ φ → Disj x ∈ A C
4 disjxpin.4 ⊢ φ → Disj y ∈ B D
5 xp1st ⊢ q ∈ A × B → 1 st ⁡ q ∈ A
6 5 ad2antrl ⊢ φ ∧ q ∈ A × B ∧ r ∈ A × B → 1 st ⁡ q ∈ A
7 xp1st ⊢ r ∈ A × B → 1 st ⁡ r ∈ A
8 7 ad2antll ⊢ φ ∧ q ∈ A × B ∧ r ∈ A × B → 1 st ⁡ r ∈ A
9 simpl ⊢ φ ∧ q ∈ A × B ∧ r ∈ A × B → φ
10 disjors ⊢ Disj x ∈ A C ↔ ∀ a ∈ A ∀ c ∈ A a = c ∨ ⦋ a / x⦌ C ∩ ⦋ c / x⦌ C = ∅
11 3 10 sylib ⊢ φ → ∀ a ∈ A ∀ c ∈ A a = c ∨ ⦋ a / x⦌ C ∩ ⦋ c / x⦌ C = ∅
12 eqeq1 ⊢ a = 1 st ⁡ q → a = c ↔ 1 st ⁡ q = c
13 csbeq1 ⊢ a = 1 st ⁡ q → ⦋ a / x⦌ C = ⦋ 1 st ⁡ q / x⦌ C
14 13 ineq1d ⊢ a = 1 st ⁡ q → ⦋ a / x⦌ C ∩ ⦋ c / x⦌ C = ⦋ 1 st ⁡ q / x⦌ C ∩ ⦋ c / x⦌ C
15 14 eqeq1d ⊢ a = 1 st ⁡ q → ⦋ a / x⦌ C ∩ ⦋ c / x⦌ C = ∅ ↔ ⦋ 1 st ⁡ q / x⦌ C ∩ ⦋ c / x⦌ C = ∅
16 12 15 orbi12d ⊢ a = 1 st ⁡ q → a = c ∨ ⦋ a / x⦌ C ∩ ⦋ c / x⦌ C = ∅ ↔ 1 st ⁡ q = c ∨ ⦋ 1 st ⁡ q / x⦌ C ∩ ⦋ c / x⦌ C = ∅
17 eqeq2 ⊢ c = 1 st ⁡ r → 1 st ⁡ q = c ↔ 1 st ⁡ q = 1 st ⁡ r
18 csbeq1 ⊢ c = 1 st ⁡ r → ⦋ c / x⦌ C = ⦋ 1 st ⁡ r / x⦌ C
19 18 ineq2d ⊢ c = 1 st ⁡ r → ⦋ 1 st ⁡ q / x⦌ C ∩ ⦋ c / x⦌ C = ⦋ 1 st ⁡ q / x⦌ C ∩ ⦋ 1 st ⁡ r / x⦌ C
20 19 eqeq1d ⊢ c = 1 st ⁡ r → ⦋ 1 st ⁡ q / x⦌ C ∩ ⦋ c / x⦌ C = ∅ ↔ ⦋ 1 st ⁡ q / x⦌ C ∩ ⦋ 1 st ⁡ r / x⦌ C = ∅
21 17 20 orbi12d ⊢ c = 1 st ⁡ r → 1 st ⁡ q = c ∨ ⦋ 1 st ⁡ q / x⦌ C ∩ ⦋ c / x⦌ C = ∅ ↔ 1 st ⁡ q = 1 st ⁡ r ∨ ⦋ 1 st ⁡ q / x⦌ C ∩ ⦋ 1 st ⁡ r / x⦌ C = ∅
22 16 21 rspc2v ⊢ 1 st ⁡ q ∈ A ∧ 1 st ⁡ r ∈ A → ∀ a ∈ A ∀ c ∈ A a = c ∨ ⦋ a / x⦌ C ∩ ⦋ c / x⦌ C = ∅ → 1 st ⁡ q = 1 st ⁡ r ∨ ⦋ 1 st ⁡ q / x⦌ C ∩ ⦋ 1 st ⁡ r / x⦌ C = ∅
23 11 22 syl5 ⊢ 1 st ⁡ q ∈ A ∧ 1 st ⁡ r ∈ A → φ → 1 st ⁡ q = 1 st ⁡ r ∨ ⦋ 1 st ⁡ q / x⦌ C ∩ ⦋ 1 st ⁡ r / x⦌ C = ∅
24 23 imp ⊢ 1 st ⁡ q ∈ A ∧ 1 st ⁡ r ∈ A ∧ φ → 1 st ⁡ q = 1 st ⁡ r ∨ ⦋ 1 st ⁡ q / x⦌ C ∩ ⦋ 1 st ⁡ r / x⦌ C = ∅
25 6 8 9 24 syl21anc ⊢ φ ∧ q ∈ A × B ∧ r ∈ A × B → 1 st ⁡ q = 1 st ⁡ r ∨ ⦋ 1 st ⁡ q / x⦌ C ∩ ⦋ 1 st ⁡ r / x⦌ C = ∅
26 xp2nd ⊢ q ∈ A × B → 2 nd ⁡ q ∈ B
27 26 ad2antrl ⊢ φ ∧ q ∈ A × B ∧ r ∈ A × B → 2 nd ⁡ q ∈ B
28 xp2nd ⊢ r ∈ A × B → 2 nd ⁡ r ∈ B
29 28 ad2antll ⊢ φ ∧ q ∈ A × B ∧ r ∈ A × B → 2 nd ⁡ r ∈ B
30 disjors ⊢ Disj y ∈ B D ↔ ∀ b ∈ B ∀ d ∈ B b = d ∨ ⦋ b / y⦌ D ∩ ⦋ d / y⦌ D = ∅
31 4 30 sylib ⊢ φ → ∀ b ∈ B ∀ d ∈ B b = d ∨ ⦋ b / y⦌ D ∩ ⦋ d / y⦌ D = ∅
32 eqeq1 ⊢ b = 2 nd ⁡ q → b = d ↔ 2 nd ⁡ q = d
33 csbeq1 ⊢ b = 2 nd ⁡ q → ⦋ b / y⦌ D = ⦋ 2 nd ⁡ q / y⦌ D
34 33 ineq1d ⊢ b = 2 nd ⁡ q → ⦋ b / y⦌ D ∩ ⦋ d / y⦌ D = ⦋ 2 nd ⁡ q / y⦌ D ∩ ⦋ d / y⦌ D
35 34 eqeq1d ⊢ b = 2 nd ⁡ q → ⦋ b / y⦌ D ∩ ⦋ d / y⦌ D = ∅ ↔ ⦋ 2 nd ⁡ q / y⦌ D ∩ ⦋ d / y⦌ D = ∅
36 32 35 orbi12d ⊢ b = 2 nd ⁡ q → b = d ∨ ⦋ b / y⦌ D ∩ ⦋ d / y⦌ D = ∅ ↔ 2 nd ⁡ q = d ∨ ⦋ 2 nd ⁡ q / y⦌ D ∩ ⦋ d / y⦌ D = ∅
37 eqeq2 ⊢ d = 2 nd ⁡ r → 2 nd ⁡ q = d ↔ 2 nd ⁡ q = 2 nd ⁡ r
38 csbeq1 ⊢ d = 2 nd ⁡ r → ⦋ d / y⦌ D = ⦋ 2 nd ⁡ r / y⦌ D
39 38 ineq2d ⊢ d = 2 nd ⁡ r → ⦋ 2 nd ⁡ q / y⦌ D ∩ ⦋ d / y⦌ D = ⦋ 2 nd ⁡ q / y⦌ D ∩ ⦋ 2 nd ⁡ r / y⦌ D
40 39 eqeq1d ⊢ d = 2 nd ⁡ r → ⦋ 2 nd ⁡ q / y⦌ D ∩ ⦋ d / y⦌ D = ∅ ↔ ⦋ 2 nd ⁡ q / y⦌ D ∩ ⦋ 2 nd ⁡ r / y⦌ D = ∅
41 37 40 orbi12d ⊢ d = 2 nd ⁡ r → 2 nd ⁡ q = d ∨ ⦋ 2 nd ⁡ q / y⦌ D ∩ ⦋ d / y⦌ D = ∅ ↔ 2 nd ⁡ q = 2 nd ⁡ r ∨ ⦋ 2 nd ⁡ q / y⦌ D ∩ ⦋ 2 nd ⁡ r / y⦌ D = ∅
42 36 41 rspc2v ⊢ 2 nd ⁡ q ∈ B ∧ 2 nd ⁡ r ∈ B → ∀ b ∈ B ∀ d ∈ B b = d ∨ ⦋ b / y⦌ D ∩ ⦋ d / y⦌ D = ∅ → 2 nd ⁡ q = 2 nd ⁡ r ∨ ⦋ 2 nd ⁡ q / y⦌ D ∩ ⦋ 2 nd ⁡ r / y⦌ D = ∅
43 31 42 syl5 ⊢ 2 nd ⁡ q ∈ B ∧ 2 nd ⁡ r ∈ B → φ → 2 nd ⁡ q = 2 nd ⁡ r ∨ ⦋ 2 nd ⁡ q / y⦌ D ∩ ⦋ 2 nd ⁡ r / y⦌ D = ∅
44 43 imp ⊢ 2 nd ⁡ q ∈ B ∧ 2 nd ⁡ r ∈ B ∧ φ → 2 nd ⁡ q = 2 nd ⁡ r ∨ ⦋ 2 nd ⁡ q / y⦌ D ∩ ⦋ 2 nd ⁡ r / y⦌ D = ∅
45 27 29 9 44 syl21anc ⊢ φ ∧ q ∈ A × B ∧ r ∈ A × B → 2 nd ⁡ q = 2 nd ⁡ r ∨ ⦋ 2 nd ⁡ q / y⦌ D ∩ ⦋ 2 nd ⁡ r / y⦌ D = ∅
46 25 45 jca ⊢ φ ∧ q ∈ A × B ∧ r ∈ A × B → 1 st ⁡ q = 1 st ⁡ r ∨ ⦋ 1 st ⁡ q / x⦌ C ∩ ⦋ 1 st ⁡ r / x⦌ C = ∅ ∧ 2 nd ⁡ q = 2 nd ⁡ r ∨ ⦋ 2 nd ⁡ q / y⦌ D ∩ ⦋ 2 nd ⁡ r / y⦌ D = ∅
47 anddi ⊢ 1 st ⁡ q = 1 st ⁡ r ∨ ⦋ 1 st ⁡ q / x⦌ C ∩ ⦋ 1 st ⁡ r / x⦌ C = ∅ ∧ 2 nd ⁡ q = 2 nd ⁡ r ∨ ⦋ 2 nd ⁡ q / y⦌ D ∩ ⦋ 2 nd ⁡ r / y⦌ D = ∅ ↔ 1 st ⁡ q = 1 st ⁡ r ∧ 2 nd ⁡ q = 2 nd ⁡ r ∨ 1 st ⁡ q = 1 st ⁡ r ∧ ⦋ 2 nd ⁡ q / y⦌ D ∩ ⦋ 2 nd ⁡ r / y⦌ D = ∅ ∨ ⦋ 1 st ⁡ q / x⦌ C ∩ ⦋ 1 st ⁡ r / x⦌ C = ∅ ∧ 2 nd ⁡ q = 2 nd ⁡ r ∨ ⦋ 1 st ⁡ q / x⦌ C ∩ ⦋ 1 st ⁡ r / x⦌ C = ∅ ∧ ⦋ 2 nd ⁡ q / y⦌ D ∩ ⦋ 2 nd ⁡ r / y⦌ D = ∅
48 46 47 sylib ⊢ φ ∧ q ∈ A × B ∧ r ∈ A × B → 1 st ⁡ q = 1 st ⁡ r ∧ 2 nd ⁡ q = 2 nd ⁡ r ∨ 1 st ⁡ q = 1 st ⁡ r ∧ ⦋ 2 nd ⁡ q / y⦌ D ∩ ⦋ 2 nd ⁡ r / y⦌ D = ∅ ∨ ⦋ 1 st ⁡ q / x⦌ C ∩ ⦋ 1 st ⁡ r / x⦌ C = ∅ ∧ 2 nd ⁡ q = 2 nd ⁡ r ∨ ⦋ 1 st ⁡ q / x⦌ C ∩ ⦋ 1 st ⁡ r / x⦌ C = ∅ ∧ ⦋ 2 nd ⁡ q / y⦌ D ∩ ⦋ 2 nd ⁡ r / y⦌ D = ∅
49 orass ⊢ 1 st ⁡ q = 1 st ⁡ r ∧ 2 nd ⁡ q = 2 nd ⁡ r ∨ 1 st ⁡ q = 1 st ⁡ r ∧ ⦋ 2 nd ⁡ q / y⦌ D ∩ ⦋ 2 nd ⁡ r / y⦌ D = ∅ ∨ ⦋ 1 st ⁡ q / x⦌ C ∩ ⦋ 1 st ⁡ r / x⦌ C = ∅ ∧ 2 nd ⁡ q = 2 nd ⁡ r ∨ ⦋ 1 st ⁡ q / x⦌ C ∩ ⦋ 1 st ⁡ r / x⦌ C = ∅ ∧ ⦋ 2 nd ⁡ q / y⦌ D ∩ ⦋ 2 nd ⁡ r / y⦌ D = ∅ ↔ 1 st ⁡ q = 1 st ⁡ r ∧ 2 nd ⁡ q = 2 nd ⁡ r ∨ 1 st ⁡ q = 1 st ⁡ r ∧ ⦋ 2 nd ⁡ q / y⦌ D ∩ ⦋ 2 nd ⁡ r / y⦌ D = ∅ ∨ ⦋ 1 st ⁡ q / x⦌ C ∩ ⦋ 1 st ⁡ r / x⦌ C = ∅ ∧ 2 nd ⁡ q = 2 nd ⁡ r ∨ ⦋ 1 st ⁡ q / x⦌ C ∩ ⦋ 1 st ⁡ r / x⦌ C = ∅ ∧ ⦋ 2 nd ⁡ q / y⦌ D ∩ ⦋ 2 nd ⁡ r / y⦌ D = ∅
50 48 49 sylib ⊢ φ ∧ q ∈ A × B ∧ r ∈ A × B → 1 st ⁡ q = 1 st ⁡ r ∧ 2 nd ⁡ q = 2 nd ⁡ r ∨ 1 st ⁡ q = 1 st ⁡ r ∧ ⦋ 2 nd ⁡ q / y⦌ D ∩ ⦋ 2 nd ⁡ r / y⦌ D = ∅ ∨ ⦋ 1 st ⁡ q / x⦌ C ∩ ⦋ 1 st ⁡ r / x⦌ C = ∅ ∧ 2 nd ⁡ q = 2 nd ⁡ r ∨ ⦋ 1 st ⁡ q / x⦌ C ∩ ⦋ 1 st ⁡ r / x⦌ C = ∅ ∧ ⦋ 2 nd ⁡ q / y⦌ D ∩ ⦋ 2 nd ⁡ r / y⦌ D = ∅
51 xpopth ⊢ q ∈ A × B ∧ r ∈ A × B → 1 st ⁡ q = 1 st ⁡ r ∧ 2 nd ⁡ q = 2 nd ⁡ r ↔ q = r
52 51 adantl ⊢ φ ∧ q ∈ A × B ∧ r ∈ A × B → 1 st ⁡ q = 1 st ⁡ r ∧ 2 nd ⁡ q = 2 nd ⁡ r ↔ q = r
53 52 biimpd ⊢ φ ∧ q ∈ A × B ∧ r ∈ A × B → 1 st ⁡ q = 1 st ⁡ r ∧ 2 nd ⁡ q = 2 nd ⁡ r → q = r
54 inss2 ⊢ ⦋ q / p⦌ E ∩ ⦋ r / p⦌ E ∩ ⦋ q / p⦌ F ∩ ⦋ r / p⦌ F ⊆ ⦋ q / p⦌ F ∩ ⦋ r / p⦌ F
55 csbin ⊢ ⦋ q / p⦌ E ∩ F = ⦋ q / p⦌ E ∩ ⦋ q / p⦌ F
56 csbin ⊢ ⦋ r / p⦌ E ∩ F = ⦋ r / p⦌ E ∩ ⦋ r / p⦌ F
57 55 56 ineq12i ⊢ ⦋ q / p⦌ E ∩ F ∩ ⦋ r / p⦌ E ∩ F = ⦋ q / p⦌ E ∩ ⦋ q / p⦌ F ∩ ⦋ r / p⦌ E ∩ ⦋ r / p⦌ F
58 in4 ⊢ ⦋ q / p⦌ E ∩ ⦋ q / p⦌ F ∩ ⦋ r / p⦌ E ∩ ⦋ r / p⦌ F = ⦋ q / p⦌ E ∩ ⦋ r / p⦌ E ∩ ⦋ q / p⦌ F ∩ ⦋ r / p⦌ F
59 57 58 eqtri ⊢ ⦋ q / p⦌ E ∩ F ∩ ⦋ r / p⦌ E ∩ F = ⦋ q / p⦌ E ∩ ⦋ r / p⦌ E ∩ ⦋ q / p⦌ F ∩ ⦋ r / p⦌ F
60 vex ⊢ q ∈ V
61 csbnestgw ⊢ q ∈ V → ⦋ q / p⦌ ⦋ 2 nd ⁡ p / y⦌ D = ⦋ ⦋ q / p⦌ 2 nd ⁡ p / y⦌ D
62 60 61 ax-mp ⊢ ⦋ q / p⦌ ⦋ 2 nd ⁡ p / y⦌ D = ⦋ ⦋ q / p⦌ 2 nd ⁡ p / y⦌ D
63 fvex ⊢ 2 nd ⁡ p ∈ V
64 63 2 csbie ⊢ ⦋ 2 nd ⁡ p / y⦌ D = F
65 64 csbeq2i ⊢ ⦋ q / p⦌ ⦋ 2 nd ⁡ p / y⦌ D = ⦋ q / p⦌ F
66 csbfv ⊢ ⦋ q / p⦌ 2 nd ⁡ p = 2 nd ⁡ q
67 csbeq1 ⊢ ⦋ q / p⦌ 2 nd ⁡ p = 2 nd ⁡ q → ⦋ ⦋ q / p⦌ 2 nd ⁡ p / y⦌ D = ⦋ 2 nd ⁡ q / y⦌ D
68 66 67 ax-mp ⊢ ⦋ ⦋ q / p⦌ 2 nd ⁡ p / y⦌ D = ⦋ 2 nd ⁡ q / y⦌ D
69 62 65 68 3eqtr3ri ⊢ ⦋ 2 nd ⁡ q / y⦌ D = ⦋ q / p⦌ F
70 vex ⊢ r ∈ V
71 csbnestgw ⊢ r ∈ V → ⦋ r / p⦌ ⦋ 2 nd ⁡ p / y⦌ D = ⦋ ⦋ r / p⦌ 2 nd ⁡ p / y⦌ D
72 70 71 ax-mp ⊢ ⦋ r / p⦌ ⦋ 2 nd ⁡ p / y⦌ D = ⦋ ⦋ r / p⦌ 2 nd ⁡ p / y⦌ D
73 64 csbeq2i ⊢ ⦋ r / p⦌ ⦋ 2 nd ⁡ p / y⦌ D = ⦋ r / p⦌ F
74 csbfv ⊢ ⦋ r / p⦌ 2 nd ⁡ p = 2 nd ⁡ r
75 csbeq1 ⊢ ⦋ r / p⦌ 2 nd ⁡ p = 2 nd ⁡ r → ⦋ ⦋ r / p⦌ 2 nd ⁡ p / y⦌ D = ⦋ 2 nd ⁡ r / y⦌ D
76 74 75 ax-mp ⊢ ⦋ ⦋ r / p⦌ 2 nd ⁡ p / y⦌ D = ⦋ 2 nd ⁡ r / y⦌ D
77 72 73 76 3eqtr3ri ⊢ ⦋ 2 nd ⁡ r / y⦌ D = ⦋ r / p⦌ F
78 69 77 ineq12i ⊢ ⦋ 2 nd ⁡ q / y⦌ D ∩ ⦋ 2 nd ⁡ r / y⦌ D = ⦋ q / p⦌ F ∩ ⦋ r / p⦌ F
79 54 59 78 3sstr4i ⊢ ⦋ q / p⦌ E ∩ F ∩ ⦋ r / p⦌ E ∩ F ⊆ ⦋ 2 nd ⁡ q / y⦌ D ∩ ⦋ 2 nd ⁡ r / y⦌ D
80 sseq0 ⊢ ⦋ q / p⦌ E ∩ F ∩ ⦋ r / p⦌ E ∩ F ⊆ ⦋ 2 nd ⁡ q / y⦌ D ∩ ⦋ 2 nd ⁡ r / y⦌ D ∧ ⦋ 2 nd ⁡ q / y⦌ D ∩ ⦋ 2 nd ⁡ r / y⦌ D = ∅ → ⦋ q / p⦌ E ∩ F ∩ ⦋ r / p⦌ E ∩ F = ∅
81 79 80 mpan ⊢ ⦋ 2 nd ⁡ q / y⦌ D ∩ ⦋ 2 nd ⁡ r / y⦌ D = ∅ → ⦋ q / p⦌ E ∩ F ∩ ⦋ r / p⦌ E ∩ F = ∅
82 81 a1i ⊢ φ ∧ q ∈ A × B ∧ r ∈ A × B → ⦋ 2 nd ⁡ q / y⦌ D ∩ ⦋ 2 nd ⁡ r / y⦌ D = ∅ → ⦋ q / p⦌ E ∩ F ∩ ⦋ r / p⦌ E ∩ F = ∅
83 82 adantld ⊢ φ ∧ q ∈ A × B ∧ r ∈ A × B → 1 st ⁡ q = 1 st ⁡ r ∧ ⦋ 2 nd ⁡ q / y⦌ D ∩ ⦋ 2 nd ⁡ r / y⦌ D = ∅ → ⦋ q / p⦌ E ∩ F ∩ ⦋ r / p⦌ E ∩ F = ∅
84 inss1 ⊢ ⦋ q / p⦌ E ∩ ⦋ r / p⦌ E ∩ ⦋ q / p⦌ F ∩ ⦋ r / p⦌ F ⊆ ⦋ q / p⦌ E ∩ ⦋ r / p⦌ E
85 csbnestgw ⊢ q ∈ V → ⦋ q / p⦌ ⦋ 1 st ⁡ p / x⦌ C = ⦋ ⦋ q / p⦌ 1 st ⁡ p / x⦌ C
86 60 85 ax-mp ⊢ ⦋ q / p⦌ ⦋ 1 st ⁡ p / x⦌ C = ⦋ ⦋ q / p⦌ 1 st ⁡ p / x⦌ C
87 fvex ⊢ 1 st ⁡ p ∈ V
88 87 1 csbie ⊢ ⦋ 1 st ⁡ p / x⦌ C = E
89 88 csbeq2i ⊢ ⦋ q / p⦌ ⦋ 1 st ⁡ p / x⦌ C = ⦋ q / p⦌ E
90 csbfv ⊢ ⦋ q / p⦌ 1 st ⁡ p = 1 st ⁡ q
91 csbeq1 ⊢ ⦋ q / p⦌ 1 st ⁡ p = 1 st ⁡ q → ⦋ ⦋ q / p⦌ 1 st ⁡ p / x⦌ C = ⦋ 1 st ⁡ q / x⦌ C
92 90 91 ax-mp ⊢ ⦋ ⦋ q / p⦌ 1 st ⁡ p / x⦌ C = ⦋ 1 st ⁡ q / x⦌ C
93 86 89 92 3eqtr3ri ⊢ ⦋ 1 st ⁡ q / x⦌ C = ⦋ q / p⦌ E
94 csbnestgw ⊢ r ∈ V → ⦋ r / p⦌ ⦋ 1 st ⁡ p / x⦌ C = ⦋ ⦋ r / p⦌ 1 st ⁡ p / x⦌ C
95 70 94 ax-mp ⊢ ⦋ r / p⦌ ⦋ 1 st ⁡ p / x⦌ C = ⦋ ⦋ r / p⦌ 1 st ⁡ p / x⦌ C
96 88 csbeq2i ⊢ ⦋ r / p⦌ ⦋ 1 st ⁡ p / x⦌ C = ⦋ r / p⦌ E
97 csbfv ⊢ ⦋ r / p⦌ 1 st ⁡ p = 1 st ⁡ r
98 csbeq1 ⊢ ⦋ r / p⦌ 1 st ⁡ p = 1 st ⁡ r → ⦋ ⦋ r / p⦌ 1 st ⁡ p / x⦌ C = ⦋ 1 st ⁡ r / x⦌ C
99 97 98 ax-mp ⊢ ⦋ ⦋ r / p⦌ 1 st ⁡ p / x⦌ C = ⦋ 1 st ⁡ r / x⦌ C
100 95 96 99 3eqtr3ri ⊢ ⦋ 1 st ⁡ r / x⦌ C = ⦋ r / p⦌ E
101 93 100 ineq12i ⊢ ⦋ 1 st ⁡ q / x⦌ C ∩ ⦋ 1 st ⁡ r / x⦌ C = ⦋ q / p⦌ E ∩ ⦋ r / p⦌ E
102 84 59 101 3sstr4i ⊢ ⦋ q / p⦌ E ∩ F ∩ ⦋ r / p⦌ E ∩ F ⊆ ⦋ 1 st ⁡ q / x⦌ C ∩ ⦋ 1 st ⁡ r / x⦌ C
103 sseq0 ⊢ ⦋ q / p⦌ E ∩ F ∩ ⦋ r / p⦌ E ∩ F ⊆ ⦋ 1 st ⁡ q / x⦌ C ∩ ⦋ 1 st ⁡ r / x⦌ C ∧ ⦋ 1 st ⁡ q / x⦌ C ∩ ⦋ 1 st ⁡ r / x⦌ C = ∅ → ⦋ q / p⦌ E ∩ F ∩ ⦋ r / p⦌ E ∩ F = ∅
104 102 103 mpan ⊢ ⦋ 1 st ⁡ q / x⦌ C ∩ ⦋ 1 st ⁡ r / x⦌ C = ∅ → ⦋ q / p⦌ E ∩ F ∩ ⦋ r / p⦌ E ∩ F = ∅
105 104 a1i ⊢ φ ∧ q ∈ A × B ∧ r ∈ A × B → ⦋ 1 st ⁡ q / x⦌ C ∩ ⦋ 1 st ⁡ r / x⦌ C = ∅ → ⦋ q / p⦌ E ∩ F ∩ ⦋ r / p⦌ E ∩ F = ∅
106 105 adantrd ⊢ φ ∧ q ∈ A × B ∧ r ∈ A × B → ⦋ 1 st ⁡ q / x⦌ C ∩ ⦋ 1 st ⁡ r / x⦌ C = ∅ ∧ 2 nd ⁡ q = 2 nd ⁡ r → ⦋ q / p⦌ E ∩ F ∩ ⦋ r / p⦌ E ∩ F = ∅
107 82 adantld ⊢ φ ∧ q ∈ A × B ∧ r ∈ A × B → ⦋ 1 st ⁡ q / x⦌ C ∩ ⦋ 1 st ⁡ r / x⦌ C = ∅ ∧ ⦋ 2 nd ⁡ q / y⦌ D ∩ ⦋ 2 nd ⁡ r / y⦌ D = ∅ → ⦋ q / p⦌ E ∩ F ∩ ⦋ r / p⦌ E ∩ F = ∅
108 106 107 jaod ⊢ φ ∧ q ∈ A × B ∧ r ∈ A × B → ⦋ 1 st ⁡ q / x⦌ C ∩ ⦋ 1 st ⁡ r / x⦌ C = ∅ ∧ 2 nd ⁡ q = 2 nd ⁡ r ∨ ⦋ 1 st ⁡ q / x⦌ C ∩ ⦋ 1 st ⁡ r / x⦌ C = ∅ ∧ ⦋ 2 nd ⁡ q / y⦌ D ∩ ⦋ 2 nd ⁡ r / y⦌ D = ∅ → ⦋ q / p⦌ E ∩ F ∩ ⦋ r / p⦌ E ∩ F = ∅
109 83 108 jaod ⊢ φ ∧ q ∈ A × B ∧ r ∈ A × B → 1 st ⁡ q = 1 st ⁡ r ∧ ⦋ 2 nd ⁡ q / y⦌ D ∩ ⦋ 2 nd ⁡ r / y⦌ D = ∅ ∨ ⦋ 1 st ⁡ q / x⦌ C ∩ ⦋ 1 st ⁡ r / x⦌ C = ∅ ∧ 2 nd ⁡ q = 2 nd ⁡ r ∨ ⦋ 1 st ⁡ q / x⦌ C ∩ ⦋ 1 st ⁡ r / x⦌ C = ∅ ∧ ⦋ 2 nd ⁡ q / y⦌ D ∩ ⦋ 2 nd ⁡ r / y⦌ D = ∅ → ⦋ q / p⦌ E ∩ F ∩ ⦋ r / p⦌ E ∩ F = ∅
110 53 109 orim12d ⊢ φ ∧ q ∈ A × B ∧ r ∈ A × B → 1 st ⁡ q = 1 st ⁡ r ∧ 2 nd ⁡ q = 2 nd ⁡ r ∨ 1 st ⁡ q = 1 st ⁡ r ∧ ⦋ 2 nd ⁡ q / y⦌ D ∩ ⦋ 2 nd ⁡ r / y⦌ D = ∅ ∨ ⦋ 1 st ⁡ q / x⦌ C ∩ ⦋ 1 st ⁡ r / x⦌ C = ∅ ∧ 2 nd ⁡ q = 2 nd ⁡ r ∨ ⦋ 1 st ⁡ q / x⦌ C ∩ ⦋ 1 st ⁡ r / x⦌ C = ∅ ∧ ⦋ 2 nd ⁡ q / y⦌ D ∩ ⦋ 2 nd ⁡ r / y⦌ D = ∅ → q = r ∨ ⦋ q / p⦌ E ∩ F ∩ ⦋ r / p⦌ E ∩ F = ∅
111 50 110 mpd ⊢ φ ∧ q ∈ A × B ∧ r ∈ A × B → q = r ∨ ⦋ q / p⦌ E ∩ F ∩ ⦋ r / p⦌ E ∩ F = ∅
112 111 ralrimivva ⊢ φ → ∀ q ∈ A × B ∀ r ∈ A × B q = r ∨ ⦋ q / p⦌ E ∩ F ∩ ⦋ r / p⦌ E ∩ F = ∅
113 disjors ⊢ Disj p ∈ A × B E ∩ F ↔ ∀ q ∈ A × B ∀ r ∈ A × B q = r ∨ ⦋ q / p⦌ E ∩ F ∩ ⦋ r / p⦌ E ∩ F = ∅
114 112 113 sylibr ⊢ φ → Disj p ∈ A × B E ∩ F