Metamath Proof Explorer


Theorem divcan4i

Description: A cancellation law for division. (Contributed by NM, 18-May-1999)

Ref Expression
Hypotheses divclz.1 ⊢ A ∈ ℂ
divclz.2 ⊢ B ∈ ℂ
divcl.3 ⊢ B ≠ 0
Assertion divcan4i ⊢ A ⁢ B B = A

Proof

Step Hyp Ref Expression
1 divclz.1 ⊢ A ∈ ℂ
2 divclz.2 ⊢ B ∈ ℂ
3 divcl.3 ⊢ B ≠ 0
4 1 2 divcan4zi ⊢ B ≠ 0 → A ⁢ B B = A
5 3 4 ax-mp ⊢ A ⁢ B B = A