Metamath Proof Explorer


Theorem divcan4i

Description: A cancellation law for division. (Contributed by NM, 18-May-1999)

Ref Expression
Hypotheses divclz.1 A
divclz.2 B
divcl.3 B 0
Assertion divcan4i A B B = A

Proof

Step Hyp Ref Expression
1 divclz.1 A
2 divclz.2 B
3 divcl.3 B 0
4 1 2 divcan4zi B 0 A B B = A
5 3 4 ax-mp A B B = A