Metamath Proof Explorer


Theorem divcxp

Description: Complex exponentiation of a quotient. (Contributed by Mario Carneiro, 8-Sep-2014)

Ref Expression
Assertion divcxp ⊢ A ∈ ℝ ∧ 0 ≤ A ∧ B ∈ ℝ + ∧ C ∈ ℂ → A B C = A C B C

Proof

Step Hyp Ref Expression
1 simp1l ⊢ A ∈ ℝ ∧ 0 ≤ A ∧ B ∈ ℝ + ∧ C ∈ ℂ → A ∈ ℝ
2 simp1r ⊢ A ∈ ℝ ∧ 0 ≤ A ∧ B ∈ ℝ + ∧ C ∈ ℂ → 0 ≤ A
3 simp2 ⊢ A ∈ ℝ ∧ 0 ≤ A ∧ B ∈ ℝ + ∧ C ∈ ℂ → B ∈ ℝ +
4 3 rpreccld ⊢ A ∈ ℝ ∧ 0 ≤ A ∧ B ∈ ℝ + ∧ C ∈ ℂ → 1 B ∈ ℝ +
5 4 rpred ⊢ A ∈ ℝ ∧ 0 ≤ A ∧ B ∈ ℝ + ∧ C ∈ ℂ → 1 B ∈ ℝ
6 4 rpge0d ⊢ A ∈ ℝ ∧ 0 ≤ A ∧ B ∈ ℝ + ∧ C ∈ ℂ → 0 ≤ 1 B
7 simp3 ⊢ A ∈ ℝ ∧ 0 ≤ A ∧ B ∈ ℝ + ∧ C ∈ ℂ → C ∈ ℂ
8 mulcxp ⊢ A ∈ ℝ ∧ 0 ≤ A ∧ 1 B ∈ ℝ ∧ 0 ≤ 1 B ∧ C ∈ ℂ → A ⁢ 1 B C = A C ⁢ 1 B C
9 1 2 5 6 7 8 syl221anc ⊢ A ∈ ℝ ∧ 0 ≤ A ∧ B ∈ ℝ + ∧ C ∈ ℂ → A ⁢ 1 B C = A C ⁢ 1 B C
10 cxprec ⊢ B ∈ ℝ + ∧ C ∈ ℂ → 1 B C = 1 B C
11 3 7 10 syl2anc ⊢ A ∈ ℝ ∧ 0 ≤ A ∧ B ∈ ℝ + ∧ C ∈ ℂ → 1 B C = 1 B C
12 11 oveq2d ⊢ A ∈ ℝ ∧ 0 ≤ A ∧ B ∈ ℝ + ∧ C ∈ ℂ → A C ⁢ 1 B C = A C ⁢ 1 B C
13 9 12 eqtrd ⊢ A ∈ ℝ ∧ 0 ≤ A ∧ B ∈ ℝ + ∧ C ∈ ℂ → A ⁢ 1 B C = A C ⁢ 1 B C
14 1 recnd ⊢ A ∈ ℝ ∧ 0 ≤ A ∧ B ∈ ℝ + ∧ C ∈ ℂ → A ∈ ℂ
15 3 rpcnd ⊢ A ∈ ℝ ∧ 0 ≤ A ∧ B ∈ ℝ + ∧ C ∈ ℂ → B ∈ ℂ
16 3 rpne0d ⊢ A ∈ ℝ ∧ 0 ≤ A ∧ B ∈ ℝ + ∧ C ∈ ℂ → B ≠ 0
17 14 15 16 divrecd ⊢ A ∈ ℝ ∧ 0 ≤ A ∧ B ∈ ℝ + ∧ C ∈ ℂ → A B = A ⁢ 1 B
18 17 oveq1d ⊢ A ∈ ℝ ∧ 0 ≤ A ∧ B ∈ ℝ + ∧ C ∈ ℂ → A B C = A ⁢ 1 B C
19 cxpcl ⊢ A ∈ ℂ ∧ C ∈ ℂ → A C ∈ ℂ
20 14 7 19 syl2anc ⊢ A ∈ ℝ ∧ 0 ≤ A ∧ B ∈ ℝ + ∧ C ∈ ℂ → A C ∈ ℂ
21 cxpcl ⊢ B ∈ ℂ ∧ C ∈ ℂ → B C ∈ ℂ
22 15 7 21 syl2anc ⊢ A ∈ ℝ ∧ 0 ≤ A ∧ B ∈ ℝ + ∧ C ∈ ℂ → B C ∈ ℂ
23 cxpne0 ⊢ B ∈ ℂ ∧ B ≠ 0 ∧ C ∈ ℂ → B C ≠ 0
24 15 16 7 23 syl3anc ⊢ A ∈ ℝ ∧ 0 ≤ A ∧ B ∈ ℝ + ∧ C ∈ ℂ → B C ≠ 0
25 20 22 24 divrecd ⊢ A ∈ ℝ ∧ 0 ≤ A ∧ B ∈ ℝ + ∧ C ∈ ℂ → A C B C = A C ⁢ 1 B C
26 13 18 25 3eqtr4d ⊢ A ∈ ℝ ∧ 0 ≤ A ∧ B ∈ ℝ + ∧ C ∈ ℂ → A B C = A C B C