Metamath Proof Explorer


Theorem divreci

Description: Relationship between division and reciprocal. Theorem I.9 of Apostol p. 18. (Contributed by NM, 9-Feb-1995)

Ref Expression
Hypotheses divclz.1 A
divclz.2 B
divcl.3 B0
Assertion divreci AB=A1B

Proof

Step Hyp Ref Expression
1 divclz.1 A
2 divclz.2 B
3 divcl.3 B0
4 1 2 divreczi B0AB=A1B
5 3 4 ax-mp AB=A1B