Metamath Proof Explorer


Theorem djhsumss

Description: Subspace sum is a subset of subspace join. (Contributed by NM, 6-Aug-2014)

Ref Expression
Hypotheses djhsumss.h ⊢ H = LHyp ⁡ K
djhsumss.u ⊢ U = DVecH ⁡ K ⁡ W
djhsumss.v ⊢ V = Base U
djhsumss.p ⊢ ⊕ ˙ = LSSum ⁡ U
djhsumss.j ⊢ ∨ ˙ = joinH ⁡ K ⁡ W
djhsumss.k ⊢ φ → K ∈ HL ∧ W ∈ H
djhsumss.x ⊢ φ → X ⊆ V
djhsumss.y ⊢ φ → Y ⊆ V
Assertion djhsumss ⊢ φ → X ⊕ ˙ Y ⊆ X ∨ ˙ Y

Proof

Step Hyp Ref Expression
1 djhsumss.h ⊢ H = LHyp ⁡ K
2 djhsumss.u ⊢ U = DVecH ⁡ K ⁡ W
3 djhsumss.v ⊢ V = Base U
4 djhsumss.p ⊢ ⊕ ˙ = LSSum ⁡ U
5 djhsumss.j ⊢ ∨ ˙ = joinH ⁡ K ⁡ W
6 djhsumss.k ⊢ φ → K ∈ HL ∧ W ∈ H
7 djhsumss.x ⊢ φ → X ⊆ V
8 djhsumss.y ⊢ φ → Y ⊆ V
9 eqid ⊢ LSpan ⁡ U = LSpan ⁡ U
10 1 2 6 dvhlmod ⊢ φ → U ∈ LMod
11 3 9 4 7 8 10 lsmssspx ⊢ φ → X ⊕ ˙ Y ⊆ LSpan ⁡ U ⁡ X ∪ Y
12 1 2 3 9 5 6 7 8 djhspss ⊢ φ → LSpan ⁡ U ⁡ X ∪ Y ⊆ X ∨ ˙ Y
13 11 12 sstrd ⊢ φ → X ⊕ ˙ Y ⊆ X ∨ ˙ Y