Metamath Proof Explorer


Theorem djuassen

Description: Associative law for cardinal addition. Exercise 4.56(c) of Mendelson p. 258. (Contributed by NM, 26-Sep-2004) (Revised by Mario Carneiro, 29-Apr-2015)

Ref Expression
Assertion djuassen ⊢ A ∈ V ∧ B ∈ W ∧ C ∈ X → A ⊔︀ B ⊔︀ C ≈ A ⊔︀ B ⊔︀ C

Proof

Step Hyp Ref Expression
1 0ex ⊢ ∅ ∈ V
2 simp1 ⊢ A ∈ V ∧ B ∈ W ∧ C ∈ X → A ∈ V
3 xpsnen2g ⊢ ∅ ∈ V ∧ A ∈ V → ∅ × A ≈ A
4 1 2 3 sylancr ⊢ A ∈ V ∧ B ∈ W ∧ C ∈ X → ∅ × A ≈ A
5 4 ensymd ⊢ A ∈ V ∧ B ∈ W ∧ C ∈ X → A ≈ ∅ × A
6 1oex ⊢ 1 𝑜 ∈ V
7 snex ⊢ ∅ ∈ V
8 simp2 ⊢ A ∈ V ∧ B ∈ W ∧ C ∈ X → B ∈ W
9 xpexg ⊢ ∅ ∈ V ∧ B ∈ W → ∅ × B ∈ V
10 7 8 9 sylancr ⊢ A ∈ V ∧ B ∈ W ∧ C ∈ X → ∅ × B ∈ V
11 xpsnen2g ⊢ 1 𝑜 ∈ V ∧ ∅ × B ∈ V → 1 𝑜 × ∅ × B ≈ ∅ × B
12 6 10 11 sylancr ⊢ A ∈ V ∧ B ∈ W ∧ C ∈ X → 1 𝑜 × ∅ × B ≈ ∅ × B
13 xpsnen2g ⊢ ∅ ∈ V ∧ B ∈ W → ∅ × B ≈ B
14 1 8 13 sylancr ⊢ A ∈ V ∧ B ∈ W ∧ C ∈ X → ∅ × B ≈ B
15 entr ⊢ 1 𝑜 × ∅ × B ≈ ∅ × B ∧ ∅ × B ≈ B → 1 𝑜 × ∅ × B ≈ B
16 12 14 15 syl2anc ⊢ A ∈ V ∧ B ∈ W ∧ C ∈ X → 1 𝑜 × ∅ × B ≈ B
17 16 ensymd ⊢ A ∈ V ∧ B ∈ W ∧ C ∈ X → B ≈ 1 𝑜 × ∅ × B
18 xp01disjl ⊢ ∅ × A ∩ 1 𝑜 × ∅ × B = ∅
19 18 a1i ⊢ A ∈ V ∧ B ∈ W ∧ C ∈ X → ∅ × A ∩ 1 𝑜 × ∅ × B = ∅
20 djuenun ⊢ A ≈ ∅ × A ∧ B ≈ 1 𝑜 × ∅ × B ∧ ∅ × A ∩ 1 𝑜 × ∅ × B = ∅ → A ⊔︀ B ≈ ∅ × A ∪ 1 𝑜 × ∅ × B
21 5 17 19 20 syl3anc ⊢ A ∈ V ∧ B ∈ W ∧ C ∈ X → A ⊔︀ B ≈ ∅ × A ∪ 1 𝑜 × ∅ × B
22 snex ⊢ 1 𝑜 ∈ V
23 simp3 ⊢ A ∈ V ∧ B ∈ W ∧ C ∈ X → C ∈ X
24 xpexg ⊢ 1 𝑜 ∈ V ∧ C ∈ X → 1 𝑜 × C ∈ V
25 22 23 24 sylancr ⊢ A ∈ V ∧ B ∈ W ∧ C ∈ X → 1 𝑜 × C ∈ V
26 xpsnen2g ⊢ 1 𝑜 ∈ V ∧ 1 𝑜 × C ∈ V → 1 𝑜 × 1 𝑜 × C ≈ 1 𝑜 × C
27 6 25 26 sylancr ⊢ A ∈ V ∧ B ∈ W ∧ C ∈ X → 1 𝑜 × 1 𝑜 × C ≈ 1 𝑜 × C
28 xpsnen2g ⊢ 1 𝑜 ∈ V ∧ C ∈ X → 1 𝑜 × C ≈ C
29 6 23 28 sylancr ⊢ A ∈ V ∧ B ∈ W ∧ C ∈ X → 1 𝑜 × C ≈ C
30 entr ⊢ 1 𝑜 × 1 𝑜 × C ≈ 1 𝑜 × C ∧ 1 𝑜 × C ≈ C → 1 𝑜 × 1 𝑜 × C ≈ C
31 27 29 30 syl2anc ⊢ A ∈ V ∧ B ∈ W ∧ C ∈ X → 1 𝑜 × 1 𝑜 × C ≈ C
32 31 ensymd ⊢ A ∈ V ∧ B ∈ W ∧ C ∈ X → C ≈ 1 𝑜 × 1 𝑜 × C
33 indir ⊢ ∅ × A ∪ 1 𝑜 × ∅ × B ∩ 1 𝑜 × 1 𝑜 × C = ∅ × A ∩ 1 𝑜 × 1 𝑜 × C ∪ 1 𝑜 × ∅ × B ∩ 1 𝑜 × 1 𝑜 × C
34 xp01disjl ⊢ ∅ × A ∩ 1 𝑜 × 1 𝑜 × C = ∅
35 xp01disjl ⊢ ∅ × B ∩ 1 𝑜 × C = ∅
36 35 xpeq2i ⊢ 1 𝑜 × ∅ × B ∩ 1 𝑜 × C = 1 𝑜 × ∅
37 xpindi ⊢ 1 𝑜 × ∅ × B ∩ 1 𝑜 × C = 1 𝑜 × ∅ × B ∩ 1 𝑜 × 1 𝑜 × C
38 xp0 ⊢ 1 𝑜 × ∅ = ∅
39 36 37 38 3eqtr3i ⊢ 1 𝑜 × ∅ × B ∩ 1 𝑜 × 1 𝑜 × C = ∅
40 34 39 uneq12i ⊢ ∅ × A ∩ 1 𝑜 × 1 𝑜 × C ∪ 1 𝑜 × ∅ × B ∩ 1 𝑜 × 1 𝑜 × C = ∅ ∪ ∅
41 un0 ⊢ ∅ ∪ ∅ = ∅
42 40 41 eqtri ⊢ ∅ × A ∩ 1 𝑜 × 1 𝑜 × C ∪ 1 𝑜 × ∅ × B ∩ 1 𝑜 × 1 𝑜 × C = ∅
43 33 42 eqtri ⊢ ∅ × A ∪ 1 𝑜 × ∅ × B ∩ 1 𝑜 × 1 𝑜 × C = ∅
44 43 a1i ⊢ A ∈ V ∧ B ∈ W ∧ C ∈ X → ∅ × A ∪ 1 𝑜 × ∅ × B ∩ 1 𝑜 × 1 𝑜 × C = ∅
45 djuenun ⊢ A ⊔︀ B ≈ ∅ × A ∪ 1 𝑜 × ∅ × B ∧ C ≈ 1 𝑜 × 1 𝑜 × C ∧ ∅ × A ∪ 1 𝑜 × ∅ × B ∩ 1 𝑜 × 1 𝑜 × C = ∅ → A ⊔︀ B ⊔︀ C ≈ ∅ × A ∪ 1 𝑜 × ∅ × B ∪ 1 𝑜 × 1 𝑜 × C
46 21 32 44 45 syl3anc ⊢ A ∈ V ∧ B ∈ W ∧ C ∈ X → A ⊔︀ B ⊔︀ C ≈ ∅ × A ∪ 1 𝑜 × ∅ × B ∪ 1 𝑜 × 1 𝑜 × C
47 df-dju ⊢ B ⊔︀ C = ∅ × B ∪ 1 𝑜 × C
48 47 xpeq2i ⊢ 1 𝑜 × B ⊔︀ C = 1 𝑜 × ∅ × B ∪ 1 𝑜 × C
49 xpundi ⊢ 1 𝑜 × ∅ × B ∪ 1 𝑜 × C = 1 𝑜 × ∅ × B ∪ 1 𝑜 × 1 𝑜 × C
50 48 49 eqtri ⊢ 1 𝑜 × B ⊔︀ C = 1 𝑜 × ∅ × B ∪ 1 𝑜 × 1 𝑜 × C
51 50 uneq2i ⊢ ∅ × A ∪ 1 𝑜 × B ⊔︀ C = ∅ × A ∪ 1 𝑜 × ∅ × B ∪ 1 𝑜 × 1 𝑜 × C
52 df-dju ⊢ A ⊔︀ B ⊔︀ C = ∅ × A ∪ 1 𝑜 × B ⊔︀ C
53 unass ⊢ ∅ × A ∪ 1 𝑜 × ∅ × B ∪ 1 𝑜 × 1 𝑜 × C = ∅ × A ∪ 1 𝑜 × ∅ × B ∪ 1 𝑜 × 1 𝑜 × C
54 51 52 53 3eqtr4i ⊢ A ⊔︀ B ⊔︀ C = ∅ × A ∪ 1 𝑜 × ∅ × B ∪ 1 𝑜 × 1 𝑜 × C
55 46 54 breqtrrdi ⊢ A ∈ V ∧ B ∈ W ∧ C ∈ X → A ⊔︀ B ⊔︀ C ≈ A ⊔︀ B ⊔︀ C