Metamath Proof Explorer


Theorem dmatelnd

Description: An extradiagonal entry of a diagonal matrix is equal to zero. (Contributed by AV, 19-Aug-2019) (Revised by AV, 18-Dec-2019)

Ref Expression
Hypotheses dmatid.a ⊢ A = N Mat R
dmatid.b ⊢ B = Base A
dmatid.0 ⊢ 0 ˙ = 0 R
dmatid.d ⊢ D = N DMat R
Assertion dmatelnd ⊢ N ∈ Fin ∧ R ∈ Ring ∧ X ∈ D ∧ I ∈ N ∧ J ∈ N ∧ I ≠ J → I X J = 0 ˙

Proof

Step Hyp Ref Expression
1 dmatid.a ⊢ A = N Mat R
2 dmatid.b ⊢ B = Base A
3 dmatid.0 ⊢ 0 ˙ = 0 R
4 dmatid.d ⊢ D = N DMat R
5 1 2 3 4 dmatel ⊢ N ∈ Fin ∧ R ∈ Ring → X ∈ D ↔ X ∈ B ∧ ∀ i ∈ N ∀ j ∈ N i ≠ j → i X j = 0 ˙
6 neeq1 ⊢ i = I → i ≠ j ↔ I ≠ j
7 oveq1 ⊢ i = I → i X j = I X j
8 7 eqeq1d ⊢ i = I → i X j = 0 ˙ ↔ I X j = 0 ˙
9 6 8 imbi12d ⊢ i = I → i ≠ j → i X j = 0 ˙ ↔ I ≠ j → I X j = 0 ˙
10 neeq2 ⊢ j = J → I ≠ j ↔ I ≠ J
11 oveq2 ⊢ j = J → I X j = I X J
12 11 eqeq1d ⊢ j = J → I X j = 0 ˙ ↔ I X J = 0 ˙
13 10 12 imbi12d ⊢ j = J → I ≠ j → I X j = 0 ˙ ↔ I ≠ J → I X J = 0 ˙
14 9 13 rspc2v ⊢ I ∈ N ∧ J ∈ N → ∀ i ∈ N ∀ j ∈ N i ≠ j → i X j = 0 ˙ → I ≠ J → I X J = 0 ˙
15 14 com23 ⊢ I ∈ N ∧ J ∈ N → I ≠ J → ∀ i ∈ N ∀ j ∈ N i ≠ j → i X j = 0 ˙ → I X J = 0 ˙
16 15 3impia ⊢ I ∈ N ∧ J ∈ N ∧ I ≠ J → ∀ i ∈ N ∀ j ∈ N i ≠ j → i X j = 0 ˙ → I X J = 0 ˙
17 16 com12 ⊢ ∀ i ∈ N ∀ j ∈ N i ≠ j → i X j = 0 ˙ → I ∈ N ∧ J ∈ N ∧ I ≠ J → I X J = 0 ˙
18 17 2a1i ⊢ N ∈ Fin ∧ R ∈ Ring → X ∈ B → ∀ i ∈ N ∀ j ∈ N i ≠ j → i X j = 0 ˙ → I ∈ N ∧ J ∈ N ∧ I ≠ J → I X J = 0 ˙
19 18 impd ⊢ N ∈ Fin ∧ R ∈ Ring → X ∈ B ∧ ∀ i ∈ N ∀ j ∈ N i ≠ j → i X j = 0 ˙ → I ∈ N ∧ J ∈ N ∧ I ≠ J → I X J = 0 ˙
20 5 19 sylbid ⊢ N ∈ Fin ∧ R ∈ Ring → X ∈ D → I ∈ N ∧ J ∈ N ∧ I ≠ J → I X J = 0 ˙
21 20 3impia ⊢ N ∈ Fin ∧ R ∈ Ring ∧ X ∈ D → I ∈ N ∧ J ∈ N ∧ I ≠ J → I X J = 0 ˙
22 21 imp ⊢ N ∈ Fin ∧ R ∈ Ring ∧ X ∈ D ∧ I ∈ N ∧ J ∈ N ∧ I ≠ J → I X J = 0 ˙