Metamath Proof Explorer


Theorem dmdprdsplit

Description: The direct product splits into the direct product of any partition of the index set. (Contributed by Mario Carneiro, 25-Apr-2016)

Ref Expression
Hypotheses dprdsplit.2 ⊢ φ → S : I ⟶ SubGrp ⁡ G
dprdsplit.i ⊢ φ → C ∩ D = ∅
dprdsplit.u ⊢ φ → I = C ∪ D
dmdprdsplit.z ⊢ Z = Cntz ⁡ G
dmdprdsplit.0 ⊢ 0 ˙ = 0 G
Assertion dmdprdsplit ⊢ φ → G dom ⁡ DProd S ↔ G dom ⁡ DProd S ↾ C ∧ G dom ⁡ DProd S ↾ D ∧ G DProd S ↾ C ⊆ Z ⁡ G DProd S ↾ D ∧ G DProd S ↾ C ∩ G DProd S ↾ D = 0 ˙

Proof

Step Hyp Ref Expression
1 dprdsplit.2 ⊢ φ → S : I ⟶ SubGrp ⁡ G
2 dprdsplit.i ⊢ φ → C ∩ D = ∅
3 dprdsplit.u ⊢ φ → I = C ∪ D
4 dmdprdsplit.z ⊢ Z = Cntz ⁡ G
5 dmdprdsplit.0 ⊢ 0 ˙ = 0 G
6 simpr ⊢ φ ∧ G dom ⁡ DProd S → G dom ⁡ DProd S
7 1 fdmd ⊢ φ → dom ⁡ S = I
8 7 adantr ⊢ φ ∧ G dom ⁡ DProd S → dom ⁡ S = I
9 ssun1 ⊢ C ⊆ C ∪ D
10 3 adantr ⊢ φ ∧ G dom ⁡ DProd S → I = C ∪ D
11 9 10 sseqtrrid ⊢ φ ∧ G dom ⁡ DProd S → C ⊆ I
12 6 8 11 dprdres ⊢ φ ∧ G dom ⁡ DProd S → G dom ⁡ DProd S ↾ C ∧ G DProd S ↾ C ⊆ G DProd S
13 12 simpld ⊢ φ ∧ G dom ⁡ DProd S → G dom ⁡ DProd S ↾ C
14 ssun2 ⊢ D ⊆ C ∪ D
15 14 10 sseqtrrid ⊢ φ ∧ G dom ⁡ DProd S → D ⊆ I
16 6 8 15 dprdres ⊢ φ ∧ G dom ⁡ DProd S → G dom ⁡ DProd S ↾ D ∧ G DProd S ↾ D ⊆ G DProd S
17 16 simpld ⊢ φ ∧ G dom ⁡ DProd S → G dom ⁡ DProd S ↾ D
18 13 17 jca ⊢ φ ∧ G dom ⁡ DProd S → G dom ⁡ DProd S ↾ C ∧ G dom ⁡ DProd S ↾ D
19 2 adantr ⊢ φ ∧ G dom ⁡ DProd S → C ∩ D = ∅
20 6 8 11 15 19 4 dprdcntz2 ⊢ φ ∧ G dom ⁡ DProd S → G DProd S ↾ C ⊆ Z ⁡ G DProd S ↾ D
21 6 8 11 15 19 5 dprddisj2 ⊢ φ ∧ G dom ⁡ DProd S → G DProd S ↾ C ∩ G DProd S ↾ D = 0 ˙
22 18 20 21 3jca ⊢ φ ∧ G dom ⁡ DProd S → G dom ⁡ DProd S ↾ C ∧ G dom ⁡ DProd S ↾ D ∧ G DProd S ↾ C ⊆ Z ⁡ G DProd S ↾ D ∧ G DProd S ↾ C ∩ G DProd S ↾ D = 0 ˙
23 1 adantr ⊢ φ ∧ G dom ⁡ DProd S ↾ C ∧ G dom ⁡ DProd S ↾ D ∧ G DProd S ↾ C ⊆ Z ⁡ G DProd S ↾ D ∧ G DProd S ↾ C ∩ G DProd S ↾ D = 0 ˙ → S : I ⟶ SubGrp ⁡ G
24 2 adantr ⊢ φ ∧ G dom ⁡ DProd S ↾ C ∧ G dom ⁡ DProd S ↾ D ∧ G DProd S ↾ C ⊆ Z ⁡ G DProd S ↾ D ∧ G DProd S ↾ C ∩ G DProd S ↾ D = 0 ˙ → C ∩ D = ∅
25 3 adantr ⊢ φ ∧ G dom ⁡ DProd S ↾ C ∧ G dom ⁡ DProd S ↾ D ∧ G DProd S ↾ C ⊆ Z ⁡ G DProd S ↾ D ∧ G DProd S ↾ C ∩ G DProd S ↾ D = 0 ˙ → I = C ∪ D
26 simpr1l ⊢ φ ∧ G dom ⁡ DProd S ↾ C ∧ G dom ⁡ DProd S ↾ D ∧ G DProd S ↾ C ⊆ Z ⁡ G DProd S ↾ D ∧ G DProd S ↾ C ∩ G DProd S ↾ D = 0 ˙ → G dom ⁡ DProd S ↾ C
27 simpr1r ⊢ φ ∧ G dom ⁡ DProd S ↾ C ∧ G dom ⁡ DProd S ↾ D ∧ G DProd S ↾ C ⊆ Z ⁡ G DProd S ↾ D ∧ G DProd S ↾ C ∩ G DProd S ↾ D = 0 ˙ → G dom ⁡ DProd S ↾ D
28 simpr2 ⊢ φ ∧ G dom ⁡ DProd S ↾ C ∧ G dom ⁡ DProd S ↾ D ∧ G DProd S ↾ C ⊆ Z ⁡ G DProd S ↾ D ∧ G DProd S ↾ C ∩ G DProd S ↾ D = 0 ˙ → G DProd S ↾ C ⊆ Z ⁡ G DProd S ↾ D
29 simpr3 ⊢ φ ∧ G dom ⁡ DProd S ↾ C ∧ G dom ⁡ DProd S ↾ D ∧ G DProd S ↾ C ⊆ Z ⁡ G DProd S ↾ D ∧ G DProd S ↾ C ∩ G DProd S ↾ D = 0 ˙ → G DProd S ↾ C ∩ G DProd S ↾ D = 0 ˙
30 23 24 25 4 5 26 27 28 29 dmdprdsplit2 ⊢ φ ∧ G dom ⁡ DProd S ↾ C ∧ G dom ⁡ DProd S ↾ D ∧ G DProd S ↾ C ⊆ Z ⁡ G DProd S ↾ D ∧ G DProd S ↾ C ∩ G DProd S ↾ D = 0 ˙ → G dom ⁡ DProd S
31 22 30 impbida ⊢ φ → G dom ⁡ DProd S ↔ G dom ⁡ DProd S ↾ C ∧ G dom ⁡ DProd S ↾ D ∧ G DProd S ↾ C ⊆ Z ⁡ G DProd S ↾ D ∧ G DProd S ↾ C ∩ G DProd S ↾ D = 0 ˙