Metamath Proof Explorer


Theorem dmxpss

Description: The domain of a Cartesian product is included in its first factor. (Contributed by NM, 19-Mar-2007)

Ref Expression
Assertion dmxpss ⊢ dom ⁡ A × B ⊆ A

Proof

Step Hyp Ref Expression
1 xpeq2 ⊢ B = ∅ → A × B = A × ∅
2 xp0 ⊢ A × ∅ = ∅
3 1 2 eqtrdi ⊢ B = ∅ → A × B = ∅
4 3 dmeqd ⊢ B = ∅ → dom ⁡ A × B = dom ⁡ ∅
5 dm0 ⊢ dom ⁡ ∅ = ∅
6 4 5 eqtrdi ⊢ B = ∅ → dom ⁡ A × B = ∅
7 0ss ⊢ ∅ ⊆ A
8 6 7 eqsstrdi ⊢ B = ∅ → dom ⁡ A × B ⊆ A
9 dmxp ⊢ B ≠ ∅ → dom ⁡ A × B = A
10 eqimss ⊢ dom ⁡ A × B = A → dom ⁡ A × B ⊆ A
11 9 10 syl ⊢ B ≠ ∅ → dom ⁡ A × B ⊆ A
12 8 11 pm2.61ine ⊢ dom ⁡ A × B ⊆ A