Metamath Proof Explorer


Theorem domnprodeq0

Description: A product over a domain is zero exactly when one of the factors is zero. Generalization of domneq0 for any number of factors. See also domnprodn0 . (Contributed by Thierry Arnoux, 15-Feb-2026)

Ref Expression
Hypotheses domnprodeq0.m ⊢ M = mulGrp R
domnprodeq0.b ⊢ B = Base R
domnprodeq0.1 ⊢ 0 ˙ = 0 R
domnprodeq0.r ⊢ φ → R ∈ IDomn
domnprodeq0.2 ⊢ φ → A ∈ Fin
domnprodeq0.f ⊢ φ → F : A ⟶ B
Assertion domnprodeq0 ⊢ φ → ∑ M F = 0 ˙ ↔ 0 ˙ ∈ ran ⁡ F

Proof

Step Hyp Ref Expression
1 domnprodeq0.m ⊢ M = mulGrp R
2 domnprodeq0.b ⊢ B = Base R
3 domnprodeq0.1 ⊢ 0 ˙ = 0 R
4 domnprodeq0.r ⊢ φ → R ∈ IDomn
5 domnprodeq0.2 ⊢ φ → A ∈ Fin
6 domnprodeq0.f ⊢ φ → F : A ⟶ B
7 mpteq1 ⊢ a = ∅ → k ∈ a ⟼ F ⁡ k = k ∈ ∅ ⟼ F ⁡ k
8 mpt0 ⊢ k ∈ ∅ ⟼ F ⁡ k = ∅
9 7 8 eqtrdi ⊢ a = ∅ → k ∈ a ⟼ F ⁡ k = ∅
10 9 oveq2d ⊢ a = ∅ → ∑ M k ∈ a F ⁡ k = ∑ M ∅
11 10 eqeq1d ⊢ a = ∅ → ∑ M k ∈ a F ⁡ k = 0 ˙ ↔ ∑ M ∅ = 0 ˙
12 9 rneqd ⊢ a = ∅ → ran ⁡ k ∈ a ⟼ F ⁡ k = ran ⁡ ∅
13 12 eleq2d ⊢ a = ∅ → 0 ˙ ∈ ran ⁡ k ∈ a ⟼ F ⁡ k ↔ 0 ˙ ∈ ran ⁡ ∅
14 11 13 bibi12d ⊢ a = ∅ → ∑ M k ∈ a F ⁡ k = 0 ˙ ↔ 0 ˙ ∈ ran ⁡ k ∈ a ⟼ F ⁡ k ↔ ∑ M ∅ = 0 ˙ ↔ 0 ˙ ∈ ran ⁡ ∅
15 mpteq1 ⊢ a = b → k ∈ a ⟼ F ⁡ k = k ∈ b ⟼ F ⁡ k
16 15 oveq2d ⊢ a = b → ∑ M k ∈ a F ⁡ k = ∑ M k ∈ b F ⁡ k
17 16 eqeq1d ⊢ a = b → ∑ M k ∈ a F ⁡ k = 0 ˙ ↔ ∑ M k ∈ b F ⁡ k = 0 ˙
18 15 rneqd ⊢ a = b → ran ⁡ k ∈ a ⟼ F ⁡ k = ran ⁡ k ∈ b ⟼ F ⁡ k
19 18 eleq2d ⊢ a = b → 0 ˙ ∈ ran ⁡ k ∈ a ⟼ F ⁡ k ↔ 0 ˙ ∈ ran ⁡ k ∈ b ⟼ F ⁡ k
20 17 19 bibi12d ⊢ a = b → ∑ M k ∈ a F ⁡ k = 0 ˙ ↔ 0 ˙ ∈ ran ⁡ k ∈ a ⟼ F ⁡ k ↔ ∑ M k ∈ b F ⁡ k = 0 ˙ ↔ 0 ˙ ∈ ran ⁡ k ∈ b ⟼ F ⁡ k
21 mpteq1 ⊢ a = b ∪ l → k ∈ a ⟼ F ⁡ k = k ∈ b ∪ l ⟼ F ⁡ k
22 21 oveq2d ⊢ a = b ∪ l → ∑ M k ∈ a F ⁡ k = ∑ M k ∈ b ∪ l F ⁡ k
23 22 eqeq1d ⊢ a = b ∪ l → ∑ M k ∈ a F ⁡ k = 0 ˙ ↔ ∑ M k ∈ b ∪ l F ⁡ k = 0 ˙
24 21 rneqd ⊢ a = b ∪ l → ran ⁡ k ∈ a ⟼ F ⁡ k = ran ⁡ k ∈ b ∪ l ⟼ F ⁡ k
25 24 eleq2d ⊢ a = b ∪ l → 0 ˙ ∈ ran ⁡ k ∈ a ⟼ F ⁡ k ↔ 0 ˙ ∈ ran ⁡ k ∈ b ∪ l ⟼ F ⁡ k
26 23 25 bibi12d ⊢ a = b ∪ l → ∑ M k ∈ a F ⁡ k = 0 ˙ ↔ 0 ˙ ∈ ran ⁡ k ∈ a ⟼ F ⁡ k ↔ ∑ M k ∈ b ∪ l F ⁡ k = 0 ˙ ↔ 0 ˙ ∈ ran ⁡ k ∈ b ∪ l ⟼ F ⁡ k
27 mpteq1 ⊢ a = A → k ∈ a ⟼ F ⁡ k = k ∈ A ⟼ F ⁡ k
28 27 oveq2d ⊢ a = A → ∑ M k ∈ a F ⁡ k = ∑ M k ∈ A F ⁡ k
29 28 eqeq1d ⊢ a = A → ∑ M k ∈ a F ⁡ k = 0 ˙ ↔ ∑ M k ∈ A F ⁡ k = 0 ˙
30 27 rneqd ⊢ a = A → ran ⁡ k ∈ a ⟼ F ⁡ k = ran ⁡ k ∈ A ⟼ F ⁡ k
31 30 eleq2d ⊢ a = A → 0 ˙ ∈ ran ⁡ k ∈ a ⟼ F ⁡ k ↔ 0 ˙ ∈ ran ⁡ k ∈ A ⟼ F ⁡ k
32 29 31 bibi12d ⊢ a = A → ∑ M k ∈ a F ⁡ k = 0 ˙ ↔ 0 ˙ ∈ ran ⁡ k ∈ a ⟼ F ⁡ k ↔ ∑ M k ∈ A F ⁡ k = 0 ˙ ↔ 0 ˙ ∈ ran ⁡ k ∈ A ⟼ F ⁡ k
33 eqid ⊢ 1 R = 1 R
34 1 33 ringidval ⊢ 1 R = 0 M
35 34 gsum0 ⊢ ∑ M ∅ = 1 R
36 35 a1i ⊢ φ → ∑ M ∅ = 1 R
37 4 idomdomd ⊢ φ → R ∈ Domn
38 domnnzr ⊢ R ∈ Domn → R ∈ NzRing
39 33 3 nzrnz ⊢ R ∈ NzRing → 1 R ≠ 0 ˙
40 37 38 39 3syl ⊢ φ → 1 R ≠ 0 ˙
41 36 40 eqnetrd ⊢ φ → ∑ M ∅ ≠ 0 ˙
42 41 neneqd ⊢ φ → ¬ ∑ M ∅ = 0 ˙
43 noel ⊢ ¬ 0 ˙ ∈ ∅
44 rn0 ⊢ ran ⁡ ∅ = ∅
45 44 eleq2i ⊢ 0 ˙ ∈ ran ⁡ ∅ ↔ 0 ˙ ∈ ∅
46 43 45 mtbir ⊢ ¬ 0 ˙ ∈ ran ⁡ ∅
47 46 a1i ⊢ φ → ¬ 0 ˙ ∈ ran ⁡ ∅
48 42 47 2falsed ⊢ φ → ∑ M ∅ = 0 ˙ ↔ 0 ˙ ∈ ran ⁡ ∅
49 simpr ⊢ φ ∧ b ⊆ A ∧ l ∈ A ∖ b ∧ ∑ M k ∈ b F ⁡ k = 0 ˙ ↔ 0 ˙ ∈ ran ⁡ k ∈ b ⟼ F ⁡ k → ∑ M k ∈ b F ⁡ k = 0 ˙ ↔ 0 ˙ ∈ ran ⁡ k ∈ b ⟼ F ⁡ k
50 49 orbi1d ⊢ φ ∧ b ⊆ A ∧ l ∈ A ∖ b ∧ ∑ M k ∈ b F ⁡ k = 0 ˙ ↔ 0 ˙ ∈ ran ⁡ k ∈ b ⟼ F ⁡ k → ∑ M k ∈ b F ⁡ k = 0 ˙ ∨ F ⁡ l = 0 ˙ ↔ 0 ˙ ∈ ran ⁡ k ∈ b ⟼ F ⁡ k ∨ F ⁡ l = 0 ˙
51 1 2 mgpbas ⊢ B = Base M
52 eqid ⊢ ⋅ R = ⋅ R
53 1 52 mgpplusg ⊢ ⋅ R = + M
54 4 idomcringd ⊢ φ → R ∈ CRing
55 1 crngmgp ⊢ R ∈ CRing → M ∈ CMnd
56 54 55 syl ⊢ φ → M ∈ CMnd
57 56 ad2antrr ⊢ φ ∧ b ⊆ A ∧ l ∈ A ∖ b → M ∈ CMnd
58 5 ad2antrr ⊢ φ ∧ b ⊆ A ∧ l ∈ A ∖ b → A ∈ Fin
59 simplr ⊢ φ ∧ b ⊆ A ∧ l ∈ A ∖ b → b ⊆ A
60 58 59 ssfid ⊢ φ ∧ b ⊆ A ∧ l ∈ A ∖ b → b ∈ Fin
61 6 ad3antrrr ⊢ φ ∧ b ⊆ A ∧ l ∈ A ∖ b ∧ k ∈ b → F : A ⟶ B
62 59 sselda ⊢ φ ∧ b ⊆ A ∧ l ∈ A ∖ b ∧ k ∈ b → k ∈ A
63 61 62 ffvelcdmd ⊢ φ ∧ b ⊆ A ∧ l ∈ A ∖ b ∧ k ∈ b → F ⁡ k ∈ B
64 simpr ⊢ φ ∧ b ⊆ A ∧ l ∈ A ∖ b → l ∈ A ∖ b
65 64 eldifbd ⊢ φ ∧ b ⊆ A ∧ l ∈ A ∖ b → ¬ l ∈ b
66 6 ad2antrr ⊢ φ ∧ b ⊆ A ∧ l ∈ A ∖ b → F : A ⟶ B
67 64 eldifad ⊢ φ ∧ b ⊆ A ∧ l ∈ A ∖ b → l ∈ A
68 66 67 ffvelcdmd ⊢ φ ∧ b ⊆ A ∧ l ∈ A ∖ b → F ⁡ l ∈ B
69 fveq2 ⊢ k = l → F ⁡ k = F ⁡ l
70 51 53 57 60 63 64 65 68 69 gsumunsn ⊢ φ ∧ b ⊆ A ∧ l ∈ A ∖ b → ∑ M k ∈ b ∪ l F ⁡ k = ∑ M k ∈ b F ⁡ k ⋅ R F ⁡ l
71 70 eqeq1d ⊢ φ ∧ b ⊆ A ∧ l ∈ A ∖ b → ∑ M k ∈ b ∪ l F ⁡ k = 0 ˙ ↔ ∑ M k ∈ b F ⁡ k ⋅ R F ⁡ l = 0 ˙
72 37 ad2antrr ⊢ φ ∧ b ⊆ A ∧ l ∈ A ∖ b → R ∈ Domn
73 63 ralrimiva ⊢ φ ∧ b ⊆ A ∧ l ∈ A ∖ b → ∀ k ∈ b F ⁡ k ∈ B
74 51 57 60 73 gsummptcl ⊢ φ ∧ b ⊆ A ∧ l ∈ A ∖ b → ∑ M k ∈ b F ⁡ k ∈ B
75 2 52 3 domneq0 ⊢ R ∈ Domn ∧ ∑ M k ∈ b F ⁡ k ∈ B ∧ F ⁡ l ∈ B → ∑ M k ∈ b F ⁡ k ⋅ R F ⁡ l = 0 ˙ ↔ ∑ M k ∈ b F ⁡ k = 0 ˙ ∨ F ⁡ l = 0 ˙
76 72 74 68 75 syl3anc ⊢ φ ∧ b ⊆ A ∧ l ∈ A ∖ b → ∑ M k ∈ b F ⁡ k ⋅ R F ⁡ l = 0 ˙ ↔ ∑ M k ∈ b F ⁡ k = 0 ˙ ∨ F ⁡ l = 0 ˙
77 71 76 bitrd ⊢ φ ∧ b ⊆ A ∧ l ∈ A ∖ b → ∑ M k ∈ b ∪ l F ⁡ k = 0 ˙ ↔ ∑ M k ∈ b F ⁡ k = 0 ˙ ∨ F ⁡ l = 0 ˙
78 77 adantr ⊢ φ ∧ b ⊆ A ∧ l ∈ A ∖ b ∧ ∑ M k ∈ b F ⁡ k = 0 ˙ ↔ 0 ˙ ∈ ran ⁡ k ∈ b ⟼ F ⁡ k → ∑ M k ∈ b ∪ l F ⁡ k = 0 ˙ ↔ ∑ M k ∈ b F ⁡ k = 0 ˙ ∨ F ⁡ l = 0 ˙
79 eqid ⊢ k ∈ b ∪ l ⟼ F ⁡ k = k ∈ b ∪ l ⟼ F ⁡ k
80 fvex ⊢ F ⁡ k ∈ V
81 79 80 elrnmpti ⊢ 0 ˙ ∈ ran ⁡ k ∈ b ∪ l ⟼ F ⁡ k ↔ ∃ k ∈ b ∪ l 0 ˙ = F ⁡ k
82 rexun ⊢ ∃ k ∈ b ∪ l 0 ˙ = F ⁡ k ↔ ∃ k ∈ b 0 ˙ = F ⁡ k ∨ ∃ k ∈ l 0 ˙ = F ⁡ k
83 eqid ⊢ k ∈ b ⟼ F ⁡ k = k ∈ b ⟼ F ⁡ k
84 83 80 elrnmpti ⊢ 0 ˙ ∈ ran ⁡ k ∈ b ⟼ F ⁡ k ↔ ∃ k ∈ b 0 ˙ = F ⁡ k
85 84 bicomi ⊢ ∃ k ∈ b 0 ˙ = F ⁡ k ↔ 0 ˙ ∈ ran ⁡ k ∈ b ⟼ F ⁡ k
86 vex ⊢ l ∈ V
87 69 eqeq2d ⊢ k = l → 0 ˙ = F ⁡ k ↔ 0 ˙ = F ⁡ l
88 eqcom ⊢ 0 ˙ = F ⁡ l ↔ F ⁡ l = 0 ˙
89 87 88 bitrdi ⊢ k = l → 0 ˙ = F ⁡ k ↔ F ⁡ l = 0 ˙
90 86 89 rexsn ⊢ ∃ k ∈ l 0 ˙ = F ⁡ k ↔ F ⁡ l = 0 ˙
91 85 90 orbi12i ⊢ ∃ k ∈ b 0 ˙ = F ⁡ k ∨ ∃ k ∈ l 0 ˙ = F ⁡ k ↔ 0 ˙ ∈ ran ⁡ k ∈ b ⟼ F ⁡ k ∨ F ⁡ l = 0 ˙
92 81 82 91 3bitri ⊢ 0 ˙ ∈ ran ⁡ k ∈ b ∪ l ⟼ F ⁡ k ↔ 0 ˙ ∈ ran ⁡ k ∈ b ⟼ F ⁡ k ∨ F ⁡ l = 0 ˙
93 92 a1i ⊢ φ ∧ b ⊆ A ∧ l ∈ A ∖ b ∧ ∑ M k ∈ b F ⁡ k = 0 ˙ ↔ 0 ˙ ∈ ran ⁡ k ∈ b ⟼ F ⁡ k → 0 ˙ ∈ ran ⁡ k ∈ b ∪ l ⟼ F ⁡ k ↔ 0 ˙ ∈ ran ⁡ k ∈ b ⟼ F ⁡ k ∨ F ⁡ l = 0 ˙
94 50 78 93 3bitr4d ⊢ φ ∧ b ⊆ A ∧ l ∈ A ∖ b ∧ ∑ M k ∈ b F ⁡ k = 0 ˙ ↔ 0 ˙ ∈ ran ⁡ k ∈ b ⟼ F ⁡ k → ∑ M k ∈ b ∪ l F ⁡ k = 0 ˙ ↔ 0 ˙ ∈ ran ⁡ k ∈ b ∪ l ⟼ F ⁡ k
95 94 ex ⊢ φ ∧ b ⊆ A ∧ l ∈ A ∖ b → ∑ M k ∈ b F ⁡ k = 0 ˙ ↔ 0 ˙ ∈ ran ⁡ k ∈ b ⟼ F ⁡ k → ∑ M k ∈ b ∪ l F ⁡ k = 0 ˙ ↔ 0 ˙ ∈ ran ⁡ k ∈ b ∪ l ⟼ F ⁡ k
96 95 anasss ⊢ φ ∧ b ⊆ A ∧ l ∈ A ∖ b → ∑ M k ∈ b F ⁡ k = 0 ˙ ↔ 0 ˙ ∈ ran ⁡ k ∈ b ⟼ F ⁡ k → ∑ M k ∈ b ∪ l F ⁡ k = 0 ˙ ↔ 0 ˙ ∈ ran ⁡ k ∈ b ∪ l ⟼ F ⁡ k
97 14 20 26 32 48 96 5 findcard2d ⊢ φ → ∑ M k ∈ A F ⁡ k = 0 ˙ ↔ 0 ˙ ∈ ran ⁡ k ∈ A ⟼ F ⁡ k
98 6 feqmptd ⊢ φ → F = k ∈ A ⟼ F ⁡ k
99 98 oveq2d ⊢ φ → ∑ M F = ∑ M k ∈ A F ⁡ k
100 99 eqeq1d ⊢ φ → ∑ M F = 0 ˙ ↔ ∑ M k ∈ A F ⁡ k = 0 ˙
101 98 rneqd ⊢ φ → ran ⁡ F = ran ⁡ k ∈ A ⟼ F ⁡ k
102 101 eleq2d ⊢ φ → 0 ˙ ∈ ran ⁡ F ↔ 0 ˙ ∈ ran ⁡ k ∈ A ⟼ F ⁡ k
103 97 100 102 3bitr4d ⊢ φ → ∑ M F = 0 ˙ ↔ 0 ˙ ∈ ran ⁡ F