Metamath Proof Explorer


Theorem drnginvrn0d

Description: A multiplicative inverse in a division ring is nonzero. ( recne0d analog). (Contributed by SN, 14-Aug-2024)

Ref Expression
Hypotheses drnginvrn0d.b ⊢ B = Base R
drnginvrn0d.0 ⊢ 0 ˙ = 0 R
drnginvrn0d.i ⊢ I = inv r ⁡ R
drnginvrn0d.r ⊢ φ → R ∈ DivRing
drnginvrn0d.x ⊢ φ → X ∈ B
drnginvrn0d.1 ⊢ φ → X ≠ 0 ˙
Assertion drnginvrn0d ⊢ φ → I ⁡ X ≠ 0 ˙

Proof

Step Hyp Ref Expression
1 drnginvrn0d.b ⊢ B = Base R
2 drnginvrn0d.0 ⊢ 0 ˙ = 0 R
3 drnginvrn0d.i ⊢ I = inv r ⁡ R
4 drnginvrn0d.r ⊢ φ → R ∈ DivRing
5 drnginvrn0d.x ⊢ φ → X ∈ B
6 drnginvrn0d.1 ⊢ φ → X ≠ 0 ˙
7 1 2 3 drnginvrn0 ⊢ R ∈ DivRing ∧ X ∈ B ∧ X ≠ 0 ˙ → I ⁡ X ≠ 0 ˙
8 4 5 6 7 syl3anc ⊢ φ → I ⁡ X ≠ 0 ˙