Metamath Proof Explorer


Theorem dtruALT

Description: Alternate proof of dtru which requires more axioms but is shorter and may be easier to understand. Like dtruALT2 , it uses ax-pow rather than ax-pr .

Assuming that ZF set theory is consistent, we cannot prove this theorem unless we specify that x and y be distinct. Specifically, Theorem spcev requires that x must not occur in the subexpression -. y = { (/) } in step 4 nor in the subexpression -. y = (/) in step 9. The proof verifier will require that x and y be in a distinct variable group to ensure this. You can check this by deleting the $d statement in set.mm and rerunning the verifier, which will print a detailed explanation of the distinct variable violation. (Contributed by NM, 15-Jul-1994) (Proof modification is discouraged.) (New usage is discouraged.)

Ref Expression
Assertion dtruALT ⊢ ¬ ∀ x x = y

Proof

Step Hyp Ref Expression
1 0inp0 ⊢ y = ∅ → ¬ y = ∅
2 p0ex ⊢ ∅ ∈ V
3 eqeq2 ⊢ x = ∅ → y = x ↔ y = ∅
4 3 notbid ⊢ x = ∅ → ¬ y = x ↔ ¬ y = ∅
5 2 4 spcev ⊢ ¬ y = ∅ → ∃ x ¬ y = x
6 1 5 syl ⊢ y = ∅ → ∃ x ¬ y = x
7 0ex ⊢ ∅ ∈ V
8 eqeq2 ⊢ x = ∅ → y = x ↔ y = ∅
9 8 notbid ⊢ x = ∅ → ¬ y = x ↔ ¬ y = ∅
10 7 9 spcev ⊢ ¬ y = ∅ → ∃ x ¬ y = x
11 6 10 pm2.61i ⊢ ∃ x ¬ y = x
12 exnal ⊢ ∃ x ¬ y = x ↔ ¬ ∀ x y = x
13 eqcom ⊢ y = x ↔ x = y
14 13 albii ⊢ ∀ x y = x ↔ ∀ x x = y
15 12 14 xchbinx ⊢ ∃ x ¬ y = x ↔ ¬ ∀ x x = y
16 11 15 mpbi ⊢ ¬ ∀ x x = y