Metamath Proof Explorer


Theorem dvcmul

Description: The product rule when one argument is a constant. (Contributed by Mario Carneiro, 9-Aug-2014) (Revised by Mario Carneiro, 10-Feb-2015)

Ref Expression
Hypotheses dvcmul.s ⊢ φ → S ∈ ℝ ℂ
dvcmul.f ⊢ φ → F : X ⟶ ℂ
dvcmul.a ⊢ φ → A ∈ ℂ
dvcmul.x ⊢ φ → X ⊆ S
dvcmul.c ⊢ φ → C ∈ dom ⁡ F S ′
Assertion dvcmul ⊢ φ → S × A × f F S ′ ⁡ C = A ⁢ F S ′ ⁡ C

Proof

Step Hyp Ref Expression
1 dvcmul.s ⊢ φ → S ∈ ℝ ℂ
2 dvcmul.f ⊢ φ → F : X ⟶ ℂ
3 dvcmul.a ⊢ φ → A ∈ ℂ
4 dvcmul.x ⊢ φ → X ⊆ S
5 dvcmul.c ⊢ φ → C ∈ dom ⁡ F S ′
6 fconst6g ⊢ A ∈ ℂ → S × A : S ⟶ ℂ
7 3 6 syl ⊢ φ → S × A : S ⟶ ℂ
8 ssidd ⊢ φ → S ⊆ S
9 recnprss ⊢ S ∈ ℝ ℂ → S ⊆ ℂ
10 1 9 syl ⊢ φ → S ⊆ ℂ
11 10 2 4 dvbss ⊢ φ → dom ⁡ F S ′ ⊆ X
12 11 5 sseldd ⊢ φ → C ∈ X
13 4 12 sseldd ⊢ φ → C ∈ S
14 fconst6g ⊢ A ∈ ℂ → ℂ × A : ℂ ⟶ ℂ
15 3 14 syl ⊢ φ → ℂ × A : ℂ ⟶ ℂ
16 ssidd ⊢ φ → ℂ ⊆ ℂ
17 dvconst ⊢ A ∈ ℂ → ℂ D ℂ × A = ℂ × 0
18 3 17 syl ⊢ φ → ℂ D ℂ × A = ℂ × 0
19 18 dmeqd ⊢ φ → dom ⁡ ℂ × A ℂ ′ = dom ⁡ ℂ × 0
20 c0ex ⊢ 0 ∈ V
21 20 fconst ⊢ ℂ × 0 : ℂ ⟶ 0
22 21 fdmi ⊢ dom ⁡ ℂ × 0 = ℂ
23 19 22 eqtrdi ⊢ φ → dom ⁡ ℂ × A ℂ ′ = ℂ
24 10 23 sseqtrrd ⊢ φ → S ⊆ dom ⁡ ℂ × A ℂ ′
25 dvres3 ⊢ S ∈ ℝ ℂ ∧ ℂ × A : ℂ ⟶ ℂ ∧ ℂ ⊆ ℂ ∧ S ⊆ dom ⁡ ℂ × A ℂ ′ → S D ℂ × A ↾ S = ℂ × A ℂ ′ ↾ S
26 1 15 16 24 25 syl22anc ⊢ φ → S D ℂ × A ↾ S = ℂ × A ℂ ′ ↾ S
27 xpssres ⊢ S ⊆ ℂ → ℂ × A ↾ S = S × A
28 10 27 syl ⊢ φ → ℂ × A ↾ S = S × A
29 28 oveq2d ⊢ φ → S D ℂ × A ↾ S = S D S × A
30 18 reseq1d ⊢ φ → ℂ × A ℂ ′ ↾ S = ℂ × 0 ↾ S
31 xpssres ⊢ S ⊆ ℂ → ℂ × 0 ↾ S = S × 0
32 10 31 syl ⊢ φ → ℂ × 0 ↾ S = S × 0
33 30 32 eqtrd ⊢ φ → ℂ × A ℂ ′ ↾ S = S × 0
34 26 29 33 3eqtr3d ⊢ φ → S D S × A = S × 0
35 20 fconst2 ⊢ S × A S ′ : S ⟶ 0 ↔ S D S × A = S × 0
36 34 35 sylibr ⊢ φ → S × A S ′ : S ⟶ 0
37 36 fdmd ⊢ φ → dom ⁡ S × A S ′ = S
38 13 37 eleqtrrd ⊢ φ → C ∈ dom ⁡ S × A S ′
39 7 8 2 4 1 38 5 dvmul ⊢ φ → S × A × f F S ′ ⁡ C = S × A S ′ ⁡ C ⁢ F ⁡ C + F S ′ ⁡ C ⁢ S × A ⁡ C
40 34 fveq1d ⊢ φ → S × A S ′ ⁡ C = S × 0 ⁡ C
41 20 fvconst2 ⊢ C ∈ S → S × 0 ⁡ C = 0
42 13 41 syl ⊢ φ → S × 0 ⁡ C = 0
43 40 42 eqtrd ⊢ φ → S × A S ′ ⁡ C = 0
44 43 oveq1d ⊢ φ → S × A S ′ ⁡ C ⁢ F ⁡ C = 0 ⋅ F ⁡ C
45 2 12 ffvelcdmd ⊢ φ → F ⁡ C ∈ ℂ
46 45 mul02d ⊢ φ → 0 ⋅ F ⁡ C = 0
47 44 46 eqtrd ⊢ φ → S × A S ′ ⁡ C ⁢ F ⁡ C = 0
48 fvconst2g ⊢ A ∈ ℂ ∧ C ∈ S → S × A ⁡ C = A
49 3 13 48 syl2anc ⊢ φ → S × A ⁡ C = A
50 49 oveq2d ⊢ φ → F S ′ ⁡ C ⁢ S × A ⁡ C = F S ′ ⁡ C ⁢ A
51 dvfg ⊢ S ∈ ℝ ℂ → F S ′ : dom ⁡ F S ′ ⟶ ℂ
52 1 51 syl ⊢ φ → F S ′ : dom ⁡ F S ′ ⟶ ℂ
53 52 5 ffvelcdmd ⊢ φ → F S ′ ⁡ C ∈ ℂ
54 53 3 mulcomd ⊢ φ → F S ′ ⁡ C ⁢ A = A ⁢ F S ′ ⁡ C
55 50 54 eqtrd ⊢ φ → F S ′ ⁡ C ⁢ S × A ⁡ C = A ⁢ F S ′ ⁡ C
56 47 55 oveq12d ⊢ φ → S × A S ′ ⁡ C ⁢ F ⁡ C + F S ′ ⁡ C ⁢ S × A ⁡ C = 0 + A ⁢ F S ′ ⁡ C
57 3 53 mulcld ⊢ φ → A ⁢ F S ′ ⁡ C ∈ ℂ
58 57 addlidd ⊢ φ → 0 + A ⁢ F S ′ ⁡ C = A ⁢ F S ′ ⁡ C
59 39 56 58 3eqtrd ⊢ φ → S × A × f F S ′ ⁡ C = A ⁢ F S ′ ⁡ C