Metamath Proof Explorer


Theorem dvcnp

Description: The difference quotient is continuous at B when the original function is differentiable at B . (Contributed by Mario Carneiro, 8-Aug-2014) (Revised by Mario Carneiro, 28-Dec-2016)

Ref Expression
Hypotheses dvcnp.j ⊢ J = K ↾ 𝑡 A
dvcnp.k ⊢ K = TopOpen ⁡ ℂ fld
dvcnp.g ⊢ G = z ∈ A ⟼ if z = B F S ′ ⁡ B F ⁡ z − F ⁡ B z − B
Assertion dvcnp ⊢ S ∈ ℝ ℂ ∧ F : A ⟶ ℂ ∧ A ⊆ S ∧ B ∈ dom ⁡ F S ′ → G ∈ J CnP K ⁡ B

Proof

Step Hyp Ref Expression
1 dvcnp.j ⊢ J = K ↾ 𝑡 A
2 dvcnp.k ⊢ K = TopOpen ⁡ ℂ fld
3 dvcnp.g ⊢ G = z ∈ A ⟼ if z = B F S ′ ⁡ B F ⁡ z − F ⁡ B z − B
4 dvfg ⊢ S ∈ ℝ ℂ → F S ′ : dom ⁡ F S ′ ⟶ ℂ
5 4 3ad2ant1 ⊢ S ∈ ℝ ℂ ∧ F : A ⟶ ℂ ∧ A ⊆ S → F S ′ : dom ⁡ F S ′ ⟶ ℂ
6 ffun ⊢ F S ′ : dom ⁡ F S ′ ⟶ ℂ → Fun ⁡ F S ′
7 funfvbrb ⊢ Fun ⁡ F S ′ → B ∈ dom ⁡ F S ′ ↔ B F S ′ F S ′ ⁡ B
8 5 6 7 3syl ⊢ S ∈ ℝ ℂ ∧ F : A ⟶ ℂ ∧ A ⊆ S → B ∈ dom ⁡ F S ′ ↔ B F S ′ F S ′ ⁡ B
9 eqid ⊢ K ↾ 𝑡 S = K ↾ 𝑡 S
10 eqid ⊢ z ∈ A ∖ B ⟼ F ⁡ z − F ⁡ B z − B = z ∈ A ∖ B ⟼ F ⁡ z − F ⁡ B z − B
11 recnprss ⊢ S ∈ ℝ ℂ → S ⊆ ℂ
12 11 3ad2ant1 ⊢ S ∈ ℝ ℂ ∧ F : A ⟶ ℂ ∧ A ⊆ S → S ⊆ ℂ
13 simp2 ⊢ S ∈ ℝ ℂ ∧ F : A ⟶ ℂ ∧ A ⊆ S → F : A ⟶ ℂ
14 simp3 ⊢ S ∈ ℝ ℂ ∧ F : A ⟶ ℂ ∧ A ⊆ S → A ⊆ S
15 9 2 10 12 13 14 eldv ⊢ S ∈ ℝ ℂ ∧ F : A ⟶ ℂ ∧ A ⊆ S → B F S ′ F S ′ ⁡ B ↔ B ∈ int ⁡ K ↾ 𝑡 S ⁡ A ∧ F S ′ ⁡ B ∈ z ∈ A ∖ B ⟼ F ⁡ z − F ⁡ B z − B lim ℂ B
16 8 15 bitrd ⊢ S ∈ ℝ ℂ ∧ F : A ⟶ ℂ ∧ A ⊆ S → B ∈ dom ⁡ F S ′ ↔ B ∈ int ⁡ K ↾ 𝑡 S ⁡ A ∧ F S ′ ⁡ B ∈ z ∈ A ∖ B ⟼ F ⁡ z − F ⁡ B z − B lim ℂ B
17 16 simplbda ⊢ S ∈ ℝ ℂ ∧ F : A ⟶ ℂ ∧ A ⊆ S ∧ B ∈ dom ⁡ F S ′ → F S ′ ⁡ B ∈ z ∈ A ∖ B ⟼ F ⁡ z − F ⁡ B z − B lim ℂ B
18 14 12 sstrd ⊢ S ∈ ℝ ℂ ∧ F : A ⟶ ℂ ∧ A ⊆ S → A ⊆ ℂ
19 18 adantr ⊢ S ∈ ℝ ℂ ∧ F : A ⟶ ℂ ∧ A ⊆ S ∧ B ∈ dom ⁡ F S ′ → A ⊆ ℂ
20 12 13 14 dvbss ⊢ S ∈ ℝ ℂ ∧ F : A ⟶ ℂ ∧ A ⊆ S → dom ⁡ F S ′ ⊆ A
21 20 sselda ⊢ S ∈ ℝ ℂ ∧ F : A ⟶ ℂ ∧ A ⊆ S ∧ B ∈ dom ⁡ F S ′ → B ∈ A
22 eldifsn ⊢ z ∈ A ∖ B ↔ z ∈ A ∧ z ≠ B
23 13 adantr ⊢ S ∈ ℝ ℂ ∧ F : A ⟶ ℂ ∧ A ⊆ S ∧ B ∈ dom ⁡ F S ′ → F : A ⟶ ℂ
24 23 19 21 dvlem ⊢ S ∈ ℝ ℂ ∧ F : A ⟶ ℂ ∧ A ⊆ S ∧ B ∈ dom ⁡ F S ′ ∧ z ∈ A ∖ B → F ⁡ z − F ⁡ B z − B ∈ ℂ
25 22 24 sylan2br ⊢ S ∈ ℝ ℂ ∧ F : A ⟶ ℂ ∧ A ⊆ S ∧ B ∈ dom ⁡ F S ′ ∧ z ∈ A ∧ z ≠ B → F ⁡ z − F ⁡ B z − B ∈ ℂ
26 19 21 25 1 2 limcmpt2 ⊢ S ∈ ℝ ℂ ∧ F : A ⟶ ℂ ∧ A ⊆ S ∧ B ∈ dom ⁡ F S ′ → F S ′ ⁡ B ∈ z ∈ A ∖ B ⟼ F ⁡ z − F ⁡ B z − B lim ℂ B ↔ z ∈ A ⟼ if z = B F S ′ ⁡ B F ⁡ z − F ⁡ B z − B ∈ J CnP K ⁡ B
27 17 26 mpbid ⊢ S ∈ ℝ ℂ ∧ F : A ⟶ ℂ ∧ A ⊆ S ∧ B ∈ dom ⁡ F S ′ → z ∈ A ⟼ if z = B F S ′ ⁡ B F ⁡ z − F ⁡ B z − B ∈ J CnP K ⁡ B
28 3 27 eqeltrid ⊢ S ∈ ℝ ℂ ∧ F : A ⟶ ℂ ∧ A ⊆ S ∧ B ∈ dom ⁡ F S ′ → G ∈ J CnP K ⁡ B