Metamath Proof Explorer


Theorem dvcxp2

Description: The derivative of a complex power with respect to the second argument. (Contributed by Mario Carneiro, 24-Feb-2015)

Ref Expression
Assertion dvcxp2 ⊢ A ∈ ℝ + → dx ∈ ℂ A x d ℂ x = x ∈ ℂ ⟼ log ⁡ A ⁢ A x

Proof

Step Hyp Ref Expression
1 cnelprrecn ⊢ ℂ ∈ ℝ ℂ
2 1 a1i ⊢ A ∈ ℝ + → ℂ ∈ ℝ ℂ
3 simpr ⊢ A ∈ ℝ + ∧ x ∈ ℂ → x ∈ ℂ
4 relogcl ⊢ A ∈ ℝ + → log ⁡ A ∈ ℝ
5 4 adantr ⊢ A ∈ ℝ + ∧ x ∈ ℂ → log ⁡ A ∈ ℝ
6 5 recnd ⊢ A ∈ ℝ + ∧ x ∈ ℂ → log ⁡ A ∈ ℂ
7 3 6 mulcld ⊢ A ∈ ℝ + ∧ x ∈ ℂ → x ⁢ log ⁡ A ∈ ℂ
8 efcl ⊢ y ∈ ℂ → e y ∈ ℂ
9 8 adantl ⊢ A ∈ ℝ + ∧ y ∈ ℂ → e y ∈ ℂ
10 3 6 mulcomd ⊢ A ∈ ℝ + ∧ x ∈ ℂ → x ⁢ log ⁡ A = log ⁡ A ⁢ x
11 10 mpteq2dva ⊢ A ∈ ℝ + → x ∈ ℂ ⟼ x ⁢ log ⁡ A = x ∈ ℂ ⟼ log ⁡ A ⁢ x
12 11 oveq2d ⊢ A ∈ ℝ + → dx ∈ ℂ x ⁢ log ⁡ A d ℂ x = dx ∈ ℂ log ⁡ A ⁢ x d ℂ x
13 1cnd ⊢ A ∈ ℝ + ∧ x ∈ ℂ → 1 ∈ ℂ
14 2 dvmptid ⊢ A ∈ ℝ + → dx ∈ ℂ x d ℂ x = x ∈ ℂ ⟼ 1
15 4 recnd ⊢ A ∈ ℝ + → log ⁡ A ∈ ℂ
16 2 3 13 14 15 dvmptcmul ⊢ A ∈ ℝ + → dx ∈ ℂ log ⁡ A ⁢ x d ℂ x = x ∈ ℂ ⟼ log ⁡ A ⋅ 1
17 6 mulridd ⊢ A ∈ ℝ + ∧ x ∈ ℂ → log ⁡ A ⋅ 1 = log ⁡ A
18 17 mpteq2dva ⊢ A ∈ ℝ + → x ∈ ℂ ⟼ log ⁡ A ⋅ 1 = x ∈ ℂ ⟼ log ⁡ A
19 12 16 18 3eqtrd ⊢ A ∈ ℝ + → dx ∈ ℂ x ⁢ log ⁡ A d ℂ x = x ∈ ℂ ⟼ log ⁡ A
20 dvef ⊢ ℂ D exp = exp
21 eff ⊢ exp : ℂ ⟶ ℂ
22 21 a1i ⊢ A ∈ ℝ + → exp : ℂ ⟶ ℂ
23 22 feqmptd ⊢ A ∈ ℝ + → exp = y ∈ ℂ ⟼ e y
24 23 eqcomd ⊢ A ∈ ℝ + → y ∈ ℂ ⟼ e y = exp
25 24 oveq2d ⊢ A ∈ ℝ + → dy ∈ ℂ e y d ℂ y = ℂ D exp
26 20 25 24 3eqtr4a ⊢ A ∈ ℝ + → dy ∈ ℂ e y d ℂ y = y ∈ ℂ ⟼ e y
27 fveq2 ⊢ y = x ⁢ log ⁡ A → e y = e x ⁢ log ⁡ A
28 2 2 7 5 9 9 19 26 27 27 dvmptco ⊢ A ∈ ℝ + → dx ∈ ℂ e x ⁢ log ⁡ A d ℂ x = x ∈ ℂ ⟼ e x ⁢ log ⁡ A ⁢ log ⁡ A
29 rpcn ⊢ A ∈ ℝ + → A ∈ ℂ
30 29 adantr ⊢ A ∈ ℝ + ∧ x ∈ ℂ → A ∈ ℂ
31 rpne0 ⊢ A ∈ ℝ + → A ≠ 0
32 31 adantr ⊢ A ∈ ℝ + ∧ x ∈ ℂ → A ≠ 0
33 30 32 3 cxpefd ⊢ A ∈ ℝ + ∧ x ∈ ℂ → A x = e x ⁢ log ⁡ A
34 33 mpteq2dva ⊢ A ∈ ℝ + → x ∈ ℂ ⟼ A x = x ∈ ℂ ⟼ e x ⁢ log ⁡ A
35 34 oveq2d ⊢ A ∈ ℝ + → dx ∈ ℂ A x d ℂ x = dx ∈ ℂ e x ⁢ log ⁡ A d ℂ x
36 30 3 cxpcld ⊢ A ∈ ℝ + ∧ x ∈ ℂ → A x ∈ ℂ
37 6 36 mulcomd ⊢ A ∈ ℝ + ∧ x ∈ ℂ → log ⁡ A ⁢ A x = A x ⁢ log ⁡ A
38 33 oveq1d ⊢ A ∈ ℝ + ∧ x ∈ ℂ → A x ⁢ log ⁡ A = e x ⁢ log ⁡ A ⁢ log ⁡ A
39 37 38 eqtrd ⊢ A ∈ ℝ + ∧ x ∈ ℂ → log ⁡ A ⁢ A x = e x ⁢ log ⁡ A ⁢ log ⁡ A
40 39 mpteq2dva ⊢ A ∈ ℝ + → x ∈ ℂ ⟼ log ⁡ A ⁢ A x = x ∈ ℂ ⟼ e x ⁢ log ⁡ A ⁢ log ⁡ A
41 28 35 40 3eqtr4d ⊢ A ∈ ℝ + → dx ∈ ℂ A x d ℂ x = x ∈ ℂ ⟼ log ⁡ A ⁢ A x