Metamath Proof Explorer


Theorem dvhopN

Description: Decompose a DVecH vector expressed as an ordered pair into the sum of two components, the first from the translation group vector base of DVecA and the other from the one-dimensional vector subspace E . Part of Lemma M of Crawley p. 121, line 18. We represent their e, sigma, f by ` <. (I |`` B ) , ( I |`T ) >. , U , <. F , O >. . We swapped the order of vector sum (their juxtaposition i.e. composition) to show <. F , O >. first. Note that O and ` (I |`T ) are the zero and one of the division ring E , and ` ( I |`B ) is the zero of the translation group. S is the scalar product. (Contributed by NM, 21-Nov-2013) (New usage is discouraged.)

Ref Expression
Hypotheses dvhop.b ⊢ B = Base K
dvhop.h ⊢ H = LHyp ⁡ K
dvhop.t ⊢ T = LTrn ⁡ K ⁡ W
dvhop.e ⊢ E = TEndo ⁡ K ⁡ W
dvhop.p ⊢ P = a ∈ E , b ∈ E ⟼ c ∈ T ⟼ a ⁡ c ∘ b ⁡ c
dvhop.a ⊢ A = f ∈ T × E , g ∈ T × E ⟼ 1 st ⁡ f ∘ 1 st ⁡ g 2 nd ⁡ f P 2 nd ⁡ g
dvhop.s ⊢ S = s ∈ E , f ∈ T × E ⟼ s ⁡ 1 st ⁡ f s ∘ 2 nd ⁡ f
dvhop.o ⊢ O = c ∈ T ⟼ I ↾ B
Assertion dvhopN ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ U ∈ E → F U = F O A U S I ↾ B I ↾ T

Proof

Step Hyp Ref Expression
1 dvhop.b ⊢ B = Base K
2 dvhop.h ⊢ H = LHyp ⁡ K
3 dvhop.t ⊢ T = LTrn ⁡ K ⁡ W
4 dvhop.e ⊢ E = TEndo ⁡ K ⁡ W
5 dvhop.p ⊢ P = a ∈ E , b ∈ E ⟼ c ∈ T ⟼ a ⁡ c ∘ b ⁡ c
6 dvhop.a ⊢ A = f ∈ T × E , g ∈ T × E ⟼ 1 st ⁡ f ∘ 1 st ⁡ g 2 nd ⁡ f P 2 nd ⁡ g
7 dvhop.s ⊢ S = s ∈ E , f ∈ T × E ⟼ s ⁡ 1 st ⁡ f s ∘ 2 nd ⁡ f
8 dvhop.o ⊢ O = c ∈ T ⟼ I ↾ B
9 simprr ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ U ∈ E → U ∈ E
10 1 2 3 idltrn ⊢ K ∈ HL ∧ W ∈ H → I ↾ B ∈ T
11 10 adantr ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ U ∈ E → I ↾ B ∈ T
12 2 3 4 tendoidcl ⊢ K ∈ HL ∧ W ∈ H → I ↾ T ∈ E
13 12 adantr ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ U ∈ E → I ↾ T ∈ E
14 7 dvhopspN ⊢ U ∈ E ∧ I ↾ B ∈ T ∧ I ↾ T ∈ E → U S I ↾ B I ↾ T = U ⁡ I ↾ B U ∘ I ↾ T
15 9 11 13 14 syl12anc ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ U ∈ E → U S I ↾ B I ↾ T = U ⁡ I ↾ B U ∘ I ↾ T
16 1 2 4 tendoid ⊢ K ∈ HL ∧ W ∈ H ∧ U ∈ E → U ⁡ I ↾ B = I ↾ B
17 16 adantrl ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ U ∈ E → U ⁡ I ↾ B = I ↾ B
18 2 3 4 tendo1mulr ⊢ K ∈ HL ∧ W ∈ H ∧ U ∈ E → U ∘ I ↾ T = U
19 18 adantrl ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ U ∈ E → U ∘ I ↾ T = U
20 17 19 opeq12d ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ U ∈ E → U ⁡ I ↾ B U ∘ I ↾ T = I ↾ B U
21 15 20 eqtrd ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ U ∈ E → U S I ↾ B I ↾ T = I ↾ B U
22 21 oveq2d ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ U ∈ E → F O A U S I ↾ B I ↾ T = F O A I ↾ B U
23 simprl ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ U ∈ E → F ∈ T
24 1 2 3 4 8 tendo0cl ⊢ K ∈ HL ∧ W ∈ H → O ∈ E
25 24 adantr ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ U ∈ E → O ∈ E
26 6 dvhopaddN ⊢ F ∈ T ∧ O ∈ E ∧ I ↾ B ∈ T ∧ U ∈ E → F O A I ↾ B U = F ∘ I ↾ B O P U
27 23 25 11 9 26 syl22anc ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ U ∈ E → F O A I ↾ B U = F ∘ I ↾ B O P U
28 1 2 3 ltrn1o ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T → F : B ⟶ 1-1 onto B
29 28 adantrr ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ U ∈ E → F : B ⟶ 1-1 onto B
30 f1of ⊢ F : B ⟶ 1-1 onto B → F : B ⟶ B
31 fcoi1 ⊢ F : B ⟶ B → F ∘ I ↾ B = F
32 29 30 31 3syl ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ U ∈ E → F ∘ I ↾ B = F
33 1 2 3 4 8 5 tendo0pl ⊢ K ∈ HL ∧ W ∈ H ∧ U ∈ E → O P U = U
34 33 adantrl ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ U ∈ E → O P U = U
35 32 34 opeq12d ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ U ∈ E → F ∘ I ↾ B O P U = F U
36 22 27 35 3eqtrrd ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ U ∈ E → F U = F O A U S I ↾ B I ↾ T